The process of solving a system of equations! x2 y2 6x 4 0

The analytic expression of two circles, their intersection is the solution.

1＋4λ)x＋6y＝0…①；6x＋(2＋λ)y＝0…②；4x∧2＋y∧2＝25…③；Derived from the formula, y [ 1 4 ) 6]x [ 6 (2 )x; 1 4 ) 6 6 (2) Simplification ( 2) (4 17) 0;λ1＝2；λ2＝－17／4；Substituting 1 2 into the formula, 9x 6y 0, y 3x 2...., substituting the formula into , 4x 2 (9 4) x 2 25, simplifying, x 2 4, x1 2, x2 2, substituting x1 2 into the formula, getting y1 3, substituting x2 2 into the formula, getting y2 3;Substituting 2 17 4 into the formula, we get, 16x 6y 0, y 8x 3...., substituting the formula into , 4x 2 (64 9) x 2 25, simplifying, x 2 9 4, x3 3 2, x4 3 2, substituting x3 3 2 into the formula, getting y3 4, substituting x4 3 2 into the formula, getting y4 4. It's not easy to type on your phone, hope, if you have any questions, please ask.

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x-y=0......(1)

5x-7y-2=0......Silver (2).

Solution: Use the method of addition and subtraction to prepare for the elimination of the element.

1) 7 A (2) gets:

2x+2=0

x = a 1 from (1) gets:

y=x=a1

So the solution of the original equation is ruined: =y=a1.

x-y=4 4x+2y=-1 is substituted by x=4+y, and 4(4+y)+2y=-1 is solved to get y= -17 6 x=4+(-17 imitation 6)=7 6

x+y=5 (1)

2x-y=4 (2)

1) +(2) to get:

3x=5+4

x=9 3x=3 is substituted into the original equation (1) to obtain:

y=5-3=2

Commutation method, 2x y 4 = 0

y= 2x－4

Bring in x +y 2x 4y=0 to get x +(2x 4)( 2x 4) 2x 4(2x 4)=0

Find 5x -26x+32=0

x1= x2=2

y1= y2=0

+ is x+y=6

That's x-y=20

Will it be done after that!?

x=(3y+4)/2

y=(2x-4)/3

x-3y=t 2x+y=t

then x-3y=2x+y

radius in mm. 2850 square millimeters = square centimeters.

A: The total area is in square centimeters.

Is the bracket misplaced?

From 4x 2-y 2=0 can be decomposed into (2x+y)(2x-y)=0, find y=-2x, y=2x, and substitute them into x 2-xy+4=0 respectively in 3x 2+4=0, of course, this formula has no solution; If y=2x, then there is -x 2+4=0, find x=+2 or -2

4x -y = (2x+y)*(2x-y)=0 to get 2x=-y or 2x=y; Substituting 2x=-y into x -xy+4=0 gives 3x =-4, which is not true; Substituting 2x=y into x -xy+4=0 gives x =4 to get x=2 or -2, so x=2, y=4 or x=-2, y=-4

By 4x 2-y 2 = 0 y = 2x

From x 2-xy+4=0, we know y≠-2x

Then, x 2-2x 2+4=0, x=2 or -2 are solved as x=2, y=4

or x=-2 y=-4

3x+4y=5 1 formula.

7x+9y=-5 2 2 formula.

Multiply 1 by 7 to get: 21x+28y=35 3x2 multiply by 3 to get: -21x+27y=-15 2 4 3+4 get: 55y=55 2

y=1 2, substitute y=1 2 into 3x+4y=5

x=1so.

x=1y=1/2

This is the score, 2 at the bottom and 5 at the top.

1+2; -4x+13y=0, get x=(13 4)y and bring in 1 to solve it.