Rush Physics Topics Buoyancy

1.Mines float in water, so the buoyancy is not calculated according to their volume, but according to their mass, so the buoyancy experienced when stationary in the water is equal to its gravity, which is 4500N

But the question is... How could a mine be so heavy?! I thought it should be 450g, so the buoyancy was there.

2.The stone is subjected to a gravity of 26000N, and the rope can withstand 20000N, so the buoyancy must be greater than 6000N

When the stone is completely submerged in water, it is subjected to a buoyancy of 10,000n (1m of water is discharged, and the mass is 1t), so it is able to lift at this time, and when the stone is exposed to more than two-fifths of its volume, the rope will break.

Agree with the upstairs, if it is not stated that the stone is a regular shape, the area cannot be calculated, the problem should be the volume).

So when the volume of the stone outcrops reaches cubic meters, the rope will break

2.Stone mass m=2600kg gravity g=mg=26000n, so when the stone buoyancy is less than 6000n, the steel rope will be broken.

v=6000/10000m^3=

Is there a mistake in the question? It should be calculated by the area of the volume, which cannot be calculated).

Copper ball gravity g = (5 6) m ball g = (5 6) copper vg = 75n.

If the hollow part is copper, then the part is subject to gravity g empty = (1 6) copper vg = 15n, then m empty = g empty g = .

Therefore, v empty = m empty copper = 1 6dm 3=. That is, the volume of the hollow is cubic decimeters.

1 Buoyancy = density x volume x g

Buoyancy = 2 Buoyancy = 1x10 3x300x10 = 3x10 6n mass = volume x density.

Fuel Mass = Buoyancy = Gravity = 3x10 6-8x10 4x10 = Volume = Buoyancy (density xg)=

Because it is submerged in water, there are 2 ways to compare the uplifting, sinking, or suspension of an object1, comparing the density of the object with the density of water, if the density of the object is greater than the density of water, the object sinks, and if the density of the object is less than the density of water, the object floats. The density of the object = m v = 1kg ( kg m 3 is greater than the density of water, so it is sinking.

2. Compare the gravity of the object and the buoyancy of the object, if the buoyancy is less than the gravity, it will sink, and if the buoyancy is greater than the gravity, it will float, which is equivalent to levitation. The buoyancy experienced by the object = less than the gravitational force of the object, so the object is sinking.

The mass of the object m = g g = 1kg, the density of the object = m v = 1kg (multiplied by 10 3kg m 3, greater than the density of water, so it sinks.

First of all, to correct one of the mistakes in the question, B should not be suspended in the "liquid surface". Suspension means that the object is submerged in a liquid but does not touch the container, so B is suspended in "liquid (water)".

According to Archimedes' law, the buoyant force experienced by an object in a liquid should be equal to the weight of the water it dissipates. The boiling water of the first row is smaller in size, less in weight, and of course less buoyant. Select "<".

Answer choice (<).

The reason is that A floats on the surface of the liquid, so the density of A is less than the density of the liquid;

B is suspended in the liquid surface, so the density of B is equal to the density of the liquid;

And B is all submerged in the liquid, the volume of B is large, by the formula, buoyancy = density * volume * g

It can be seen that B has a large buoyant.

Buoyancy: 10-8=2n

Spring dynamometer: 10-2 2 = 9n

Buoyancy2 (f=.)