For the question of ion equations, how to answer ion equations?

No, you misunderstood, soluble strong electrolytes can be disassembled, Na2CO3 is salt, and salt is to be disassembled.

When writing the ion equation, you need to pay attention to:

1.Elemental, gas, and precipitate require the complete chemical formula to be written.

2.Refractory electrolytes or non-electrolytes also need to be written with the full chemical formula.

3.If it changes from ionic to non-ionic before and after the reaction, it should be retained.

If these three are ensured, it should be possible to write the ion equation directly without the need to write it through the reaction formula. In order to write ion equations quickly, you need to practice a lot and be familiar with the properties of matter and the reaction equations.

Hope, thank you.

Electrolytes can generally be divided into strong electrolytes and weak electrolytes, and the conductivity of the two varies greatly. Strong electrolytes can be considered to exist entirely in the form of ions in solution, i.e. there are no "molecules" of the electrolyte (at least in the range of dilute solutions).

Strong electrolytes: all salts (high school stage), three strong acids (high school stage inorganic strong acids are only required for these, organic strong acids are only understood, there are trinitrophenol (picric acid), etc.), and alkali metals, alkaline earth metals formed by alkali metals (lithium hydroxide, magnesium hydroxide are medium and strong bases, except for beryllium hydroxide is amphoteric acid).

The reason why sodium carbonate needs to be dismantled is because carbonate is not easy to seize hydrogen ions in water to form bicarbonate. Therefore, it basically exists as carbonate ions in water.

Na2CO3 is soluble and exists in water as sodium ions and carbonate particles and a small amount of bicarbonate particles, and of course it can be disassembled.

Na2CO3, as a salt, is ionizable and is a strong electrolyte that can be completely ionized.

na2co3 = 2na+ +co3^2-

CO3 2- is a weak acid and ion, hydrolyzed, and does not ionize.

Salt is all detachable1! Weak acid and weak alkali are hungry 1 that cannot be dismantled!! Sodium carbonate is a strong alkali and weak salt!! As long as it's salt, you can dismantle it!!

1) NaCN is a strong alkali and weak salt, hydrolysis is alkaline, and the ionic equation is: CN - H2 O HCN+OH - so the answer is: alkali; cn - h 2 o⇌hcn+oh -

2) cn - ionizing water cn - h2o hcn + oh - water can ionize: h2o oh - h + so the ion concentration magnitude relationship is: c(na + c(cn - c(oh)> c(h + so the answer is:

c(na + salute c(liangshan comic cn - c(oh)> c(h +

3) The conservation of charge is based on the apparent neutrality of the solution, that is, the concentration of the positive charge of the hydrogen ions in the solution is equal to the concentration of the negative charge of the anions, so it is: c(na + c(h + c(oh - c(cn -

The conservation of materials is based on the column formula of CN- partial hydrolysis to HCN, so there is C(Na + C(HCN) + C(CN -

When a sufficient amount of dilute nitric acid is added to ferrous hydroxide solution, an acid-base neutralization reaction will occur to generate ferrous nitrate and water.

The ionic equation is as follows: Fe(OH) (S) + 2Hno (AQ) Fe(NO) AQ) + 2H O(L) In this equation, ferrous hydroxide (Fe(OH)) is a solid, nitric acid (Hno) is an aqueous solution, ferrous nitrate (Fe(NO) is an aqueous solution, and water (HO) is a liquid.

1. Magnesium hydroxide is soluble in hydrochloric acid

mg（oh）2 + 2h+ =mg2+ +2h2o ；

2. Reaction of barium hydroxide and sulfuric acid:

ba2+ +2oh- +2h+ +so4 2- =baso4↓ +2h2o ；

3. Barium hydroxide reacts with a small amount of sodium bisulfate

ba2+ +oh - h+ +so4 2- =baso4↓ +h2o ；

4. Add a small amount of hydrochloric acid dropwise to sodium carbonate solution

co3 2- +h+ =hco3 -

5. Add a small amount of sodium carbonate dropwise to hydrochloric acid

2h+ co3 2- =h2o + co2 ↑；Nian teasing macro.

6. Add a small amount of ammonium bisulfate to barium hydroxide solution

ba2+ +2oh - nh4+ +h+ +so4 2- =baso4 ↓ h2o + nh3 ↑

7. Sodium bicarbonate and a small amount of clarified lime water

2hco3- +ca2+ +2oh- =caco3↓ +2h2o + co3 2- ；

8. Sodium bicarbonate and sodium bisulfate are mixed

hco3- +h+ =h2o + co2↑ ；

9. Reaction of sodium hydroxide and acetic acid.

ch3cooh + oh- =ch3coo- +h2o ；

10. Insert the aluminum sheet into the copper sulfate solution

2al + 3cu2+ =2al3+ +3cu ；

11. Drop dilute hydrochloric acid to limestone:

caco3 + 2h+ =ca2+ +h2o + co2 ↑：

12. Baking soda ** stomach acid:

HCO3- +H+ =H2O + CO2 refers to height;

13. Magnesium sulfate and barium hydroxide:

mg2+ so42- +ba2+ +2oh- =mg（oh）2 ↓ baso4 ↓

The ionic equation of barium chloride solution plus dilute sulfuric acid is the same as that of barium hydroxide solution and the ionic equation of silver plus sodium sulfate solution

ba + so baso Min Shu Banquet

But the chemical equation is different, and the chemical equation of barium chloride solution plus dilute sulfuric acid is as follows:

bacl₂+h₂so₄=baso₄↓+2hcl

The chemical equation of barium hydroxide solution plus sodium sulfate solution is as follows:

ba(oh)₂+na₂so₄=baso₄↓+2naoh

Because sulfuric acid is a strong acid, HSO4- can also be considered to be able to be completely ionized, so when writing the ionization equation of NaHSO4, HSO4- is also disassembled, as sodium ion + hydrogen ion + sulfate ion.

