The application problems of three unary one dimensional equations should be fast and add points

1. Solution: If the task assigned by No. 3 blast furnace is x tons, then:

The second blast furnace was assigned 2x tasks

The task assigned to the No. 3 blast furnace is 5 3 * 2x = 10 3 * xx + 2x + 10 3x = 19000

19/3x=19ooo

x = 3000 (tons).

2x=6000 (tons).

10 3x = 10000 (tons).

Answer: The tasks assigned to No. 1, No. 2 and No. 3 blast furnaces are: 10,000 tons, 6,000 tons and 3,000 tons respectively.

2. Solution: Let A originally plan to process x, then: B originally planned to process 5 4x by the title: (1 + 15%) x + (1 + 12%) * 5 4x = 163223 20x + 28 20x = 1632

x=640 (pcs).

5 4x=800 (pcs).

Answer: A and B originally planned to process them.

3. Solution: If x people are drawn from team A, 113-x people will be drawn from team B.

Because: 190-x=2*(133-(113-x))190-x=40+2x

x=50 (person).

113-50 = 63 (people).

A: 50 people should be drawn from team A and 63 people should be drawn from team B.

Solution: The task of setting the No. 3 blast furnace is 3x tons, and by proportion, the No. 2 blast furnace is 6x tons, and the No. 1 blast furnace is 10x tons, so.

3x+6x+10x=19000

x=1000

So the task of the No. 3 blast furnace is 3,000 tons, the No. 2 blast furnace is 6,000 tons, and the No. 1 blast furnace is 10,000 tons.

Solution: If A originally planned to process 4x, then B originally planned to process 5x.

So. 4x(1+15%)+5x(1+12%)=1632, so x=160

Therefore, A originally planned to process 640 pieces, and B originally planned to process 800 pieces.

Solution: If the remaining number of team B is x, then the remaining number of team A is 2x.

190-2x+133-x=113

So x=70

So 190-140 = 50 people from team A, 133-70 = 63 people from team B.

Solution: 1. Set the No. 1 boiler as x tons

x 3x 5 + (3x 5) * (1 2) = 19000x = 10000 (tons).

No. 2 is: 10000 * 3 5 = 6000 (tons) No. 3 is: 6000 * 1 2 = 3000 (tons).

2. If A originally planned x pcs, then B originally planned 5x 4, according to the title:

x*(1+x=640 (pcs))

B is 640*5 4=800 (pcs).

3. Set up x people to be drawn from team A, according to the theme.

190 x + (190-x) 2 = 190 + 133-113x = 50 (person).

Team B draws 133 50 83 (people).

1) Solution: If the No. 2 blast furnace is set to X tons, the No. 1 blast furnace is 5 3X, and the No. 3 blast furnace is 1 2x tons.

5/3x+x+1/2x=19000

x=6000 ..

2) Solution: A x pieces B 5 4x pieces.

1+15%)x+(1+12%)x=16323), set A to draw x people, then B to draw (113-x) people.

1 2 (190-x) = 133-(113-x) The specific answer should be easy to forget, I have something to do, so I didn't write it all

1.There are a total of 834 people in the two villages, and the number of people in village A is 111 less than half of the number in village B.

2.A car and an electric car set off from two places 298 kilometers apart at the same time, and the speed of the car was 15 kilometers more than six times the speed of the electric car, and they met half an hour later. Find the speed of two cars.

3.Someone shared 142 yuan to buy two kinds of fruits for a total of 20 kilograms, it is known that fruit A is 8 yuan per kilogram, and fruit B is 6 yuan per kilogram, and asks how many kilograms of these two fruits are there?

4.Enclose a rectangle with a rope of 80m long, so that its width is 1 3 long, what should be the length and width?

5.A boat sails between the two piers, taking 10 hours against the water and 6 hours downstream. The vessel is known to travel 12 kilometers per hour in still water, and the speed of the current and the distance between the two piers are determined.

6.A project, A alone 20 days to complete, B alone 10 days to complete, now B alone for a few days, the rest of the part by A alone, has been completed in 12 days, ask B how many days?

Answer: Set up X people in Village B.

1／2x－111＋x＝834

3／2x＝945

x 630630 2 111 204 (person).

A: There are 204 people in Village A and 630 people in Village B.

Set the speed of the electric car x km/h.

x 8383 6 15 513 kmh

A: The speed of the electric car is 83 km/h, and the speed of the car is 513 km/h.

Set a kind of fruit x kilograms.

8x＋6（20－x）＝142

8x＋120－6x＝142

2x Macro Feast 22

x 1120 11 9 (kg).

