There are 60 basketballs and volleyballs in total, 4 more basketballs than volleyballs, and how many

Set up x basketballs and y volleyballs.

then we get a system of binary linear equations:

x+y=60 --Equation 1

x-y=4 -- Equation 2

Equation 1,2 add x+y+x-y=60+4 2x=64 x=32 substitute x=32 into equation 2, then 32-y=4 y=28, so 32 for basketball and 28 for volleyball.

Set: There are x basketballs, then there are x-4 volleyballs.

Solution: x+(x-4)=60

x+x-4=60

2x=64x=32

x-4=32-4=28

A: There are 32 in basketball and 28 in volleyball.

There is no need to set up unknowns for this kind of topic:

Remove the extra 4 first, for a total of 56 balls, divide by 2, 28 each.

28 plus the 4 removed is the number of basketballs, 32.

Or the other way around, fewer steps:

Isn't it simple? You don't need to know the unknown, right?

32 pcs! If there are x basketballs, then there are (x-4) volleyballs.

i.e. x+(x-4)=60, x=32.

There are 32 in basketball.

There are 28 volleyballs.

Basketball is 18.

Analysis: Suppose basketball is x and volleyball is y, and basketball is twice as large as volleyball, i.e. x=2*y. And there are a total of 27 basketball X and volleyball Y. So x+y=27

Because the above x=2*y, bring in the above x+y=27, which is 2y+y=27

3y=37y=9

That is, 9 volleyballs.

Basketball is twice as large as volleyball, so basketball is 2*9=18.

Basketball 18, volleyball 9Basketball is 2:1 than volleyball, so 27 divided by 3 equals 9 is the number of volleyballs, and 9*2 equals 18 is the number of basketballs. Thank you! ~

Number of basketballs - 12 = number of volleyballs raised.

54-12) 2=21.

21 + 12 = 33 nuclear halls.

Answer: 21 in volleyball and 33 in basketball.

There is a row of bush balls = (and - poor oaks) 2

21 (pieces) basket as wide as a cherry ball = (sum + difference) 2

33 (pcs).

Assuming there are x volleyballs, then there are x + 12 in pure silver basketball.

Volleyball + Basketball = 54

x + x + 12 = 54

2x = 42

x = 21

There are 21 volleyball banquets and 33 basketball banquets.

38 (pieces) 80-38 = 42 (pieces and holes) call for letters and dry.

A: There are 42 in basketball and 38 in volleyball

There are 240 basketball and volleyball, and basketball has 90 more than volleyball, which is four times that of volleyball. Therefore, there are x volleyballs and x+90 basketballs. From the meaning, the following equation is obtained: x + x + 90) = 240

2x + 90 = 240

2x = 150

x = 75 So, there are 75 in volleyball and 165 in basketball. Volleyball has 90 fewer than basketball, and basketball is more than volleyball (i.e. 165 75.

Set up basketball cautiously answer a wide wisdom spike, volleyball 2a a.

a+2a=54

3a=54a=18

2a=36A: 18 for basketball and 36 for volleyball.

Summary. We can assume that there are x in basketball, then there are x+12 in volleyball and x-6 in football. You can list the following equation: x+12+x-6+x 42 i.e. 3x+6 42 i.e. 3x 36 x 12

So it can be concluded that there are 12 basketballs, 24 volleyballs, and 6 footballs, for a total of 42 balls, and there are 12 more balls in volleyball than basketball, and 6 more in basketball than in football.

You can list the following equation: x+12+x-6+x 42 i.e. 3x+6 42 i.e. 3x 36 x 12 So you can get that there are 12 basketballs, 24 silver volleyballs, and 6 soccer balls, and I hope mine can help you.

Summary. So 12 in basketball, 24 in volleyball, and 6 in football.

There are 42 balls in total, 12 more in volleyball than basketball, and 6 more in basketball than in football.

Please wait a moment.

Let's see if there are any conditions that need to be added.

This problem can only be solved using equations according to the conditions you give.

Set up x basketballs, Y volleyballs, and soccer imitation Z, and the column formula is: Sen Liang Fiber x Y Z 42Y x 12x Z 6 solution: Y key He 24x 12z 6

So 12 in basketball, 24 in volleyball, and 6 in football.