The electric furnace wire is hot and red, but why is the copper wire connected to the electric furna

The wire and the resistance wire are connected in series, so the current is equal, according to Q=ixixrxt, in the case of equal current and energizing time, the greater the resistance, the more heat is generated, because the resistance of the resistance wire is greater than the wire, the heat is much more than the wire, so: the electric furnace wire is hot and red, but the copper wire connected with the resistance wire is not very hot.

Answer: Because the copper wire and the electric furnace wire are connected in series, according to Q=I2RT, the current passing through is equal, but the resistance of the copper wire is much smaller than that of the electric furnace wire, so the electric furnace wire is hot and red, while the copper wire is not very hot.

The series current is equal everywhere, and the resistance of the wire is much smaller than that of the electric furnace wire, according to Q=i Rt, it can be seen that the heat of the wire is much smaller than that of the electric furnace wire in the same time.

Because the thermal conductivity temperature of copper wires is very small.

Because the resistance of the copper wire is less than that of the electric furnace wire.

Because the electric furnace was designed with this situation in mind, they added special materials, and the heat conductivity was not good.

Because the heat conductivity of copper wires is not good.

Because there are other substances between the links of the electric furnace wire.

The copper wire connected to the electric furnace wire will generally have other substances in the middle.

Because they've designed it for this situation, with some special materials.

They have thought about the situation and have already set it in advance. Overheated copper wires will break.

When the electric furnace is in use, the electric furnace wire and the wire are connected in series, and the electric furnace wire = i wire,

Because copper has less resistance, it doesn't heat as much.

Answer: When the electric furnace is in use, the electric furnace wire and the wire are connected in series, and the current passing through them is equal, and the energizing time t is the same, because q=i2

RT, R electric furnace wire.

r wire. So the heat generated by the electric current: such as orange socks Q electric stove Wu penny.

Q wire. As a result, the electric furnace wire is hot and red, but the wire connected to the electroslag excitation wire is not very hot

The electric furnace wire is connected to the circuit through the wire, and the electric furnace wire and the wire pass through the same time and the resistance of the wire is very small, and the resistance of the electric furnace wire.

It is very large, so that when the current passing through it is equal, the electric furnace wire is hot and red, while the wire is barely hot

From Joule's law, we know that the heat generated by the current through the conductor is proportional to the square of the current, the size of the conductor resistance and the energizing time The electric furnace wire and the connected wire are connected in series in the circuit (the passing current is equal), the energizing time is the same, and the resistance of the electric furnace wire is greater than the resistance of the wire, according to the analysis of Joule's law

Answer C electric furnace wire and copper wire in series, through it the current size and power-on time are equal, because the resistance of the electric furnace wire is large, so the heat generated, so the electric furnace wire is hot after power-on, but the copper wire is not very hot

From the above, it can be seen that options a, b, and d are all incorrect

Therefore, C

According to the principle of electrical engineering, the heating rate of a wire with the same cross-section is directly proportional to the resistivity of the wire. Copper and aluminum are selected for the core of the wire because the resistivity of copper and aluminum is small. Electric furnaces use high-resistance alloys precisely to turn electrical energy into heat.

However, the electric furnace wire itself is the core part of the electrical appliance, so it improves the resistance, converts the electrical energy into heat energy, and realizes the purpose of heating.

The resistance of the electric furnace wire is larger than that of the wire.

Answer: The wire and the electric furnace wire together form a series circuit, in the series circuit, when working, the current is equal everywhere. In the production of electric furnace wire is the selection of resistivity is relatively large alloy materials, and the wire is the selection of very good conductivity of materials, plus the diameter of the electric furnace wire is very thin, and the diameter of the wire is thicker, so the resistance value of the electric furnace wire is much larger than the wire, then in the case of a certain total voltage, the voltage drop on the electric furnace wire is much greater than the voltage drop on the wire, according to the formula p=iu, so the power consumed on the electric furnace wire is much greater than the power on the wire.

As a result, there is almost no feeling of heat.

When the electric furnace is in use, the electric furnace wire and the wire are connected in series, 0 electric furnace wire = 0 wire, the energizing time t is the same, p = 0nrt, r electric furnace wire r wire, the heat generated by the current:

P electric furnace wire P wire, so the electric furnace wire is hot and red, but the wire is almost not heated;

A: Because the resistance of the electric furnace wire is large, it generates a lot of heat

1.The resistance value of the furnace wire on the material is larger, and the resistance value of the wire is smaller;

2.In the process, the diameter of the furnace wire is very small, the length is very long, the diameter of the wire is very large, and the length is very short;

3.The shape of the furnace wire coil in a spiral shape can produce the so-called "electromagnetic circulation" effect, and the wire is straight linear.

The above three points make the heat of the furnace wire hundreds of times that of the wire.

Because the electric furnace wire has a large resistance, the heat production is high, while the wire resistance value is very small.

The resistance wire in the circuit and the current in the wire are equal.

But the power does not want to wait.

Power p=i 2*r

Because the resistance of the resistance wire is very large and the resistance of the wire is small.

Therefore, the furnace wire is hot and red, but the wire temperature is not high.

Those are two materials, the resistivity is different, the thickness is different, and the resistance size is very different.

When the electric furnace is in use, the electric furnace wire and the wire are connected in series, I electric furnace wire = I wire, the energizing time t is the same, because Q = I2RT, R electric furnace wire R wire, so, the heat generated by the current:

Q electric furnace wire Q wire, so that the electric furnace wire is hot and red, and the wire connected to the electric furnace wire is not very hot Therefore, the answer is: resistance; Heat generated

Because the wire and the consumer are connected in series, according to the formula: Q=i 2 (square) r, the resistance of the wire is very small.