x x 1 0, find x to the 3rd power 2x 2010

1. m+1+2n-1=m+2n=5①

2m+n+2=3②

It is obtained: m=-1, n=3, m+n=2(b)2 (3/2x^2+xy-3/5y^2)(-4/3x^2y^2)=-2x^4y^2-4/3x^3y^3+4/5x^2y^4

3.The solution obtains a=-2, b=-3, and substituting the original formula = 6*6-9*8-4*(-11)=36-72+44=8

Original = a-b

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1)x^3+2x^2+2010=x*x^2+2x^2+2010=x(1-x)+2(1-x)=2010=-x^2-x+2012=-(x^2+x)+2012=2011

2) (m + 1 power of a n + 2 of b) (2n of a - 2m power of b) = 5 power of a and 3 power of b after combining the same kind of terms is:

a (m+2n)*b (2m+n+2)=a 5*b 3, the square into two sides corresponding to equal can obtain m+2n=5,2m+n+2=3The solution yields m=-1 and n=3

3) (three-thirds x +xy-three-fifths y) four-thirds x y) = -2x 4*y 2-4 3*x 3*y 3+4 5*x 2*y 4

4)ab（b+b²）-b²（ab-a）+2a（a-b²）=ab²（b+1）-ab²（b-1）+2a（a-b²）

2ab²+2a（a-b²）=2a(b²+a-b²)=2a²=8

x^2+x-3=0

x^2+x=3

3-x^2=x

3-x^2-x^3)/(x-1)

x-x^3)/(x-1)

x(1-x^2)/(x-1)

x(x+1)

(x^2+x)

3(x-1) (x-3)=m 2 (2x-6) denominator is meaningful, x≠3

Denominator 2 (x-1) = m2

x=1+m^2/2

The equation has an additional root, 1+m 2 2=3

m^2=4m=±2

m=2. (m^2-2m)/(m^2-1)]/[m-1-(2m-1)/(m+1)]

0m=-2, (m2-2m) (m2-1)] [m-1-(2m-1) (m+1)].

3 x+6 (x-1)-(m+x) [x(x-1)] = 0 denominator is meaningful, x≠0 x≠1

Denominator 3(x-1)+6x-(m+x)=0

I tidy it up and get it. 8x=m+3

x=(m+3)/8

When x=0, m=-3

When x = 1, m = 5

To sum up, m is taken as any real number except -3 and 5.

x-1) (x-2) = m (x-2) + 2 denominator is meaningful, x≠2

Remove the denominator x-1=m+2(x-2).

I tidy it up and get it. x+m-3=0

x=3-m is a positive number, x>0 3-m>0 m<3

When x=2, m=1

In summary, m<3 and m≠1 are obtained

The value of m can be ( , 1) u(1, 3).

x -3x+1=0 is divided by x

x+1 x=3 is the same square.

x^2+1/x^2=7

x x to the fourth power + 3x +1 divided by 2=1 (x2+1 x2+3).

1+x+x+x +x to the third power of 0

So x+x +x=-1

So we get x=-1

So x+x+x to the third power of x + x + ......The power of 2008 of x = 0ps: lz sees that it is a high-order problem, and the x value is nothing more than , -1, and you will know it with a look.

1+x+x+x +x to the third power of 0

Multiplication xx + x + x to the third power + x4 power = 0

Multiply x x 4 times.

x5 times + x6 times + x7 times + x8 times = 0

The same goes for ......x2005+x2006+x2007+x2008=0 add up to 0

x²-3x+1=0

x-3+1/x=0

x+1/x=3

x x to the fourth power + 3x + 1 numerator denominator divided by x at the same time

1/(x²+3+1/x²)

1/[(x+1/x)²+1]