About the selection of servo motors 10

Updated on technology 2024-07-16
7 answers
  1. Anonymous users2024-02-12

    The main difference between cryogenic servo motors and normal motors is the temperature range in which they are designed and used. Ordinary Motors: Ordinary motors are motors that typically operate at room temperatures and are designed and manufactured with the temperature conditions of general industrial and household applications in mind.

    The temperature range of these motors is typically 0??c (Celsius) to 40??c.

    In this range, the performance and reliability of ordinary motors can be well guaranteed. Low-temperature motors: Low-temperature servo motors are specially designed and manufactured for use in low-temperature environments.

    These motors are capable of operating in more extreme low temperature conditions and have higher cold resistance. Their temperature range is usually -40??c or lower, e.g. -60??

    c。Low-temperature motors play an important role in applications such as extremely cold regions, high altitudes, refrigeration industry and scientific experiments...

  2. Anonymous users2024-02-11

    Depending on the selection and application of the servo motor, it is simply necessary to determine: the nature of the load (such as horizontal or vertical load, etc.), the requirements of torque, inertia, speed, accuracy, acceleration and deceleration, the requirements of upper control (such as the requirements for port interface and communication), and the main control mode is position, torque or speed. Whether the power supply is DC or AC power, or battery powered, voltage range.

    Specific control principles and examples, these are long to talk about, really, it is better to go here, mainly to consult and refer to opinions, are all experienced.

  3. Anonymous users2024-02-10

    The technical parameters of the servo motor are: 1. Confirmation of speed and encoder resolution. 2. Conversion of load torque on motor shaft and calculation of acceleration and deceleration torque.

    3. Calculate the load inertia and the matching of inertia, Yaskawa servo motor as an example, the inertia matching of some products can reach 50 times, but the smaller the actual better, so that the accuracy and response speed are good. Fourth, the calculation and selection of regenerative resistance, for servo, generally more than 2kw, to be configured. Fifth, cable selection, encoder cable twisted pair shielding, for Yaskawa servo and other Japanese products the absolute value of the encoder is 6 cores, incremental is 4 cores.

  4. Anonymous users2024-02-09

    There are also corresponding rules and formulas to follow in the selection of servo motors. The most common mechanical transmission structures are timing belts, racks and pinions, screw rods, etc. Taking the synchronous belt as an example, the parameters that need to be calculated are motor speed, motor torque, and moment of inertia.

    First, the rated speed of the motor n=(V 2R)*i, the tensile force required at the moment of start-up f=(m+m1-m2)a+(m+m1-m2)g (horizontal), f=(m+m1-m2)a+(m+m1-m2)g+(m+m1-m2)g (vertical), t torque=f*motor=t torque, mechanical reduction ratio n, motor power=n*t motor 10, starting inertia j=1 2mr2, motor inertia j motor = j reduction ratio squared n2 inertia ratio i. Second, the diameter of the synchronous pulley d=100mm, the total weight of the hoisting machine cargo platform m=30kg, the total weight of the cargo m1=10kg, the counterweight m2=25kg, the lifting rolling friction coefficient takes = acceleration a = 2m s2, and the lifting speed v = 3m s. The reduction ratio of the reducer is i=5, the rated speed of the motor is n=(V 2R)*I=3 (2*, the tensile force required at the moment of start-up is f=(m+m1-m2)a+delta, (m+m1-m2)g+(m+m1-m2)g=(30+10-25)*2+.

    t torque = f * r =, converted motor torque t1 =, converted motor power p1 = 2866*. Starting inertia J = 1 2mr2 =, the inertia required to convert the motor J1 = , according to the empirical value to take the inertia ratio = 10, then the actual J electricity = J1 10 =. It is calculated that the motor meets at least the following conditions, and the inertia of the motor is 4 Nm under the following conditions.

    So you can choose the motor of 80ST-M04030.

  5. Anonymous users2024-02-08

    You should want to apply it directly now, so you won't talk about so many theories. You first calculate the power of the current servo motor from the original motor. I don't have to write these formulas.

    As for the torque, it can be estimated, as long as it is satisfied. The other is the speed response frequency, your speed ratio is not large, just be satisfied, and waste more. In fact, most servo motors can meet your requirements, and these are just to save costs.

  6. Anonymous users2024-02-07

    Torque is calculated first, and then selected according to the speed ratio.

  7. Anonymous users2024-02-06

    Hello, the parameters you give are not very complete, so I want to help you calculate it, in fact, the motor selection is mainly to calculate the torque and inertia, I will give you the formula, you set the formula yourself.

    J (wire cylinder) = Pi* (D1 1000)) 4th power J (load) = W * (1 2 Pi * BP 1000) square J = J (wire cylinder) + J (load).

    pi=, l is the length of the screw cylinder (mm) d is the diameter of the screw cylinder w is the load weight, and the premise of this formula is that the load moves in parallel, not vertically or incliningly. After finding J, look at your actual requirements to determine the load inertia ratio, if you require rapid acceleration and deceleration, the inertia ratio can not exceed 5

    You need to know the acceleration time of your system in terms of load torque, and if the acceleration time is not required, it can not be counted.

    I don't understand that they're coming to me.

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