1 If x 2 is to the m 1 power, y 3 4 is to the m power, and y is expressed by an algebraic expression

x=2 (m+1)=2 m2=4 m2 2 so x2=4 m4

So y=3+4 m=3+x 2 4

a=log2(3) b=log2(5) c=log2(30) because log2(30)=log2(5)+log2(6)=log2(5)+log2(3)+log2(2).

So c=a+b+1

x+y+z)(x-y-z)=-(x+y+z)(y+z-x)=-[(y+z)^2-x^2]=x^2-(y+z)^2

a+b+c)(a+b-c)=(a+b)^2-c^2

a(a-1)-(a²-b)=2

a^2-a-a^2+b=2

b-a=2 algebraic formula ab-(a +b 2)=(2ab-a 2-b 2) 2=-(a-b) 2 2=-2

The algebraic formula x +y +4x-6y+14=x 2+4x+4+y 2-6y+9+1=(x+2) 2+(y-3) 2+1>0

So no matter what value x or y takes, the value of the algebraic formula x +y + 4x-6y + 14 is always positive.

You can ask for it.

4 to the m power = 2 to the 2m power.

x=(2 to the mth power) + 1 so 2 to the 2m power = (x-1) to the square of the flat Huhong ridge.

So y = 3 + (m power of 4) = 3 + (x-1) pants permeable squared.

It is known that x = 1 + 2 to the m power, and y = 1-4 to the m power is expressed by the algebraic expression of x

x=2^m+1

2^m=x-1

Both sides of the square old stove this.

2^m)^2=(x-1)^2

4^m=(x-1)^2

y=3+4^m

4^m=y-3

So the squire argues y-3=(x-1) 2

y=(x-1)^2+3

i.e. y=x 2-2x+4

x=2 to the power of m+1 can become 2 to the 2m power = (x's square) 4 y=3+(4 to the m's power) can become 2 to the 2m power=y-3 so (x's square) talk about 4=y-3 i.e.: y=(x's square) 4+3

x=2*2^m

2^m=x/2

y=3+(2^m)²

3+(x/2)²

3+x²/4

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Hello: Provide you with precise answers.

x=2 (m+1) shows that 2 m=x 2, and y=3+4 m

3+(2^m)^2

3+(x/2)^2

3+x^2/4

Thank you, if you don't understand, you can ask.

x = 2 to the power of m + 1.

x=2 to the power of m2

M power of 2 = x 2

y = 3 + 4 to the m power = 3 + (2 to the m power) = 3 + (x 2) = 3 + x 4

Solution: x = 2 to the power of m + 1 can become 2 to the 2m power = (x squared) 4y = 3 + (4 to the m power) can become 2 to the 2m power = y-3 so (x squared) 4 = y-3

i.e.: y=(x) 4+3

x = 2 to the power of m + 1.

then x=2 to the m power of 2.

So 2 to the power of m = x 2

y=3+4 to the power of m=3+2 to the power of 2m=3+(x 2) =3+x 4, so y=3+x4