An Olympiad problem! Math Masters Advance!

Updated on educate 2024-05-26
11 answers
  1. Anonymous users2024-02-11

    You can first set x to the perimeter of the garden, then the father can walk x 72 footprints when he walks alone, and the son can walk out x 54 footprints when he walks alone, and the number of overlapping footprints is y, then x 72 + x 54-y = 60, the number of overlapping footprints is y, and the least common multiple of the footsteps is 216, then it is easy to know x 216 = yBecause the value of y is equivalent to another person walking in a circle alone and taking y steps. y=10, x=2160

    That is, the circumference of the flower bed is 2160 cm.

  2. Anonymous users2024-02-10

    First of all, you must know that there are several footprints that coincide with Xiao Ming and his father.

    54 72=3 4 So every 4 steps coincide with his father's footprints every 3 steps.

    When Xiao Ming walked to the fourth step, it coincided with his father's footprints in the third step, and there should have been 7 footprints, but because they coincided, only 6 footprints were left, so the cycle was 6.

    60 6=10 So there are 10 footprints that coincide with Xiao Ming and his father, which means that Xiao Ming walked 10*4=40 steps, and his father walked 10*3=30 steps.

    So the length of the flower bed should be 40*54=30*72=2160 cm.

  3. Anonymous users2024-02-09

    This question is a sample problem in Chapter 2 of the China Women and Children's Publishing House, Primary School Mathematics Improvement Class.

    The common multiple of 54 and 72 is 216For every 216cm, Xiao Ming has 4 footprints [216 54=4 (pieces)], and Dad has 3 footprints [216 72=3 (pieces)], which should be considered for the circular closed head and tail, so there is only one overlapping footprint in 216cm. Therefore, [3+4-1=6 (pieces)] 216cm has 6 footprints, and among the 60 footprints, there are [60 6=10 (group)], 10 groups of 216cm, so the circumference of the flower bed is [216 10=2160 (cm)=

    Done, the correct answer is rice.

  4. Anonymous users2024-02-08

    When the footprints of two people coincide for the first time after departure, the distance from the starting point should be the least common multiple of the step length of two people, and the least common multiple is 3 * 8 * 9 = 216, that is, the number of steps of two people per 216cm should be subtracted by 1, and the circumference of the flower bed is x, then x 54 + x 72-x 216 = 60, and x = 2160cm is obtained

  5. Anonymous users2024-02-07

    If the common multiple is 216, then the distance traveled by Xiao Ming is 216*(60-1)=12744cm (that is, the circumference of the flower bed).

  6. Anonymous users2024-02-06

    It seems to be on the "Talent Class Question".,I did it in the sixth grade.。。。

  7. Anonymous users2024-02-05

    The common multiple of 54 and 72 is 216, in 216, the father leaves 2 footprints, the son leaves 3 footprints, plus the overlapping one, so there are 6 footprints, then the length is 216 * 60 6 = 2160 cm = meters.

  8. Anonymous users2024-02-04

    For ease of calculation, it is advisable to use 1 16 metres as a unit of length.

    Then the fox jumps 2 and 3/4 meters = 44 length units, the weasel jumps 4 and 1/8 meters = 66 length units, and the runway is 1,500 meters = 24,000 length units.

    Dig a trap every 6 and 3/16 meters = 99 length units.

    The least common multiple of 44 and 99 is 396, and the fox encounters a trap for every 396 length units of jump, so it takes 9+10=19 seconds for each 396 length units of jump. 24000÷396=60……240, the fox jumps in time: 19 60 + 240 44 = 1145 and 11/5 seconds.

    The least common multiple of 66 and 99 is 198, and the weasel encounters a trap per 198 length units per jump, so it takes 3 + 10 = 13 seconds per 198 length units per jump. It takes 13 (396 198) = 26 seconds per 396 length units per jump.

    So the fox arrived before the weasel.

    When the fox arrived, the weasel traveled the following distance: 1145 13 = 88 ......1, 198 88+66 1 and 5/11 = 17,520 units of length, and 24,000-17,520 = 6,480 units of length from the end point.

    6480 1 16 = 405 meters.

  9. Anonymous users2024-02-03

    Assuming the total is x, then.

    x4/7+(x-x4/7)*(3/5)+42=x

    x=245 is a hole shot, and Master Zhang wants to make 245 parts of the fluttering ball.

  10. Anonymous users2024-02-02

    B propylene 20 minutes line (800 + 700) 20 = 30,000 meters.

    The meeting time of A and C is 30000 (1000-800) = 150 minutes.

    From the east to the west, there is a total of (1000 + 700) 150 = 255000 meters = 255 thousand trembling manuscript meters.

  11. Anonymous users2024-02-01

    How do I feel that this is a ...... of swiping points

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