Find the mole equation calculation of chemistry, how to calculate the mole applied to the chemical e

The chemical equation can represent the ratio of the quantity to the mass of the substance between the reactant and the product.

For example: 2h + o = (ignition) = 2h o

The ratio of the coefficients is 2 1 2

The ratio of the number of particles is 2 1 2

The ratio of the amount of matter is 2 1 2

The mass ratio is 4 32 36

From the above analysis, it can be seen that the ratio of the coefficients of each substance in the chemical equation is the ratio of the amount of substances between them. Using this principle, it is possible to calculate the quantity of each substance according to the chemical equation.

One-twelfth of the mass of a carbon atom (c) is the international benchmark for relative atomic mass (formula). It is known that 12g c contains a carbon atom. This number is called the Avogadro number, so it can also be said that the amount of matter containing the basic particles of the Avogadero number is 1mol.

For example, 1mol of oxygen molecule contains an oxygen molecule, and its mass is hydrogen ion containing hydrogen ion, and its mass is. In chemical calculations, approximate values are taken.

The carbon dioxide is , which contains oxygen atoms, so ozone is made up of these oxygen atoms.

The neutralization of 24g of sodium hydroxide is used, and the hydroxide group is neutralized, which means that the acid is, the molar mass of the acid is, and the relative atomic mass of a is very good, which is 32

The unit of quantity of matter – mole.

According to Moore's definition, the number of carbon atoms contained in 12 g 12C is 1 mol, that is, the unit of mole is based on the number of atoms contained in 12 g 12C as the standard to measure the number of basic units contained in the substance.

Concepts such as the quantity of a substance are used in the calculation of chemical equations.

The ratio of the stoichiometric number of each substance in the chemical equation = = the ratio of the number of particles of the corresponding substance = = the ratio of the amount of the substance of each substance (if it is a gas, it is equal to the ratio of the corresponding volume).

Discuss] According to the chemical equation, what is the volume of O2 under the standard condition for a complete reaction of 2molH2? What is the quality of the H2O generated?

2h2(g)+o2(g)=2h2o(l)

2mol 36g

2. The quantity of the substance, the molar volume of the gas, and the concentration of the substance are comprehensively used in the calculation of chemical equations.

Summary] Exercise 1: 400ml of NaOH solution of a certain concentration happens to be in the standard condition) to complete the reaction, calculate:

1) The amount of Naclo produced by the substance.

2) The amount and concentration of NaOH in the solution.

Intent or Explanation: Example 3 of the textbook is changed to a student exercise, and the student already has the knowledge and ability to solve Example 3 on the basis of Example 1 and Example 2, and the teacher can adjust the next teaching action through the feedback from the student practice. ）

Practice 2: Bleaching powder is made industrially by the interaction of Cl2 and lime milk. 1mol Cl2 is completely absorbed by lime milk, calculate:

1) Find the amount of Ca(OH)2 substances participating in the reaction.

2) Find the amount of Ca(clo)2 generated.

3) Find the quality of the bleaching powder to be prepared.

Exercise 3: Vitamin C, also known as ascorbic acid, has a molecular formula of C6H8O6, and each mole of vitamin C can follow 1moloh-. A sodium hydroxide solution commonly used to determine the amount of vitamin C in a tablet.

What is the mass fraction of vitamin C in a tablet where the sodium hydroxide required for a tablet is completely neutralized?

Exercise 4: Sodium peroxide can be used as an oxygen supply in submarines. There are 50 people on board a submarine, and each person consumes the standard condition per minute), find the amount of sodium peroxide required on the submarine for a day.

Exercise 5: H2 and Cl2 are used to synthesize HCl gas in industry, and then dissolve in water to produce hydrochloric acid. If the industrial production of hydrochloric acid with a mass fraction of 31% ( =, what is the volume of chlorine under the theoretical standard condition?

Summary] (1) Clear calculation basis: the ratio of the amount of substances participating in the reaction is equal to the ratio of the stoichiometric number;

2) In the comprehensive calculation, we should be good at converting other physical quantities into the quantity of matter for calculation;

3) Attention should be paid to the normalized representation of physical quantities and the normalization of the calculation process.

1.Number of moles of NH3 used = MV = 2 x (20 x 10-3) = mol 2NH3 + H2SO4 NH4)2SO4 molar ratio NH3 : H2SO4 = 2:

1 The number of moles of H2SO4 used = x (1 2) = mol The mass of H2SO4 = 2x1 + 16x4 = g The mass of H2SO4 used in mol-1 = the number of moles x the molar mass = x = g The concentration of H2SO4 used = Mass Volume = 16 x 10-3) = g DM-3 ==2Molar mass of MgSO4 = + + 16x4 = g mol-1 mol-1 molar mass of H2O = 1x2 + 16 = 18 g Mass of H2O in the mol-1 sample = 63 g Mass of MgSO4 in the sample = - 63 = g molar ratio of MgSO4 : H2O = :

63 18) = : = 1 : 7 so x = 7

1)nh3+h2o <=nh4oh 2(nh4oh)+h2so4 ==nh4)2so4+2(h2o) 2 mole ammonium water need 1 mole of h2so4 to neutralize of h2so4 used = of nh4oh used = mass of h2so4 used= g concentration= g dm^-3 2)formula mass of mgso4= thus ratio of mgso4:h2o is (

1 : 7 thus x=7

Suppose the chemical formula of compound c is $c xa yb z$, where $x, y, z$ denote the number of moles of elements c, a, and b in the compound, respectively, and satisfy $x+y+z=1$, because the sum of the molar fractions of the elements in a compound is equal to 1.

Compound C is known to be made up of elements A and B and can be obtained:

y+z=Since the chemical formula of compound c contains only the elements a, b, and c, it can be obtained:

x+y+z=1$

Therefore, the auspicious Qing $x$ in the chemical formula $c xa yb z$ is:

c_a_b_$

Therefore, the chemical formula of compound c is:

c_a_b_$

It should be n, which represents the amount of matter.

n=m m m--- mass m---molar mass.

n=number of particles na na--- Avogadro's constant.

n = volume of gas under standard conditions).

1. n = m m, n is the amount of matter (mol), m is the mass (g), m is the molar mass (shiming g mol).

2. n=n na, n is the number of particles, and na is the addreo constant.

3. n=v vm, v is the body culture of the gas (l), vm is the molar volume of the gas under certain conditions (l mol), in the standard condition, vm =

4. n=cv, c is the amount and concentration of the substance dissolved in the solution (mol l), v is the volume of the solution (l).