Do 10 kW motors and 380V motors consume the same amount of electricity per hour?

It is not necessarily the same, but the difference is not too big, of course, this is in the pure motor, not considering the installation of inverters and other drives.

case. Because although the power of the motor is the same, the power factor of the motor.

The efficiency is not necessarily exactly the same, so the hourly power consumption is not necessarily exactly the same, but the power factor and efficiency of the current motor are generally the same, so the hourly power consumption will not be too different.

First, the rated power of the motor.

The rated power of the motor refers to the rated operation of the motor (rated voltage.

rated frequency, rated load) condition, the mechanical power output on the rotating shaft. That is to say, the rated power does not refer to a value in the actual operation process, its meaning is actually to describe the functional force of the motor.

The rated power of 10 kilowatts does not refer to the no-load power, let alone the maximum output power.

It means that under normal circumstances, the motor can be loaded with a load of 10 kilowatts, if the load is less than 10 kilowatts, then the actual output of the motor is less than 10 kilowatts, if the load is too small, it is equivalent to a "big horse-drawn car" is not economical.

If the actual load is greater than 10 kilowatts, the actual output of the motor will correspondingly exceed 10 kilowatts, but at this time, the temperature rise of the motor will rise sharply, and even burn the motor, which is called overload. That's where the power rating comes in.

In the case of rated voltage and rated frequency, the maximum output power of the motor is 10 kilowatts, which is the maximum load capacity of the motor, that is, the power at full load.

Motor. Second, the formula for calculating the rated power of the motor.

Rated power = sqrt (3) * rated voltage * rated current.

Power Factor * Efficiency.

The rated power of the motor refers to the output power, the rated voltage * rated current is the input power of the motor, the input power cannot be equal to the output power, and there is a loss in the middle. That's why it's multiplied by efficiency.

The output power refers to the active power, so the input power is multiplied by the power factor to be the active power, and then multiplied by the efficiency is the output power (rated power).

It is the rated voltage multiplied by the rated current (or operating current, the actual output power) multiplied by the power factor multiplied by the motor efficiency. If it is three-phase electricity.

The voltage parameter is multiplied by 380V, which is then multiplied by the rated current, power factor, and efficiency.

The efficiency of small motors is lower, such as 0, 7, and the switching efficiency of large motors is higher, such as taking.

It should be the same, the same power consumption, but its input voltage is different.

Dear, hello, I'm glad to answer for you, 15kw three-phase motor 380V metering of electricity consumption per hour? Answer: 15 kWh = 15 degrees.

Because the current work w is equal to the electrical power p multiplied by time t, that is, w = pt = 15 kW 1 hour = 15 kWh = 15 degrees. Kilowatt-hour and joules are both units of electrical work, and the relationship between them is, 1 degree = 1 kWh = joule (1kWh =. In lighting circuits, electrical work is measured by an energy meter.

The process of doing work with electric current is the process of converting electrical energy into other forms of energy.

Hello: 1, power consumption = active power running time (1kwh is one kilowatt-hour of electricity).

2. The 110kW of the three-phase motor is the active power, and the power consumption in one hour is 110kW 1H = 110kWh = 110kWh.

There is no big problem upstairs, but the normal load of the motor is generally not full, and the general design is about 80%, and the specific amount of electricity also needs to be measured by adding current transformers and watt-hour meters.

100÷50×30×1=60kwh

A: 30hz alternating current.

It is used for 50Hz motor, and the motor is running in the torque state of Labiheng, and the power consumption per hour is 60kWh.

The motor realizes the conversion or transmission of electric energy according to the law of electromagnetic induction, the motor is represented by the letter M in the circuit (the old standard is D), its main role is to generate driving torque, as the power source of electrical appliances or various machinery, the generator is represented by the letter G in the circuit, and its main role is to use mechanical energy to convert into electrical energy.

If it runs at full load for one hour, it consumes 4 kWh. Generally, you can't reach it, it should be in the fourth degree.

The specific calculation process is as follows:

Assuming that the motor works at constant power for one hour, let p = 4kw, t = 1h, w = pt = 4kwh = 4 degrees. kWh, the commonly used unit of household electricity in China, that is, kilowatt-hours, with the symbol kWh, is defined as the electricity consumption of a device with a power of 1000 watts per hour is 1 kWh.

According to the current electricity bill**, an hour is about forty or fifty yuan.

