Finding a Solution to an Engineering Problem How to calculate this engineering problem?

Team A can complete 1 123 days a day Team A completes 3 1 12 1 1 4 every day

Team A does 3 days and then Team B does 2 days, which is exactly half done.

So team B does 2 days to complete 1 2-1 4 1 4

So Team B completes 1 4 2 1 8 every day

Teams A and B cooperate to complete 1 12 + 1 8 5 24 every day, and after doing it, it is found that the two periods of time are equal.

So share 1 (1 8 + 5 24) 2 6 days.

A does it alone, does 1 12 a day, B does it alone, does 1 9 a day, and A does it for x days first.

1/12)x+(1/9)*(10-x)=11/12)x+10/9-(1/9)x=1

1/9=(1/9-1/12)x

1/9=(1/36)x

4=xx=4

A did it for 4 days.

The ergonomics of B are:

Set up for x days.

1/12+1/8）*x/2+1/8*x/2=15/48*x+1/16*x=1

It took 6 days to solve x=6 answers.

Set two periods of time for x days.

1/12+1/8)x+1/8x=1

x=3 for 3+3=6 days.

Shared 8 days.

Just figure out how many days Team B will use.

It's simple.

Team A can complete it in 12 days alone.

Team A completes 1 12 per day

3 days to complete 3 1 12 1 4

After team A does 3 days, team B does 2 days, which is exactly half done.

So team B does 2 days to complete 1 slip and 2-1 4 1 4, so team B completes 1 4 2 1 8 every day

The two teams A and B are cautious and cautious every day, and after completing 1 12 + 1 8 5 24 every day, they find that the two periods of time are equal.

So. Shared 1 (1 8+5 24) 2 6 days.

Assuming that all 10 days are dry, the project should be completed.

1/9 10 10/9

More than it actually is.

1 out of 9 1 out of 9 1 out of 9 1 out of 1 9 out of 1 9 1 out of 1 9 1 1 1 1

B completes the work more every day than A.

1/9 1/12 1/36

A worked. 1/9 1/36 4 days.

B worked. 10 4 wheels sedan orange 6 days.

He's right, right answer, you're wrong, I feel like you're just thinking too much, what, B, according to A's standards... Don't think too much about it, just let them do it.

Suppose the entire engineering quantity is 1

A can dry 1 20= per day

B can dry 1 10 = per day

If A and B take turns to do it, they will work together every two days.

It will be completed in 12 days.

There is still 1 day left, and the first is done.

For the rest, B dry for half a day.

The total number of days is 12+1+.

When the master completed 40 of his tasks, the apprentice processed 240. Then when the master completes 100%, the apprentice has processed 240*100% 40%=600 At this time, the apprentice is still 20 short of completion, that is to say, the apprentice is 80% complete, then the apprentice has completed a total of 600 80%=750 This batch of parts has 750*2=1500.

This batch of parts is 1500 pieces, and this problem can be calculated without equations, with proportions. First, calculate the velocity ratio of the teacher:apprentice, and then the root velocity ratio can be calculated.

The speed ratio of master to apprentice is 1

When the master completes 40%, the apprentice completes 40%.

240 32% = 750 * 2 = 1500 pcs.

It's a very simple question.

Solution: 1-1 5-1 2) (1 5-1 7)=21 4 hours).

A: One more hour.

Set the apprentice to do x in an hour, and the master to do y in an hour. There are 30x parts in total.

The two of them processed 1 of the 3 parts of this batch in 4 hours. Rule.

4（x+y）=1/3*30x.3x=2y, and 2 3*30x=20x remains

The rest of the master does it, that is, 20x y = 20x (3x 2) = 40 3 hours.

It takes 30 hours for the apprentice to do it alone: the apprentice's efficiency is 1 30 of the total amount of completion per hour, and the master-apprentice cooperates for 4 hours to process 1 3 of the batch of parts: the master-apprentice cooperation processes 1 3 4 = 1 12,; The master completes 1 12-1 30 = 1 20 per hour

The rest is done by the master alone: the remaining 1-1 3=2 3;The master does 2 3 1 20 = 40 3 = 13 hours and 20 minutes.

Integer: (1-1 3) (1 3 4-1 30) = 13 hours and 20 minutes Answer: omitted.

Suppose that a batch of workpieces is "1" and the processing speed of the master is x, then 4(x+1 30)=1 3

The solution is x=1 20

Solution: Assuming that the specified date is x days, then:

A ergonomics: 1 x

B efficiency: 1 (x+4).

According to the title, it gets: 3 x+x (x+4)=1

3(x+4)+x^2=x(x+4)

3x+12+x^2=x^2+4x

x = 12, i.e. the specified date is 12 days.