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1. Reflection of light.
2. Principle of plane mirror imaging. Left and right are reversed.
3. Left hand. Principle of plane mirror imaging. Left and right are reversed.
4. Same. You can consult the junior high school physics teacher for specific explanations, because this is the content of junior high school physics.
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1) It should be the use of specular reflection.
2) Reflection, not the same is just the opposite, why. Draw a specular reflection diagram to know the pull.
3) Left hand pull. Draw a specular reflection diagram again.
4. Same. Again, draw a specular reflection diagram.
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1.The principle of reflection of light.
2.The principle of plane mirror is also the principle of reflection, and the left and right sides are opposite and symmetrical.
3.Left hand, reflex principle.
4.The size is the same, but the left and right sides are opposite and symmetrical, and the principle of plane mirror imaging.
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1. Reflection of plane mirrors.
2, ditto, just along the lake folding.
3. Left hand, because the image folds along the mirror.
4. The same, this is an axiom, and you will know it when you learn physics in the future.
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Solution: If du has x red balls, then there are 2 3x yellow balls, and 2 3x blue dao balls have 2 3x inner 2 3+3.
x-(2/3x×2/3+3)=32
x-4/9x-3=32
5/9x-3=32
5/9x=32+3
5/9x=35
x=63 has 2 yellow balls 2 3x=63 2 3 = 42, blue balls have 2 3x 2 3+3=2 3 63 2 3+3=31, and the wooden box has a capacity of 63+42+31=136.
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Solution: If there are baix red balls, then yellow balls have (
du2 3x) zhi, blue balls have (2 3x*2 3+3) equal relations: the number of dao red balls.
Special - Number of blue balls = 32
According to the equation of the question: x-(2 3x*2 3+3)=32x-(4 9x+3)=32
x-4/9x-3=32
5/9x=32+3
x=35*9 5 (originally 35 divided by 5 9 oh, don't get me wrong) x=63
Yellow balls: 63*2 3=42 (pieces) Blue balls: 42*2 3+3=31 (pieces) Total: 63+42+31=136 (pieces).
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Let their numbers be different.
Bai is x, duy, and z, according to the title.
zha ternary equation dao
groups, y=2 3x, z=2 3y+3, x—z=32, respectively. If you solve it, you can do it inside. Answers: 63 red balls, 42 yellow balls, and 31 basketball balls.
However, if it is a question in the sixth grade of elementary school, there may be some simple algorithm, such as Olympiad mathematics. Do you teach equations in elementary school? I don't know...... hey
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Actual distance = 3 * 26000000 = 78000000cm = 780000m = 780km
The plane flew for 1 hour and 6 minutes = 11 10 hours.
780 (11 10) = km h = 710 km h 09 cycles.
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7:54 is the hour.
A: The aircraft flies 710 kilometers per hour.
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Solution: If the capacity of container A is x liters, then the capacity of container B is 2*(105-x) liters.
2*(105-x)+1/3*x=105
Solution: x=63 The capacity of container B is 2*(105-x)=84 liters.
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Solution: Filling 3 containers B and 1 container A requires 105 * 3 = 315 liters of water;
105 litres of water are required to fill 1 2 containers B and 1 container A;
210 litres of water are required to fill 3-1 2 = B containers.
Container B capacity: 210 litres.
A container capacity: 105-84 2 = 63 liters.
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Fill container B and container A with 1 3
Then 1 2 of container B and 1 6 of volume A = 105 2 liters of container A capacity = (105-105 2) (1-1 6) = 63 liters of container A capacity = 105-63 = 42 liters.
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105 liters can be filled with 1 2 of container A and container B, then 210 liters can be filled with 2 containers A and 1 container B, and 1 3 of container B and container A are filled with 105 liters, then 1 container A plus 2 3 containers A is 105 liters, and the capacity of container A is 105 divided by (1 2 3) = 63 liters, so that container B is 84 liters.
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Solution: The capacity of container A is x, then B is: 105-x 3 So there is equation:
x+(105-x/3)/2=105
Get x = 63, B container = 105-63 3 = 84 and that's it.
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Let container A have a capacity of x liters and B as y liters.
According to the title. x/3+y=105
x+y/2=105
x=63; y=84
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Multiply 2,210 litres by the second case of the title to fill two containers of A and one container of B. Compared to the previous case, subtraction, 105 liters of water can fill 5 3 A containers. Then 105 divided by 5 3 is the capacity of container A, then the capacity of container B is unknown.
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100+x= Move the item here.
The result is that x is approximately equal to 5
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Because the volume of the cone is equal to one-third of the volume of the cylinder of equal height of the bottom, when the volume is constant, the base area is inversely proportional to the height.
So (1) 5 3 = 15 (cm).
2) 12 3 = 36 (cm).
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Using the principle that the cone is one-half of the volume of the cylinder, the formula for calculating the volume of the cone, the area at the bottom of the cone is known, and the area at the bottom of the cone is known.
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1/5=4/20;1/4=5/20;The rest accounts for the whole 11 20, and the whole is 200kg, so the remaining 11 20 is 110 kg.
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The topic of 110kg is very simple, one-fifth plus one-quarter is nine-twentieths
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200 (1-quarter-5).
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