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First, you can't ride a bicycle on a high speed, so it is recommended that you take a large road. You can ask how to go on the large road at the airport, and the large road is Shuangliu, Xinjin, Pengshan, Meishan, Jiajiang, and the branch road to Jiajiang County, because the large road is to Leshan, and your destination is Emei. At this time, ask the locals how they got to Emei.
It is recommended that you eat in Meishan, and you have basically walked halfway to Meishan, and there is a slight slope after Meishan.
According to the usual situation, the whole journey is about 120 kilometers, it is recommended that you start early, be sure to arrive in Emei before dark, if you are a student, you must bring a student ID, and the ticket will be discounted.
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Go buy the latest Sichuan traffic atlas How can I express it clearly to you on this?
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You're like my boyfriend, you always want to ride, and he still wants to ride to Siguniang Mountain, it's so dangerous
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Go early and come back early to stay safe.
PS: I'm also at the airport.
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Go to Qingcheng Mountain, I strongly urge you to pay attention to you as a person!! Not God!!
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Alas, you go to a larger bookstore to find a Sichuan traffic atlas to buy it, (people are classified, according to the classification to find it, it is easy to find) how to go. As long as you have a map in hand, you are not afraid of getting lost.
My classmate does travel **, if you come to our school, you can let him lend you the information to copy, so that there is any place to have fun.
I think that's the best way, I'm 51 also going out on a bike with my classmates, and we're in Hongguang Town. Hehe.
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You're crazy, ride a bike, and when you get to the next step without dying of pain, you can call 114 for the convenience of the people** to ask the route, they are very detailed, and buy a map of Chengdu and Leshan to see for yourself.
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It's crazy to ride a bike.
I know that to go to Mount Emei, you can go to the new south gate to take a car.
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f(x)=sin squared + sinxcosx=(1-cos2x) 2+1 2sin2x=1 2+1 2(sin2x-cos2x)=1 2+ 2 2sin(2x-4).
Because -1 sin(2x-4) 1
So the maximum value of f(x) is 1 2 + 2 2
In this case, sin(2x-4)=1, then 2x-4=2k + 2
Therefore x=k +3 8
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The maximum value is taken when x = 45 degrees.
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f(x)=(1-cos2x)/2+1/2*sin2x=1/2*(sin2x-cos2x)+1/2=√2/2(√2/2*sinx-√2/2cos2x)+1/2=√2/2sin(2x-π/4)+1/2
So sin(2x-4)=1 is maximum.
2x-π/4=2kπ+π/2
So x=k +3 8, f(x) max=(2+1) 2
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f=(1 2)(1-cos(2x)) 1 2)sin(2x)=(1 2)(1+2 *sin(2x+45 degrees))f when the maximum value of sin(2x+45 degrees)=1, that is, f=(1 2)(1+2, when x=degrees+-180n degrees, n=0,1,2,..
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f(x)=(1-cos2x)/2+sin2x/2=1/2+(sin2x-cos2x)/2=1/2+2?(sin2xcos45°-cos2xsin45°)/2=1/2+2?sin(2x-45°)/2
When sin(2x-45°)=1, the maximum value (1+2?) is taken)/2
At this time, 2x-4=2k + 2,k n, i.e. x=k +3 4
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= [(root number 5 + root number 6) + root number 7] [(root number 5 + root number 6) - root number 7]*[root number 5 - root number 6) + root number 7]* - root number 5 - root number 6) - root number 7].
[4+2 [(root number 5 * root number 6)] [4-2 [(root number 5 * root number 6)].
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The answer is 1, this is a regular question of mine, take a look.
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<> so anxious, I'm making pure liquid for you, why didn't you have a rotten orange response from the hungry pants?
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