What is 7 to the power of 2010 and how to calculate the 7 to the power of 2010?

Multiply by 10 to the power of 1698, brother, if you had so many grains of rice, enough people in the world to eat for a century.

This thing can only be calculated with a calculator, and if you do it by hand, you can't calculate it even if you have handwriting cramps.

Answer: Use the xy function of the calculator.

The 7 to the power of 2010 is relatively large, and it cannot be calculated with conventional calculation methods, so it can be calculated with the help of a calculator.

Calculator operation process Input: 7, enter xy, and then enter 2010 (7, 2010).

The unit of 7 to the power of the 1st is 7, the unit of the 2nd power of 7 is 9, the unit of the 3rd power of 7 is 3, and the unit of the 4th power of 7 is 1;

The unit of 7 to the power of 5 is 7, the unit of 7 to the power of 6 is 9, the unit of 7 to the power of 7 to the power of 7 is 3, and the power of 7 to the power of 8 is 1;

The unit of 7 to the 9th power is 7, the 10th power of 7 is 9, the 11th power of 7 is 3, and the 12th power of 7 is 1;

。Lao Hui. Every 4 numbers is a cycle, and the single digit of 7 to the power of 2012 is 1 (the same as 7 to the 4th power).

The 10 digits of 7 to the power of 2011 are 4, I calculated it with a VBA in Excel, scientific notation.

There are 1700 bits for the full results, as follows:

The procedure is as follows: sub macro 1().

m = 7 '3 of 2 4038 = 2019n = 2011'To the nth power.

w = 189 'The number of 9-digit cells in the budget result.

j = 2 'From the second line, multiply the second to start the calculation.

cells(1, w) = m 'Place cardinality.

do while j <= n '

for i = w to 1 step -1cells(j, i) = cells(j - 1, i) *mnextfor i = w to 2 step -1a = int(cells(j, i) / 1000000000)b = cells(j, i) -a * 1000000000cells(j, i) = b

cells(j, i - 1) = cells(j, i - 1) +a

nextj = j + 1

loopend sub

7 to the 1st power, the last number is 7, 7 to the 2nd power, the last two numbers are 49, 7 to the 3rd power, the last two numbers are 43, 7 to the 4th power, the last two numbers are 01, 7 to the 5th power, the last number is 07, 2011 4 = 502 ......3

So the number of tens to the power of 7 in 2011 is 4.

The original title is the proportional series, the first term is 7, the common ratio is 7, and the sum of the first 2012 terms is found

The formula for the sum of the first n terms of the equal ratio of the lead slow banquet is: sn=a1(1-q n) (1-q).