Please specify that you can get 2 to the power of 100 and 2 to the power of 97 ?

Proof: (1) $1 stackrel2 stackrel4 stackrel8 stackrel10 stackrel20 stackrel22$

It can also be considered the other way around:

22$ stackrel20 stackrel10 stackrel8 stackrel4 stackrel2 stackrel1$, or 1$ stackrel2 stackrel4 stackrel8 stackrel11 stackrel22$).

2) Proof: 1$ stackrel3 2-4 stackrel3 2-2 stackrel3 -4$$ stackrel3 -2 stackrel3 -4 stackrel3 -2....$

Multiply by 2 constantly, plus 2)$stackrel3 -4 stackrel3 -1 stackrel + 3$$stackrel + 1 stackrel + 2$;

2 of 100 times of the quiet elimination of the side - 2 of the hole brother 99 power.

2 x to the 99th power (2-1).

2 of the tremor knows the 99th power.

2 to the 99th power.

Reason: (-2) to the power of 100 = 2 to the power of 100 = 2 * 2 to the power of 99.

2) to the 99th power = -2 to the 99th power.

So (-2) to the power of 100 + (-2) to the power of 99 = 2 * 2 to the power of 99 + (-2 to the power of 99) = 2 to the power of 99.

Negative odd power Jing Zai is still negative For example, the 3rd power of -3 = -27, the negative even power is positive, the 4th power of -3 = 81, the sent modulus is (-2 of the 99th power) is negative = -2 of the 99th power) (2 of the 100th power) is positive = 2 of the 100th power (-2 of the 99th power) + (2 of the 100th power) is equivalent to the 100th power of =2 - (2 of the 99th power.

2 + 2 to the 2nd power + 2 to the 3rd power....The 99th power of the hole noise elimination +2 + 2 to the 100th power is a proportional series.

The first term is 2, the common ratio is 2, and the number of terms is 100

2 + 2 to the 2nd power + 2 to the 3rd power....+2 to the power of 99 + 2 to the power of 100 (1-2 100) Nazhi (1-2) matching.

Note: 2 100 means 2 to the 100th power.