On October 10, chemistry 7, the molecular formula of a certain ester is C6H12O2, and its transformat

Esters are hydrolyzed to form acids and alcohols, and observation shows that A is an acid, B is an alcohol, and A and C can undergo a silver mirror reaction, then A can only be formic acid, C is an aldehyde with five carbon atoms, and aldehydes with five carbon atoms have four isomers, which are valeraldehyde, 2-methylbutyraldehyde, 3-methylbutyraldehyde, and 2,2-dimethylpropionaldehyde. The alcohols are also four isomers, and the esters are also four isomers.

The answer is b

<> esters are hydrolyzed to produce acids and alcohols, A is acid, B is alcohol, alcohol can be catalytically oxidized to obtain aldehydes, and because A and C can undergo silver mirror reaction, A can only be formic acid HCOOH, C is an aldehyde of five carbon atoms, 1, CH3-CH2-CH2-CH2-C=OH 2, CH3-CH-CH2-C=OH 3, CH3-CH2-CH-C=OH 4, C(CH3)3C=OH,

ch3 ch3

Aldehydes with five carbon atoms have four isomers, then the corresponding alcohols are also four isomers, and esters are also four isomers.

The answer is b

The silver mirror reaction is to identify the aldehyde group, AC has an aldehyde group, and because the hydrolysis of the ester obtains A, a is formic acid, B is oxidized to form C aldehyde, then B is a primary alcohol, and because the unsaturation is 1, it is occupied by the carbonyl group, so there are four carbon atom skeletons left, which can form several groups and have several structures, that is, the type of butyl group, and the answer is B

A: As follows. It can form a yellow precipitate with 2,4-dinitrophenylhydrazine, indicating that there is a C=O group, and it will not react with Tolen's reagent to form a silver mirror, indicating that it is not an aldehyde but a ketone.

A catalytically hydrogenates to obtain compound B, then B is an alcohol. B is reacted with concentrated sulfuric acid at high temperature to obtain compound C, that is, the alcohol hydroxyl group is eliminated to form a carbon-carbon unsaturated double bond, and C is an olefin. C is treated with ozone and zinc powder to obtain a molecule of aldehyde D and a molecule of silver ketone E, and the ozone hydrolysis reaction occurs to generate an aldehyde and a ketone, indicating that the carbon skeleton is T-shaped, and there are only 6 carbons, and the skeleton can only be.

c cc-c-c=c or c-c=c

c c-cd cannot react with iodoform, indicating that d does not have a -coch3 structure, and the second carbon skeleton can be ruled out, then c is.

ch3ch2ch2=c(ch3)2

If it is reversed to A, then A is CH3CH2Coch(CH3)2<>

Original topic: A compound with the molecular formula C6H12O, can form a yellow precipitate with 2,4-dinitrophenylhydrazine, but will not react with Toren reagent to form a silver mirror. A catalyzes hydrogenation to obtain compound B, B reacts with concentrated knowledge Yeyan sulfuric acid at high temperature to obtain compound C, C is treated with ozone and zinc powder to obtain a molecule of aldehyde D and a molecule of ketone E, D can not react with iodoform, and the structure of ABCDE is obtained.

Summary. Analysis: The ester with the molecular formula C10H20O2 is hydrolyzed under acidic conditions, and according to the molecular composition, it can be known that the ester formed by saturated monoacid and saturated monool can be hydrolyzed to form organic matter A and B under acidic conditions, and A can be converted into B under certain conditions, indicating that the number of carbon atoms of A and B is the same, and the carbon chain is the same, so as to answer this question

Answer: Solution: C10H20O2 is a saturated ester, and the two side chains are the same, there are 2 hydrogen atoms on the carbon linked to the hydroxyl group to be oxidized to carboxylic acid, and the analysis of C4H9CoOH or C4H9CH2OH contains C4H9-hydrocarbon group, and there are four structures:

An ester with the molecular formula C10H20O2 can be hydrolyzed to form carboxylic acids and alcohols with the same number of carbon atoms, and the ester has the most.

Good morning, dear, wow.

Analysis: The ester with the molecular formula C10H20O2 is hydrolyzed under acidic conditions, and according to the molecular composition, it can be known that the ester formed by the saturated monoacid and saturated monool can be decomposed into organic matter A and B under acidic bending conditions, and A can be converted into B under certain conditions, indicating that the number of carbon atoms of A and B is the same, and the carbon chain is the same, so as to answer the question Answer: Solution:

C10H20O2 is a saturated ester, and the two side chains are the same, there are 2 hydrogen atoms on the carbon linked to the hydroxyl group to be oxidized to carboxylic acid, the analysis of C4H9COOH or C4H9CH2OH contains C4H9-hydrocarbon group, there are four structures:

Therefore, it is not difficult to conclude that there are also 4 kinds of isomeric lipids.

How many are there at most.

There are four types of butyl alcohols, and there are eight types of alcohols.

There are 32 kinds in total.

Dear, wait a minute. There are 8 isomers of pentanol, then C4H9Cooh has 4 bells, and the maximum is 32 bells.

Summary. Analysis: The ester with the molecular formula C10H20O2 is hydrolyzed under acidic conditions, and according to the molecular composition, it can be known that the ester formed by saturated monoacid and saturated monool can be hydrolyzed to form organic matter A and B under acidic conditions, and A can be converted into B under certain conditions, indicating that the number of carbon atoms of A and B is the same, and the carbon chain is the same, so as to answer this question

Answer: Solution: C10H20O2 is a saturated ester, and the two side chains are the same, there are 2 hydrogen atoms on the carbon linked to the hydroxyl group to be oxidized to carboxylic acid, and the analysis of C4H9CoOH or C4H9CH2OH contains C4H9-hydrocarbon group, and there are four structures:

Therefore A has four structures, so the number of isomers of the ester that meets this condition is 4

Therefore, an ester with the molecular formula C10H20O2 can be hydrolyzed to form carboxylic acids and alcohols with the same number of carbon atoms, and the ester has the most.

