C String Conversion Problem, C How to Convert Integer to Character Type?

Use the ITOA function.

Prototype: extern char *itoa(int i);

#include<

#include<

int main()

int a=125;

char b[50];

printf("%s",itoa(a,b,10));Convert 125 in decimal 10 to characters and output it.

return 0;

First of all, the char character should be output with %c, %d is the output of integer numbers, but since the characters and integers are compatible, the char character can also be output with %d, although the output result is not the desired result ......

Since all symbols are stored in ASCII code corresponding to 0 255, it is necessary to convert c=130 to binary, which is the state of c=130 in memory.

130 to binary string is"1000

0010"However, the data in the computer is stored in complements, so this"10000010"It's a complement, then the complement is 1000

What is the number of 0010?

So the key to outputting -126 is to use %d.

d", when out, because "1000."

0010" is 8-bit, which should obviously be short

int, so the compiler automatically interprets it as"hd", (note that the highest bit is 1) so it is interpreted as -126

Not of the same type, character'a'It only takes up one byte, and the string is followed by a closing character'\0', therefore"a"The actual storage space station is two bytes, for.

It's different.

characters'a'In C Ann ASCII storage.

Strings"a"The A in it is replaced by a string, eg "efw34" or something, which is a string.

If you put the string t="efw34"; This defines the output function to write printf("%s",t);It's equivalent to printf( "efw34");

Not of the same type, in memory 'a' occupies one byte and 'a' occupies two bytes ('a''\0')

It is different that a single quotation mark encloses a character, and a double quotation mark encloses a string, and the string will be followed by a '0' as the ending flag of the string, and '0' is also a character.