Solve 1 1 2 to the 8th power 1 1 2 to the 4th power 1 1 2 to the 2nd power 1 1 2

Updated on healthy 2024-07-28
15 answers
  1. Anonymous users2024-02-13

    The steps to solve the problem are as follows:

    1+1 2 to the 8th power) (1+1 2 to the 4th power) (1+1 2 to the 2nd power) (1+1 2).

    1+1 2 to the 8th power) (1+1 2 to the 4th power) (1+1 2 to the 2nd power) (1+1 2) (1-1 2) (1-1 2).

    1-1 2 to the 16th power) (1-1 2).

    2-1 2 to the 15th power.

  2. Anonymous users2024-02-12

    It is like this (1+1 2 to the 8th power) (1+1 2 to the 4th power) (1+1 2 to the 2nd power) (1+1 2).

    1+1 2 to the 8th power) (1+1 2 to the 4th power) (1+1 2 to the 2nd power) (1+1 2) (1-1 2) (1-1 2).

    1-1 2 to the 16th power) (1-1 2).

    2-1 2 to the 15th power.

  3. Anonymous users2024-02-11

    1+1 2 to the 8th power) (1+1 2 to the 4th power) (1+1 2 to the 2nd power) (1+1 2).

    1+1 2 to the 8th power) (1+1 2 to the 4th power) (1+1 2 to the 2nd power) (1+1 2) (1-1 2) (1-1 2).

    1-1 2 to the 16th power) (1-1 2).

    2-1 2 to the 15th power.

  4. Anonymous users2024-02-10

    The numerator and denominator are multiplied by (1-1, 2) respectively

  5. Anonymous users2024-02-09

    (5 + 1) (5 + 1) (5 to the fourth power + 1) (5 to the eighth power + 1) (5 to the 16th power + 1) +

    Multiply the first term by (5-1) 4;Since the value is 1, multiplying this item does not affect the result.

    Original = [(5-1) (5+1) (5 +1) (5 to the fourth power + 1) (5 to the eighth power + 1) (5 to the 16th power + 1)] 4 + 1 4

    5 -1) (5 +1) (5 to the fourth power + 1) (5 to the eighth power + 1) (5 to the 16th power +1)] 4 + 1 4

    5 to the fourth power -1) (5 to the fourth power + 1) (5 to the eighth power + 1) (5 to the 16th power +1)] 4 + 1 4

    5 to the power of 32 -1) 4 + 1 4

    5 to the power of 32 4+1 4-1 4

    5 to the 32nd power 4

  6. Anonymous users2024-02-08

    (2+1) (2 +1) (2 to the fourth power + 1) (2 to the eighth power + 1)....(2 to the power of 512 +1).

    2-1) (2 + 1) (2 + 1) (2 to the fourth power + 1) (2 to the eighth power + 1) ...(2 to the power of 512 +1).

    (2+1) (2 +1) (2 to the fourth power + 1) (2 to the eighth power + 1)....(2 to the power of 512 +1).

    2 to the fourth power - 1) (2 to the fourth power + 1) (2 to the eighth power + 1) ...(2 to the power of 512 +1).

    = (2 to the power of 512 - 1) (2 to the power of 512 + 1).

    2 to the power of 1024-1

    Happy learning!

    o(∩_o~

  7. Anonymous users2024-02-07

    Preceded by (2-1) a square difference.

    Original = (2-1) (2+1)· (2 +1)· (2 to the fourth power +1) · (2 to the eighth power + 1).

    (2+1) (2 +1) (2 to the fourth power + 1) (2 to the eighth power + 1)....

    2 to the fourth power -1) (2 to the fourth power +1) · (2 to the eighth power + 1) = (2 to the eighth power - 1) (2 to the eighth power + 1).

    2 to the 16th power - 1

  8. Anonymous users2024-02-06

    Multiply by (2-1).

    2+1) (2 +1) (2 to the power of 4 +1) (2 to the power of 8 +1) +1

    2-1) (2 + 1) (2 squared + 1) (2 to the 4th power + 1) (2 to the 8th power + 1) + 1

    2 to the 8th power - 1+1

    2 to the 16th power.

    If it helps you, please remember to adopt, o( o thank you.

  9. Anonymous users2024-02-05

    Because (2-1) = 1

    So the original formula = (2-1) (2 + 1) (2 + 1) (2 to the fourth power + 1) (2 to the eighth power + 1) ......2 to the nth power +1).

    (2+1) (2 +1) (2 to the fourth power + 1) (2 to the eighth power + 1)....2 to the nth power +1).

    …= (2 to the nth power - 1) (2 to the n power + 1) = 2 to the n + 1 power - 1

  10. Anonymous users2024-02-04

    The title should read: (2 + 1) (2 + 1) (2 to the fourth power + 1) (2 to the eighth power + 1) ......2 to the nth power + 1) [n = 2 m, m is a natural number] (2 + 1) (2 + 1) (2 to the fourth power + 1) (2 to the eighth power + 1) ......2 to the nth power +1).

    2-1) (2 + 1) (2 + 1) (2 to the fourth power + 1) (2 to the eighth power + 1) ...2 to the nth power +1).

    (2+1) (2 +1) (2 to the fourth power + 1) (2 to the eighth power + 1)....2 to the nth power +1).

    2 to the 2n power - 1

  11. Anonymous users2024-02-03

    (2+1) (2 +1) (2 to the fourth power + 1) (2 to the eighth power + 1)....2 to the nth power +1).

    2-1) (2 + 1) (2 + 1) (2 to the fourth power + 1) (2 to the eighth power + 1) ...2 to the nth power +1).

    (2+1) (2 +1) (2 to the fourth power + 1) (2 to the eighth power + 1)....2 to the nth power +1).

    2 to the nth power +1).

  12. Anonymous users2024-02-02

    (2+1) (2 +1) (2 to the fourth power + 1) (2 to the eighth power + 1)....2 to the nth power +1).

    2^-1)(2^2+1)(2^4+1)(2^8+1)..2^n+1)

    2^4-1)(2^4+1)(2^8+1)..2^n+1)

    2^8-1)(2^8+1)..2^n+1)=2^(2n)-1

  13. Anonymous users2024-02-01

    1/2=1-1/2

    1 2 + (1 2) +1 2) = 7 8 = 1-1 81 2 + (1 2) +1 2) +1 2) to the power of 4 = 15 16 = 1-1 16 .........1 2 + (1 2) +1 2) +1 2) +1 2).1 2) to the nth power = 1-1 2 to the nth power.

  14. Anonymous users2024-01-31

    This is a proportional series, and the common ratio is 1 2

    Original 1 2*(1-(1 2) n) (1-1 2).

    1-1/2^n

  15. Anonymous users2024-01-30

    (1+2) (1+2 ) (1+2 to the fourth power) (1+2 to the eighth power) = -(1-2) (1+2) (1+2) (1+2 to the fourth power) (1+2 to the eighth power).

    (1-2) (1+2) (1+2 to the fourth power) (1+2 to the eighth power) = - (1-2 to the fourth power) (1+2 to the fourth power) (1+2 to the eighth power) = - (1-2 to the eighth power) (1+2 to the eighth power).

    (1-2 to the sixteenth power).

    2 to the sixteenth power - 1

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