Four basketballs and a soccer ball are 415 yuan, and four soccer balls are 385 yuan each.

Let basketball be x and football be y:

Let the equation be: 4x+y=415

4y+x=385 ②

Eq*4- Eq.

You can get a unary equation that is easy to find the answer.

Four basketballs and one soccer ball are 415 yuan, then sixteen basketballs and four soccer balls ** are: 415 * 4 = 1660 yuan.

So sixteen basketballs, four soccer balls, 1,660 yuan, minus the known four soccer balls, one basketball 385 yuan, and you get 1,275 yuan, which is the price of 15 basketballs. So 1275 divided by 15 gives basketball $85.

It is also known that four soccer balls and one basketball are 385 yuan, so 385-85=300 is the price of four soccer balls, so 300 divided by 4 gives 75 yuan per soccer ball.

It's actually the principle of the equation.

Set: Football = x, Basketball = y

According to the conditions.

4y+x=415 ①

4x+y=385 ②

Derived from x=415-4y

Bringing in 4(415-4y)+y=385 gives y=75 and brings in or , yielding x=85

So it's 85 for basketball and 75 for football

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Set up x yuan for football and y yuan for basketball.

4*y+x=415

4*x+y=385

The first equation is multiplied by 4:16y+4x=1660

Subtract the second equation to get: 15y=1275

The solution is x=75 and y=85

Haha, it's an assignment question, right?

$75 for a soccer ball.

$45 for a basketball.

A total of 435 yuan was spent.

First of all, 75 + 45 = 120 yuan.

120*3=360 yuan.

435-360 = 75 yuan.

Therefore, it is just right to buy 4 football and 3 basketball, 435 yuan.

Because a soccer ball is 30 yuan more, the money to buy 3 soccer balls is less, and you can buy 2 more basketballs, plus 3 more to buy 5 more. That is, 1 for football and 8 for basketball.

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A football is 75 yuan, a basketball is 45 yuan, and a total of 435 yuan was spent, 45 * 3 + 75 * 4 = 435 yuan, so there are 4 footballs and 3 basketballs.

A soccer ball 75, a basketball 45, a total of 435 yuan, how many basketball and soccer each? I think it's 75 yuan football, a 45 yuan basketball, there are a total of eight, and you can spend a total of 435 yuan.

If you buy 1 football, you can buy a basketball.

435-75) 45=8 (pcs).

If you buy 2 footballs, you can buy basketballs.

435-75 2) 45=pcs) is not eligible.

If you buy 3 footballs, you can buy basketballs.

435-75 3) 45=pcs) is not eligible.

If you buy 4 footballs, you can buy basketballs.

435-75 4) 45=3 (pcs).

If you buy 5 soccer balls, you can buy basketballs.

435-75 5) 45=pcs), not eligible.

Buy 1 soccer ball, buy 8 basketballs, buy 4 soccer balls, buy 3 basketballs.

75 + 45 = 120, 435 divided by 120 to take the integer 3 (group), 435-120x3 = 75 yuan, the final answer is 4 football, 3 basketball.

435-75 = 360, 360 45 = 8, or 435-75 4 = 135, 135 45 = 3, so maybe buy 1 soccer ball and 8 basketballs, or buy 4 soccer balls, 3 basketballs.

A soccer ball is 75 yuan, a basketball is 45 yuan, a total of 435 yuan was spent, how many basketballs and soccer balls are there? There are three for basketball and four for football.

This soccer is 75 yuan and the other basketball is only 45 yuan, and I think they can only spend 480 yuan at most when they get down together, and this cost should be correct when added together.

A soccer ball is 75 yuan, a basketball is 45 yuan, a total of 435 yuan was spent, ask, how much is basketball and football? I think basketball is about three footballs, 15.

4 for football and 3 for basketball.

Solution: There are x basketballs and y footballs.

Summary. This student is happy to answer your questions! The solution to this problem is to let the basketball be x-yuan and the football is y-yuan, and according to the meaning of the problem, the equations 4x+5 y=390 and 5x+4 y=410 can be obtained, and then the two equations can be solved to get the number.

4 basketballs and 5 soccer balls are 390 yuan, and 5 basketballs and 4 soccer balls are 410 yuan. Ask how much a soccer ball and a basketball are respectively.

