Ask me three questions about math, smart friend, please. 15

4 to the power of 33 (think of 2 to the power of 3 or to the power of 3).

The next one is the same.

2008 (the third is).

One, 3 to the power of 44, 4 to the power of 33, and 2 to the power of 55.

Second, the power of 2003 in 2004 is greater than the power of 2004 in 2003.

III, 1024

To do this problem using the ratio method, the 55th power of 2 can be reduced to the 11th power of 64, and the 44th power of 3 can be reduced to the 11th power of 81, and the former is divided by the latter equals the 11th power of (64 81), which is obviously less than 1, so the former is less than the latter.

Do it in a similar way

Generally compare the size of the ratio method or the difference method.

Kid: Work hard.

1. 2 55=(2 5) 11=(32) 11 3 44=(3 4) 11=(81) 11 4 33=(4 3) 11=(64) 11

Power 2 to the power of 55 < power 4 to the power of 33 < power of 3 to the power of 44.

2. According to the formula (a+1) n.

Comparison of the two formulas shows that 2004 2003 < 2003 2004 three, the first round has 2008 numbers, even numbers, except for the odd number of 1004, and so on, the number of remaining numbers is.

That is, the number of remaining numbers is in order1 (11 times in total) The first number of the remaining numbers is 3 in order....2 10 (11 times in total) So the last number is 2 10 = 1024, that is, the number of the last remaining person to report for the first time is 1024

Summary. 5*9-29=45-29=16 can also solve problems in daily life: there are 9 5 yuan of money, 29 yuan is spent, and 16 yuan is left.

Question 2. Hello, after the girls take the 3-seat merry-go-round, how many girls are left?

Hello, after the boys ride the 3-seater merry-go-round, how many boys are left?

The correct answer is: Hello, how many boys are left after the boy rides the 3-seater merry-go-round?

5*9-29=45-29=16 (bags) There are 16 bags left.

Can you hurry up.

Hurry up. If the school purchases basketball a, then the soccer ball has (a-8) a+a-8=24 to solve the equation shift as early as it gets: 2a=32 The two sides of the equation are divided by 2:

a=16a-8=16-8=8Answer: There are 16 basketballs purchased by the school, and 8 kickball balls.

Have you learned to solve equations?

To solve the school procurement disturbance which basketball x, then the purchase of football has (x-8) x+x-8=24 solution equation shift term: 2x=32 equation on both sides of the equation divided by chain fibrillation 2 to obtain: x=16x-8=16-8=8 answer slow call code:

The school procured 16 basketballs and 8 soccer balls.

If there are 23 balls in the basketball position, 23-8 = 1523 + 15>24 if there are 22 hidden balls in the basketball, 22-8 = 1422 + 14 24 if there are 21 balls in the basketball, 21-8 = 1321 + 13>24....If there are 17 basketballs, football 17-8 = 917 + 9 = 25>24 if there are 16 basketball players, football 16-8 = 816 + 8 = 24 basketball 15 pieces, football 15-8 = 715 + 7<24 ...

The above is the analysis process.

The school procured 8 soccer and 16 basketballs, respectively.

5*9-29=45-29=16 can also solve problems in daily life: there are 9 5 yuan of money, 29 yuan is spent, and 16 yuan is left.

Summary. Hello math problems.

Article 8 mentions the process <>

The root number of minus thirds is two, where did it come from?

Dear, is it minus two-thirds the root number two?

Yes. Because the square of the sin angle plus the square of the cos angle is equal to 1.

So cos is equal to the square of the minus sin under the root number.

Hello! Here's how to solve it:

1. The length of the inner edge of the innermost runway = the length of the straight road part + the length of the curve part and the length of the curve part = 2

The length of the straight section = the length of the inner edge of the innermost runway - the length of the curve section = A: The length of the straight part of the runway is a total of meters.

2. The area of the sports field.

Answer: The area of this sports field is square meters (the area within the outermost runway)3 I have already counted it for you, just spend it yourself.

Let the chick x, the hen y, and the rooster z be the proposed equation:

x+y+z=100

5x+50y+100z=1000

Simplified from 5x+50y+100z=1000, x+10y+20z=200 and subtracted from equation 1 to get 9y+19z=100

Since x, y, and z are all integers, you can make up y=9, z=1 and find x=90

So buy 90 chicks, 9 hens, and 1 rooster.

Buy a hundred chickens for ten dollars, one chick is one fifth, a hen is a five-cornered one, and a rooster is one dollar. All to buy.

Let x hens, y roosters, and 100-x-y chicks, and x,y be integers.

So the correct answer can be derived by calculation: 9 hens, 1 rooster, and 90 chicks.

The chemical composition is x+y+z=100

5x+50y+100z=1000

It is easy to know that x is a multiple of ten, x+y+z=100, then x=10

To reach 100, only start with 90, and when x=90, y=9z=1 happens to be true.

Ha ha... Get the results!

Let a, b, c

for the number of small, male and female hens.

5a+50b+100c=

Because it costs a total of 10 yuan, 1000 points).

a+b+c=100

A total of 100 chickens).

Then just try it, and the chick will definitely be able to go up from a=95

Bring it in, try a few more times until a, b, and c meet those two formulas.