A: 11 kg of fruit A and 9 kg of fruit B.

Set up a length of x meters. 2（x＋1／3x）＝80

8／3x＝80

x 3030 3 10 (m).

A: It is 30 meters long and 10 meters wide.

Let the water speed be x km/h.

10（12－x）＝6（12＋x）

120－10x＝72＋6x

16x＝－48

x 310 (12 3) 90 (km).

Answer: When the water speed is 3 km, the distance is 90 km.

Set B did it for x days.

1／10x＋1／20（12－x）＝1

2x＋12－x＝20

x 8 A: B did it for 8 days.

1 All 14x+m(x-6)=2(2-3m)

4+m)x=4

x=4/(4+m)

In order for x to be a positive integer, 4+m can only be 1,2,4, so m can only be -3,-2,0, corresponding to x is 4,2,1

2. Set up in t minutes to find, 0 to t minutes, the item and the boat travel in opposite directions, the boat speed against the water is equal to the speed of the boat and the speed of the water, and the speed of the item is equal to the speed of the water, so the distance between them is just the boat driving in the still water for t minutes, and then the boat turns around, the pursuit problem, the speed difference is just the speed of the ship in the still water, and the distance difference is the first t minute, so the time should be the same, it is also 5 minutes.

3. There is the following concentration situation:

A 2 3 4

B 7 6 5

The corresponding weight is.

Outside the parentheses is the actual weight, the first number in parentheses is the postal charge weight, and the second number is the charge).

A 33(40, 47(60, 61(80,B 103(200,6) 89(100,4) 75(80, so the latter two are yuan, you can choose.

1.There are 10 coins of 1 jiao, 5 jiao and 1 yuan. Fifteen pieces were taken out of it, worth a total of 7 yuan. How many coins are 1 jiao, 5 jiao, and 1 yuan?

2.The whole journey from A to B is kilometers, one section uphill, one section flat road, and one section downhill. If you keep going uphill, you can travel 3 kilometers per hour, 4 kilometers per hour on flat roads, and 5 kilometers per hour on downhill slopes.

Then it takes 51 minutes to get from A to B, and it takes 51 minutes to travel from B to A. What is the distance from A to B: uphill, flat and downhill?

3.A district is holding a junior high school basketball league, and the points rules are: 3 points for a win, 1 point for a draw, and 0 points for a loss.

By the end of the 9th round (1 game per team per round), we have a total of 18 points. Could you please tell me how many wins, draws, and losses each school will have by calculating them?

4.Shishi No. 1 Machinery Factory in the first quarter of the production of A, B and C three types of machines a total of 450 units, after the improvement of technology, plans to produce a total of 490 sets of these three types of machines in the second quarter, of which the output of a machine will increase by 10% compared with the first quarter, the output of B machine will increase by 8% compared with the first quarter C machine production 9, the factory in the first quarter of the production of A, B and C three kinds of machines each?

5.The school's basketball is 3 times less than volleyball, the ratio of the number of soccer balls to the number of volleyballs is 2:3, and there are 41 of the three types of balls, so how many balls are there in each of the three balls?

The ternary system of equations is not difficult, okay.

In the first question, groups A, B and C are set up to plant trees x, y, and z respectively to obtain the system of equations x+y+z=50 1

x+z)/4=y 2y+z=x 3

Subtract Eq. 3 from Eq. 1 to get x=50-x, and deform Eq. 2 with x=25 to get Eq. 4: x+z=4y

Subtract Equation 4 from Equation 1 to get Y=50-4Y, get Y=10 and substitute x=25y=10 into any equation to get Z=15

In the second question, the number of people in the first and second and third years of junior high school is set as x, y, and z, and the system of equations x+y+z=651 1

1+10%)z=y2(1+5%)y=x3, and equation 2 is multiplied by equation 4:

Subtract Equation 3 from Equation 4 to get Equation 5:

Add Equation 1 to Equation 5 to get Equation 6:

Add Equation 6 to Equation 2 to get Z=200 and substitute Z=200 into Equation 2 to get Y=220

Substituting y=220 into equation 3 gives x=231

Set up: X trees were planted in group A, y trees were planted in group B, and z trees were planted in group C.

1）x+y+z=50

2) 4y=x+z

3) x=y+z

1)+(3) gets: x+y+z+x=50+y+z 2x=50 x=25

Substituting (3) into (1) gets: y+z+y+z=50 2y+2z=50 y+z=25....4)

2), (4) synthesis, solution: y=10 z=15