There was a third grade math problem that stumped me. What is ABCAB A DDDDDD,ABCD?

Simple! a=3

b=7c=0d=1

Solution: If a=1,2 then it can't be true, because it's too small, so the answer can only be 3,4,5,6,7,8,9! And if it's 4, it's at least 160,000 and the maximum 199996 Exclude!

If it is 5, then the minimum 250000 and the maximum 299995, exclude! If it's 6, the minimum is 360000, the maximum is 419994, exclude! If it is 7, the minimum is 490000, and the maximum is 559993, here is 555555 this possible number, divide 555555 by 7 = 79365, not true, exclude!

If it is 8, the minimum is 640000, and the maximum is 719992, here is the possible number of 666666, the same 666666 divided by 8=, excluded! If it is 9, the minimum is 810000, and the maximum is 899991, at this time, there is another 888888, the same 888888 divided by 9=

So if a=3, the minimum is 90000, and the maximum 1199997 has 111111 111111 in the middle, divided by 3, it is 37037*3=111111

Whew, it's finally good, in fact, it can be seen at a glance In order to make the answer authoritative, Rory is a lot of trivia

In an isosceles triangle, a is the apex angle abc= cba ab=ba

A=A+AD shows A=0 or D=0

If a=0, then b=-40, c=40 3, d=-40 21 If d=0, there is no solution.

So a=0, then b=-40, c=40 3, d=-40 21 New question add:

c=2b+6

d=b+3+2b+6+7=40+b

b = 12 and then bring in the original form respectively, get.

a=15,b=12,c=30,d=52

...4 yuan once (sweat has a second)...a=a+ad gives that when ad=0 a=o, b=-40 c=40 3 d=-40 21 d=0 is not true.

So a=o b=-40 c=40 3 d=-40 21

Let a be xb and y

c is the method of placing a ternary equation for the z image.

Three equations are obtained.

They are (1) x+y=160

x+z=180

3)y+z=230

Equations (1) and (3) are then solved using binary equations.

Solution x=55

Substituting x=55 into equation (1) obtains.

y=160-55=105

Put y=105 again

Substitution (3).

z=125∴a=55

b=105c=125

By the way, is this a third-grade puzzle?

First, find a: because a*4<=c<10 (otherwise there are four digits to the right of the equal sign), then a = 1 or 2;

Because the single digit of the orange as a result of Sun nuclear excitation c*4 must be a double number, a is a double number;

In summary, a=2.

Then find c: because the result of c*4 is a and a=2, then c = 3 or 8 (3*4=12 or 8*4=32);

Because a*4<=c and a*4=8, c>=8;

In summary, c=8.

Finally, find b and d:

Now the question becomes: 2b8 * 4 = 8d2.

b * 4 < 10 (otherwise the hundred to the right of the equal sign will be greater than 8), so b = 1 or 2.

If b = 1,218 * 4 = 872, then d = 7;

If b = 2,228 * 4 = 912, the 100 digits are not 8 and do not meet the requirements.

So, a, b, c, d are 2, 1, 8, 7, respectively.

A is not equal to 0 and three digits * 4 = three digits, so Hui Honghu a< = 2c * 4 single digits are a, so a is an even number.

Therefore, a = 2, c = 8

This results in 2b8*4=8d2

The result of b*4 cannot be carried by absolute combustion, so it can only be a single digit, and you can multiply the result into three, so b can only be 1

Therefore d=7 gives a=2, b=1, c=8, d=7

a=2,b=1,c=8,d=7(218*4=872)

Problem solving process: abc*4=cda, because c is a number, it is impossible to exceed 10, so a*4 is less than 10, that is, a is 1 or 2; Substituting 1 can know that 1 is not good, so a=2, that is, 2bc*4=CD2, so Qi's Tan c is 3 or 8, and substituting can know that c=3 is not true, so c=8;According to 2b8*4=8d2, 4b+3=d, because d "nuclear slag 10, so b=1, substitution can know that Gaotong d=7."

abcd

abc+ ab

d+c+b=10 or 20 So a=1, b=8, when c+b+a can only be 17 or 18, and the previous digit is not true.

c+b+a=7 or 8 17 or 18 can only be a=1, b=7, c=9, d=4

b+a = 9 or 8

A must be 1

A is equal to 1, b is equal to 8, c is equal to 1, and d is equal to 1

The most important thing is to find a=1 first, and then gradually calculate b, c, d

Does ab mean a times b or a two-digit number?

Since the multiplier is 4, a must be an even number, and a is in the first place *4, so a can not be greater than 2 (if it is greater than 2, the multiplication is 5 digits, not 4 digits) so a = 2 so d > = a * 4 = 8, so d is 8 or 9, because d * 4 mantissa is 2, so d 8 In addition, because d 8, so b * 4 will not have a carry, so b < = 2, so b may be 0, 1, 2 at this time respectively substituted b 0, 1, 2, find c, see if you can meet the final can get b = 1, c = 7 so 2178 * 4 = 8712