This is not the case with weak acids. For example, the ionization of NaHCO3, HCO3- cannot be separated, so the ionization equation of NAHCO3 can only be written as NAHCO3=NA+ +HCO3-

So NaHCO3+NaHSO4=NA2SO4+CO2+H2O2NA+ +HCO3-+H+ +SO42-=2NA+ +SO42-+CO2+H2O

The same cancellation on both sides is: HCO3-+H+=CO2+H2O

Ag(NH3)2 oh hydroxide diaminohydride is formed when there is excess ammonia Phenol with sodium carbonate: 2C6H5OH + CO3)2- =2C6H5O- CO2 + H2O

This does not react.

Excess Hi solution is added to the ferric nitrate solution: 2Fe3+ 2I- 2Fe2+ +I2

Because there is nitric acid in the solution, it will oxidize the ferric to ferric iron again It should be HCO3- BA2+ OH- =BAC3 +H2O, since it is BA(OH)2 excess, it means that NAHC3 reacts all, so the coefficient is 1, if you don't understand, ask me again.

Excess ammonia water is added to the silver nitrate solution: AG+ NH3*H2O=AGoh +NH4+

The correct one should be: AG+ 2 NH3*H2O=[AG(NH3)2]+ 2H2O

Phenol with sodium carbonate: 2C6H5OH + CO3)2- = 2C6H5O- CO2 + H2O

The correct one should be: C6H5OH + CO3)2- =C6H5O- HCO3-

Excess Hi solution is added to the ferric nitrate solution: 2Fe3+ 2I- 2Fe2+ +I2

The correct one should be: 8h+ +2no3- 6i- 3i2 +2no +4h2o

Excess Ba(OH)2 solution is added to the NaHCO3 solution: 2HCO3-, BA2+ 2OH- = BaCO3 + H2O

The correct one should be HCO3- BA2+ OH- =BACO3 +H2O

1: Silver ammonia solution should be generated, and Ag(NH)2OH is soluble in water.

2: Phenol is too acidic (acidity is large to small: carbonic acid - phenol - bicarbonate), phenol can not make sodium carbonate to produce carbon dioxide, can only produce sodium bicarbonate.

3: The nitrate in ferric nitrate has strong oxidation under acidic conditions (excessive HI ionization out of H), and the oxidation of nitrate is greater than Fe3+, so it is the redox reaction between nitrate and iodine ions.

4: The trim is incorrect, 2 water should be generated.

Sodium bicarbonate is formed from carbon dioxide in phenol because the acidity of carbonic acid is greater than that of phenol and greater than that of sodium bicarbonate. From strong acid to weak acid, it can be seen that the acidity of the product is smaller than that of phenol, so it is sodium bicarbonate.

In small amounts, carbon dioxide reacts with alkali to directly form carbonate and water, and in excess of carbon dioxide, it reacts to form carbonate, followed by carbon dioxide reacts with carbonate and water to form bicarbonate.

"The equation for carbon dioxide in sodium phenol is how a small amount of CO2 is introduced to produce sodium bicarbonate instead of sodium bicarbonate"It is because the three are acidic, and the strength is: H2CO3, phenol, HCO3—. According to the law that only strong acids can produce weak acids, H2CO3 reacts with sodium phenol and can only produce sodium bicarbonate.

You wrote the wrong equation, a small amount is: 2alo2-+CO2+3H2O==2Al(OH)3 + CO32-

The overdose is: AlO2-+CO2+2H2O==Al(OH)3 + HCO3-

Actually, it should be understood like this:

The ratio of AlO2-+CO2+2H2O=Al(OH)3+HCO3-2ALO2-+CO2+3H2O=2Al(OH)3+CO32- changed significantly.

2alo2-+CO2+3h2o=2al(oh)3+CO32-2alo2-+2CO2+4h2o=2al(OH)3+2HCO3 - This seems to see more clearly!

Bicarbonate is an acid salt that belongs to Lewis acid.

Carbonates are basic salts and belong to the alkali group.

So an excess of carbon dioxide is acidic.

An excess of alkali is a basic formula.

Carbonic acid is stronger than phenol, but phenol is weaker acidic than bicarbonate ions, so sodium bicarbonate will not react with phenol, that is, regardless of whether carbonic acid will be excessive or not, it will only produce sodium bicarbonate when it reacts with phenol; Carbonic acid is ionized in two steps, the second ionization is very weak, when the carbonic acid is small, the hydrogen ions ionized in the first step are not enough, and the second ionization will occur, but if the carbonic acid is excessive, the hydrogen ions ionized in the first step are enough and even surplus, so there is no need to use the hydrogen ions ionized in the second step.