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Anonymous users2024-02-11Summary. And Xiaoqiang is 2 minutes and 15 seconds.
Classmates, what do you ask for in the end?
Who ran fast. Don't worry, the teacher will do the math, wait a while.
Xiao Ming ran fast.
How to calculate. Because minutes 2 minutes + minutes + 9 seconds.
And Xiaoqiang is 2 minutes and 15 seconds.
2 minutes 9 seconds 2 minutes 15 seconds.
Therefore, Xiao Ming ran fast.
This conversion formula is to be kept in mind.
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Anonymous users2024-02-10Find the total multiple of two people running a lap for 12 minutes.
Therefore, for two people to meet again, it will take 12 minutes later.
At this time, the two men ran three laps and two laps respectively. Xiao Ming ran three laps. Xiaoli ran two laps.
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Anonymous users2024-02-09The least common multiple of 4 and 6 is 12, and the two meet again at the starting point after 12 minutes. At this time, Xiao Ming ran 3 laps and Xiao Li ran 2 laps.
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Anonymous users2024-02-08The unit is the same, a total of 100 meters, then the speed ratio of Xiao Gang and Xiao Ming: 80:70 = 8:7, the speed ratio is equal to 8:7, then Xiao Ming's speed is seven-eighths of Xiao Gang, then use 100 7 8 = meters.
I hope it helps you and I wish you progress in your studies.
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Anonymous users2024-02-07The same time distance ratio of 8:7 is equal to running meters.
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Anonymous users2024-02-06This question is about unit conversion, and the solution is as follows:
1 minute = 60 seconds.
2 3 minutes = 2 3 60 = 40 seconds.
Minutes = seconds. 36 seconds, 40 seconds, 50 seconds.
Xiao Ming ran fast.
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Anonymous users2024-02-05A cycling team conducts training.
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Anonymous users2024-02-04Let it be x per second. That is, 4x+6x=100;10x=100；x = 10 (seconds).
A: Xiao Bin and Xiao Ming met 10 seconds later.
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Anonymous users2024-02-03Hello, can you describe your problem in detail?
Hello, according to your question, find an answer to a similar question for you.
Analysis (1) This question is answered by using the encounter questions in the itinerary, and the sum of the distance traveled by the two people is equal to the total distance;
2) This question uses the chase and question in the itinerary to answer the question, and the difference between the distance traveled by the two people is equal to the distance between the two The two questions use the most basic quantitative relationship: speed time = distance
Answer: (1) If the two meet after x seconds, then Xiaoqiang runs 6x meters and Xiaobin runs 4x meters, then the equation is 6x+4x=100, and the solution is x=10;
Answer: The two met after 10 seconds;
2) After setting y seconds, Xiaoqiang catches up with Xiaobin, according to the question: Xiaoqiang ran 6y meters, Xiaobin ran 4y meters, then the equation is: 6y-4y=10, and the solution is y=5;
Answer: The two started in the same direction at the same time, and Xiaoqiang caught up with Xiaobin 5 seconds later
Analysis (1) This question is answered by using the encounter questions in the itinerary, and the sum of the distance traveled by the two people is equal to the total distance;
2) This question uses the chase and question in the itinerary to answer the question, and the difference between the distance traveled by the two people is equal to the distance between the two The two questions use the most basic quantitative relationship: speed time = distance
Answer: (1) If the two meet after x seconds, then Xiaoqiang runs 6x meters and Xiaobin runs 4x meters, then the equation is 6x+4x=100, and the solution is x=10;
Answer: The two met after 10 seconds;
2) After setting y seconds, Xiaoqiang catches up with Xiaobin, according to the question: Xiaoqiang ran 6y meters, Xiaobin ran 4y meters, then the equation is: 6y-4y=10, and the solution is y=5;
Answer: The two started in the same direction at the same time, and Xiaoqiang caught up with Xiaobin 5 seconds later
If there are no other doubts and questions, please give a thumbs up after the consultation, thank you, and have a happy life
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