Math A B then A B I think it s right

Obviously not right, because a = b = (a) = (b).

So: 1. When a=0=b, then -a=-b is right.

2. When a≠0, there are two kinds of a=b, then -a=-b; a=-b then -a=b

Let's put it this way, from a = b, we can know that the value of a has two positives and a negative, and b is the same.

From -a=-b, the term is shifted to get a=b, and this is actually the conclusion of this problem, as long as it is shown that a is not equal to b, this problem can be proved wrong.

Combined with the value of a = b, the algebra is very clear, assuming a = 1, b = -1, at this point a = b is right, but -a = -b is wrong (-a = -1, -b = 1). I guess that's understandable.

It should be: a = b launch |a|=|b|Re-launch -|a|=-|b|You see, let's say a=2, b=-2

Then a = (2) =4 and b = (-2) =4 push out a = b a=-(2)=-2

b=-(-2)=2 (negative negative gets positive).

Launched-a≠-b.

a=b or -a=b or a=-b can make a =b, so the proposition is false.

This is a necessary but not sufficient proposition. a, b can be inverse numbers.

Not necessarily, unless additional condition a=b.

I didn't say anything, you guys didn't remember anything.

It is known that a b 1, that is, b 1 a a, that is hidden, algebraic whispering:

f(a,b) a2a2abab

A 2-2a (1-sales hall a) a (1-a).

a 2-2a 2a 2-1 a

3a 2 a a 1.

When a 1 6, the minimum value is obtained.

f(a,b)min 3 36-1 6-1

A 13-12.

Solution: A and b are both positive numbers.

1、∵(a-b)²≥0

a²+b²≥2ab

√［a²+b²）/2］=√［（a²+b²+a²+b²）/4］≥√a²+b²+2ab）/4］=√(a+b)²=a+b

i.e.: a + b ) 2 a + b

2.∵（a-√b）²≥0

a+b≥2√ab

（a+b）/2≥√ab

A+b 2 ab

2/（1/a+1/b）=2ab/（a+b）≤2ab/2√ab=√ab

i.e.: ab 2 (1 a+1 b).

The synthesis yields: a +b ) 2 (a+b) 2 ab 2 (1 a+1 b) (a,b are both positive).

The first equal sign is correct, the squared difference formula.

Hope. <>

OK. This is a temporary calculation of the problem, and it can be calculated as it is necessary - however, it cannot be used on any other problem than the one.

This is not true, a -b = b, then a = 2b, so a = root number 2b is true.

a²-b²=(a+b)(a-b)

That's it. The right one is gone.

The appearance of your right-hand b is wrong.

As long as it is calculated correctly, the result is the same.

a+b=10

a²+2ab+b²=100

a²+b²=4

2ab=96

ab=48a-b) =a +b -2ab=4-2 48=-92 Is this a bit problematic? Please check both of your data.

This formula is the formula for the square difference of the cherry blossoms.

According to the form of the given calculation, it can be calculated as follows:

2+3) Qin Sou Cong (6-4).

Solution: This is the basic application of the perfect square formula.

a²+b² =a+b)²-2ab

a+b=4

(a+b) =7,a +2ab+b =7(1)(a-b) =3 a -2ab+b =3(2)(1)(2) add 2(a +b) = 10, so a +b = 5(1)(2) subtract to get 4ab=4 so ab=1