Is the ratio of the centripetal acceleration of the planetary motion related to the mass of the plan

There is a quality relationship between the pork belly of that house.

Gravitational acceleration in celestial motion.

g=gm/（r+h）2

h is the height from the star.

r is the radius of the star.

m is the mass of the star.

It is the key to making celestial bodies move around the stars.

Centripetal acceleration in the motion of celestial bodies.

a=v2/r=w2r

It is the key to making the object move in a (approximate) circular motion.

Gravitational acceleration is the above total acceleration is evaluated and directionized by vector synthesis.

Is gravitational acceleration the same as centripetal acceleration in celestial motion? - Not exactly the same.

When we study objects on the surface of the earth, we often talk about gravitational acceleration. It is a part of the gravitational force. Because objects on the surface of the earth are also rotating with the earth, one part of the gravitational force provides centripetal acceleration for it, and the other part of the acceleration generated by gravity is called gravitational acceleration.

And when leaving the Earth, like a satellite, only the acceleration caused by the "gravitational pull", that is, the centripetal acceleration, is discussed. Gravitational acceleration is no longer discussed because at this point the gravitational force is all used to provide centripetal acceleration to the satellite.

Gravitational acceleration in the motion of a celestial body g=gm (r+h)2 h is the height from the star r is the radius of the star m is the mass of the star.

It is the key to making celestial bodies move around the stars.

The centripetal acceleration in the motion of a celestial body a=v2 r=w2r is the key to making the object move in a (approximate) circular motion, and the gravitational acceleration is the total acceleration above that is evaluated and oriented by vector synthesis.

1. The gravitational acceleration of the eight planets is: Mercury: gravitational acceleration meter square second; Venus:

acceleration due to gravity in meters square seconds; Earth: gravitational acceleration meters square seconds; Mars: gravitational acceleration meters square seconds; Jupiter:

acceleration due to gravity in meters square seconds; Saturn: acceleration due to gravity in meters square seconds; Uranus: gravitational acceleration meters square seconds; Neptune:

acceleration due to gravity in meters square seconds;

2. The eight planets are the eight major planets of the solar system, according to the distance from the sun from near to far, they are Mercury ( ) Venus ( ) Earth ( ) Mars ( ) Jupiter ( ) Saturn ( ) Uranus ( ) Neptune ( ) Most of the eight planets have the same rotation direction as the rotation direction. There are only two exceptions: Venus and Uranus.

Venus rotates in the opposite direction to its revolution.

3. Definition of planets: first, celestial bodies that must orbit stars; Second, the mass is large enough to rely on its own gravity to make the celestial body spherical; The third is that there should be no other objects near its orbit. According to this division, there are only eight planets in the solar system: water, metal, earth, fire, wood, and earth, plus Uranus and Neptune.

In contrast to the concept of nine planets mentioned before 2006, Pluto was classified as a dwarf planet and removed from the list of nine planets in the solar system in Resolution 5 adopted at the 26th session of the International Astronomical Union, held in Prague on 24 August 2006. The mass is large enough to rely on its own gravitational pull to make the celestial body appear spherical.

4. Celestial bodies that also have sufficient mass and are spherical in shape, but cannot clear other objects in the vicinity of their orbits are called "dwarf planets", and Pluto just fits this definition and has been recognized as a "dwarf planet" by the International Astronomical Union. So Pluto is classified as a dwarf planet. Since then, there have been only eight planets in the solar system.

The gravitational acceleration and other basic parameters of the eight planets are as follows:

Mercury: mass kilograms, radius kilometers, gravitational acceleration meters square seconds, rotation period hours;

Venus: mass kilograms, radius kilometers, gravitational acceleration meters square seconds, rotation period hours;

Earth: mass kilograms, radius kilometers, gravitational acceleration meters square seconds, rotation period hours;

Mars: mass kilograms, radius 3397 km, gravitational acceleration meters square seconds, rotation period hours;

Jupiter: mass kilograms, radius 71,492 km, acceleration due to gravity in meters square seconds, rotation period hours;

Saturn: mass kilograms, radius 60,268 kilometers, acceleration due to gravity in meters square seconds, rotation period hours;

Uranus: mass kilograms, radius 25,559 kilometers, acceleration due to gravity in meters square seconds, rotation period hours;

Neptune: mass kilogram, radius 24,764 kilometers, acceleration due to gravity in meters square seconds, rotation period hours.

The eight planets are the eight large planets of the solar system, and they are Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune in descending order from near to far. Most of the eight planets also rotate in the same direction as their orbit. There are only two exceptions: Venus and Uranus.

Venus rotates in the opposite direction to its revolution.

That's the circled column.

I'm sorry, I didn't see it so long ago.

There are eight planets in the solar system, and the gravitational acceleration on Earth is about, but on other planets, it is very different, Mercury has a gravitational acceleration of g; The acceleration due to gravity of Venus is ; The gravitational acceleration of Mars is ; Jupiter's gravitational acceleration is; The gravitational acceleration of Saturn is; The gravitational acceleration of Uranus is; Neptune's acceleration due to gravity is.

Summary. Planetary motion in the same orbit is generally not centrifugal force.

Planetary motion in the same orbit is generally not centrifugal force.

Centrifugal force is an imaginary force that has been misunderstood for a long time, i.e., an inertial force, because there is no force object, it does not conform to Newton's third law.

When you hold the magnet and rotate quickly, the small iron will run around the magnet in a circle, then the small iron will produce centrifugal force outward, the faster the rotation, the greater the centrifugal force, if the rope is suddenly broken, the small iron will fly far away, because the centrifugal force at this time has far exceeded the gravitational force of the magnet. If you use a shorter rope to tie a small piece of iron, and you rotate the magnet slowly, just the small piece of iron can rotate, then the centrifugal force generated is much smaller, the gravitational force of the magnet is greater than the centrifugal force of the small piece of iron, then if the rope is broken, the small piece of iron will be attracted by the magnet. This kind of gravitational circumferential operation is based on the premise of the rope to be successful, without the rope, the small iron is either far away or sucked in, and it is impossible to produce circular motion.

Therefore, it is impossible to produce a circular movement without gravitational force alone, let alone centrifugal force.

Is there a centrifugal force in the planetary orbital motion?

The centrifugal force is obtained by rotation.

Is there no centrifugal force in orbit change motion?

The orbital movement may be large ** or impact, and the centrifugal force generally comes from the interior of the star.

In the movement of the wild belt star around the sun, the speed is the same as the ridge of the reed.

a.That's right. b.Mistake.

Correct answer: B

The less the centripetal acceleration. The gravitational force of which bridge star is moving in a uniform circular motion around the central tremor code center object provides all the centripetal force provided by its gravitational force, i.e., a=gm d 2

A is its centripetal acceleration, m is the mass of the central celestial body, and d is the distance between the two stars From this, it can be seen that the centripetal acceleration of a star is inversely proportional to its radius of motion.

The greater the radius of motion of the star, the smaller the centripetal acceleration.

By gmm r 2 = ma=m 2r = mv 2 ra=gm r 2

(gm/r^3)^1/2

v=(gm/r)^1/2

The closer the eight planets of the solar system are to the Sun, the greater the centripetal acceleration.

The smaller the angular velocity.

The greater the linear velocity.