The calculation process is as follows:

Assuming that the motor works at constant power for one hour, let p = 4kw, t = 1h, w = pt = 4kwh = 4 degrees.

degree, the commonly used unit of household electricity in China, that is, kilowatt hours, the symbol is kWh. It is defined as the power consumption of a device with a power of 1000 watts per hour as 1 kWh.

Summary. According to electricity billing regulations, electricity charges are calculated in kilowatt-hours (kWh), that is, 1 kilowatt-hour of electricity consumed per hour is 1 kilowatt-hour. Therefore, the electricity cost of a 380V1000KW motor for one hour is 1000 kWh.

On this basis, it should be noted that the actual power consumption of the motor is also affected by a variety of factors, such as the size of the load, the length of operation, the efficiency of the motor, and so on. Therefore, in actual use, it is necessary to carry out actual calculations according to the specific situation to determine its true electricity consumption. In addition, it should be noted that the operating efficiency of the motor can be improved by certain technical means, such as the use of high-efficiency motor controllers, the use of high-quality motor materials, and so on.

These measures can effectively reduce the power consumption of the motor, which in turn reduces the energy consumption cost of the enterprise. In short, the electricity cost of a 380V1000kW motor is 1000 kWh per hour, but the actual power consumption needs to be calculated according to the specific situation, and can be optimized by improving the efficiency of the motor.

According to electricity billing regulations, electricity charges are calculated in kilowatt-hours (kWh), that is, 1 kilowatt-hour of electricity consumed per hour is 1 kilowatt-hour. Therefore, the electricity cost of a 380V1000KW motor for one hour is 1000 kWh. On this basis, it should be noted that the actual power consumption of the motor is also affected by a variety of factors, such as the size of the load, the length of operation time, the efficiency of the motor, and so on.

Therefore, in actual use, it is necessary to carry out actual calculations according to the specific situation to determine its true electricity consumption. In addition, it should be noted that the operating efficiency of the motor can be improved by certain technical means, such as the use of high-efficiency motor controllers, the use of high-quality motor materials, and so on. These measures can effectively reduce the power consumption of the electric spine or vending machine, and thus reduce the energy consumption cost of the enterprise.

In short, the electricity cost of a 380V1000kW motor is 1000 kWh per hour, but the actual power consumption needs to be calculated according to the specific situation, and can be optimized by improving the efficiency of the motor.

To calculate the power consumption of a 380V 1000kW motor in one hour, you need to know the power signal factor of the motor. Assuming the power factor of the motor is, then its actual power is 1000kw x = 850kw. The electrical energy consumption in one hour can be calculated by the following formula:

Electrical energy consumption (kWh) = power balance burial rate (kW) x time (hours) Therefore, the power consumption of a motor in one hour is 1000 kW x 1 hour = 1000 kWh. It should be noted that this is only the power consumption of the motor, and does not include the energy consumption of other equipment or systems.

Good afternoon, dear, I'm honored to answer for you. The power consumption of 380v 1000kw motor in one hour is 1 kWh 380v 1000kw motor power consumption per small and buried hour can be calculated by the following formula: power consumption (kWh) = power (kW) x time (hour) First of all, the power of the motor needs to be converted from kW to kWh.

1 kWh is equal to 1000 kWh, so 1000 kWh = 1,000,000 watts. 1000kw = 1000,000 watts If the motor runs for 1 hour, then: power consumption (kWh) = 1000 kW x 1 hour = 1000 kWh Therefore, the power consumption of a 380v 1000kw electric machine is 1000 kWh per hour.

This is only the theoretical power consumption of the motor, and in fact it will be affected by the efficiency of the motor, load, power supply voltage, etc. At the same time, if you want to calculate your electricity consumption accurately, you need to take into account the price of electricity, as it may vary from region to region and time of day. I hope mine can help you

Hello dear, happy to answer your <>

380V is the voltage and 1000W is the power. To calculate one-hour power consumption, the power needs to be converted into energy consumption. The relationship between power and time can be calculated using the following formula:

Energy (kWh) = Power (kW) Time (hours). Start by converting the power to kilowatts: 1000w = 1000 1000 = 1 kilowatt.

Then set the time to 1 hour: energy (kWh) = 1 kW 1 hour = 1 kWh. Therefore, the power consumption of the 380V 1000W punching motor in one hour is 1 kWh = 1 kWh.