This student is glad that Zelianqiao can answer your questions! The solution to this problem is to set the basketball is x-yuan, the football is y-yuan, according to the meaning of the problem can get the equation 4x+5 y=390, 5x+4 y=410, and then solve these two equations to hide the number.

x=,y=, that is, basketball is 54 pieces of five, and football is 34 pieces of four.

Ok thanks.

Summary. Suppose that basketball is x and football is y, then 4x+2y=184, 3x+4y=223

Solve x=29

So y=34

4 basketballs and 2 soccer balls are 184 yuan, 3 basketballs and 4 soccer balls are 223 yuan, how much is a basketball and how much is a soccer ball.

Let the basketball be x and the football be y, then 4x+2y=184, 3x+4y=223 solve x=29, so y=34

So basketball is 29 yuan, and football is 34 yuan.

Dear, I hope mine is helpful to you

Dear, I hope mine is helpful to you, give it a thumbs up if it's useful, thank you.

Summary. Because 3 soccer + 1 basketball 343 5 soccer + 1 basketball 473, so 2 soccer 473-343 = 130 soccer 130 2 = 65 yuan.

Three soccer balls and a basketball bought 343 yuan, five soccer balls and one basketball bought 473 yuan, how many yuan a basketball is a foot.

Hello, three soccer balls and a basketball bought 343 yuan, five soccer balls, a basketball bought 473 yuan, how many yuan a basketball, the specific calculation process is as follows:

Because 3 soccer + 1 basketball 343 5 soccer + 1 basketball 473, so 2 soccer 473-343 = 130 soccer 130 2 = 65 yuan.

So basketball 343-3 65 = 148 yuan.

Let each x-yuan basketball and each y-yuan football column binary system of equations 3x+4y=458 4x+3y=368 The first equation is multiplied by 3 on both sides at the same time to become 9x+12y=1374 is the third formula, the second equation is multiplied by 4 on both sides at the same time to become 16x+12y=1472 is the fourth formula, and then the fourth equation is subtracted by the third formula to get 7x=98 x=14 Substituting the first formula to get y=104 so that a basketball is 98 yuan, a football is 104 yuan, and a basketball plus a football is 98+104=202 yuan Got it?

Set 1 basketball x dollar and 1 football y dollar.

then 3x+4y=458

4x+3y=368 ②

So a basketball plus a soccer ball is 202 yuan.

118 yuan, solution, set basketball x yuan, football y yuan.

3x+4y=458 4x+3y=368 gives 7x+7y=826

x+y=118

3x+4y=458

4x+3y=368

Add the two formulas. 7x+7y=826

x+y=826/7=118

So your answer is: 118

458 + 368 = 7 basketballs and 7 soccer balls and then divide this result by 7 to get the price of a basketball and a soccer ball.

I guess this is a primary school question, don't talk to other students, what kind of binary equations, if people have learned equations, this question will still ask you??

The second algorithm (the basic algorithm suitable for correcting the number of basketball balls) 458-368=90 yuan 90 yuan is actually a football more expensive than a basketball** (458 is 3 basketballs + 3 footballs + 1 football**; 368 is 3 basketballs + 3 footballs + 1 basketball**) Right!! Now that you've figured it out, there's nothing left to talk about!!

Looking at the title, it can be determined that the blue ball is more expensive than the football. Set the blue ball to x, the soccer ball to x-y=22. [388-(3*22)] 7 = 46 yuan = football price, 46 + 22 = 68 yuan = basketball price.

This is a question of what grade is interesting?

3x+4y=388 4x+3y=410

3x=388-4y

x=(388-4y)/3

4×(388-4y)/3+3y=410

1552-16y)/3+9y/3=410

1552-16y+9y)/3=410

1552-16y+9y=1230

7y=-322

y=463x+4×46=388

3x=388-184

3x=204

x=68 so the ** of the basketball one is 68 yuan, and the ** of the football one is 46 yuan.

Let the unit price of basketball be x and the unit price of football be y.

3x+4y=388

4x+3y=410

Solution: x=68, y=46

SO, 1 basketball 68 yuan, 1 football 46 yuan.

Solution: Let the unit price of basketball be x and the unit price of football be y

Then you can get from the question: 3x+4y 388 yuan

4x+3y 410 yuan

Obtained by 4 -3.

7y 322 yuan.

The solution is 46 yuan

Bring in x 68 RMB.

A: Basketball is 68 yuan and football is 46 yuan.

Hello. We'll be happy to answer for you.

The unit price of basketball is 68 yuan, and the unit price of football is 46 yuan.