Wait a minute. Analysis: The ester with the molecular formula C10H20O2 is hydrolyzed under acidic conditions, and according to the molecular composition, it can be known that the ester formed by saturated monoacid and saturated monool can be hydrolyzed to form organic matter A and B under acidic conditions, and A can be converted into B under certain conditions, indicating that the number of carbon atoms of A and B is the same, and the carbon chain is the same

Solution: C10H20O2 is a saturated ester, and the two limb side chains are the same, and there are 2 hydrogen atoms on the carbon linked to the hydroxyl group to be oxidized to carboxylic acid, and the analysis of C4H9COOH or C4H9CH2OH contains C4H9-hydrocarbon group, and there are four structures. Therefore, A has four structures, so the number of isomers of esters that meet this condition is 4, so A is chosen

If you are satisfied, can you like me, thank you.

The molecular formula of A is C6H12O2, A can react under alkaline conditions to form B and D, B reacts with acid, it should be salt, D can be oxidized under Cu catalysis, it should be alcohol, then A should be an ester, C and E can not have a silver mirror reaction, indicating that C and E do not contain aldehyde groups, then C cannot be formic acid, if C is acetic acid, then D is CH3CHHch2CH3, if C is propionic acid, then D is CH3CHHch3, if C is butyric acid, then D is ethanol, if E is acetaldehyde, it is impossible, Therefore, A can only be ch3cooch(ch3)ch2ch3 or ch3ch2cooch(ch3)2kind, so choose b

The molecular formula is C10H20O2

The ester is a saturated monoester group, hydrolyzed under alkaline conditions to obtain carboxylate and alcohol, B acidification and C continuous oxidation are obtained the same substance, so B is a sodium carboxylate salt, C is an alcohol, and B and C molecules contain the same number of carbon atoms, and the carbon skeleton structure in B and C molecules is the same, so C10H20O2 is formed

The acid of the ester is C4

H9Cooh, alcohol is C4H9CH2

OH, both contain C4

H9 is hydrocarbon and identical and has four structures: -CH2

ch2ch2

ch3-ch（ch3

ch2ch3

ch2c（ch3

C(CH3 has the molecular formula C10H20O2

The ester has four structures, so D is chosen

There are mainly three types of substances: saturated monobasic acid, ester formed by saturated monobasic acid and saturated monoalcohol, and hydroxyaldehyde.

Saturated monoacids: CH3(CH2)4COOH, CH3CH(CH3)CH2CH2COOH, CH3CH2CH(CH3)CH2COOH, CH3CH2CH2CH(CH3)COOH, (CH3)3CH2COOH, CH3CH2C(CH3)2COOH, CH3CH(CH3)CH(CH3)COOH

Esters: HCOOCH2CH2CH2CH2CH3, 8 kinds of amyl groups are contained in formic acid deficient jujube esters; ch3cooch2ch2ch2ch3, acetate contains a total of 4 kinds of butyl; ch3ch2cooch2ch2ch3；ch3ch2ch2cooch2ch3, which contains propyl, a total of 2 species; ch3ch2ch2ch2cooch3, which contains 4 kinds of dingchameng degrouping.

Hydroxy aldehydes or ketones are generally not known as Zheng Zuo's requirements, such as hoch2ch2ch2ch2ch2cho

The unsaturation of this ester is 1, and the rest of the c is saturated except for the ester group. From the inscription, it is easy to obtain that condition A is the hydrolysis of esters under alkaline conditions, and C can be oxidized twice, which should be alcohol, and has a -CH2OH structure. B is a carboxylate and E is a carboxylic acid with a carboxyl group.

Since C can be oxidized twice to end up in E, C and E each have five carbons (10 2), and the four carbons except the functional group must be arranged in the same order. The types of esters are arranged by the same four carbons, i.e., the four isomeric structures of the butyl group (n-butyl, sec-butyl, sub-butyl, tert-butyl). Pick B

The answer is b, 4 kinds.

AC can undergo silver mirror reaction, then both contain aldehyde-CHO esters hydrolyzed to AB, B can be oxidized to C, then A is an acid, B is an alcohol, and C is a carboxylic acid. AC contains an aldehyde group, so a is the carbon atom on the hydroxyl group of formic acid with two hydrogen atoms attached.

hcooch2ch2ch2ch2ch3

hcooch2ch2ch(ch3)2

hcooch2ch(ch3)ch2ch3

hcooch2c(ch3)3

First of all, it can be determined that the substances A and C generated by ester hydrolysis have aldehyde groups (silver mirror reaction), and substance A is an acid, so A must be formic acid, substance B must be 5 carbon alcohol, and a certain ester of formee (with 5 carbon) is actually to look at the structure of substance B, and the answer is D

I, I

The answer is d, six. Reason: A and C both contain aldehyde group-CHO, A is a carboxylic acid and contains an aldehyde group must be formic acid HCOOH, there is only one, C is an alcohol, C5H11-OH pentanol, there are six kinds of structure, OH-CH2-CH2-CH2-CH2-CH3, OH-CH2-CH2-CH(CH3)-CH3, OH-CH2-CH(CH3)-CH3, OH-CH2-C(CH3)3, OH-CH(CH3)-CH2-CH2-CH3,OH-C(CH3)2-CH2-CH3, a total of 6 species.

Therefore, there are 6 kinds of esters that correspondingly produced.