The equation for the reaction of vitamin C with iodine, the ionic equation for the reaction of ethan

c₆h₈o₆＋i₂→c₆h₆o₆＋2hi

The interaction of vitamin C and sodium carbonate can produce a monosodium salt, which does not undergo hydrolysis because the double bond makes lactone.

The ring becomes stable, but in a strong alkaline solution, the lactone ring can be hydrolyzed to form ketoate.

The olediel group in the molecular structure has strong reducibility, and is easily oxidized to a diketone group to become dehydroascorbic acid, which can be further hydrolyzed to form diketoguloic acid in alkaline solution or strong acidic solution and lose its activity.

c6h8o6＋i2→c6h6o6＋2hi

Ionic Equation:

C6H8O6 I2 C6H6O6 (2H) 2i) The solution changes from tan to colorless.

C6H8O6 (vitamin C, ascorbic acid) + I2 (iodine) = C6H6O6 (dehydroascorbic acid) + 2Hi (hydrogen iodide).

Iodine wine is originally a reddish-brown clear liquid, but the color fades after the reaction, so the brown color of the solution fades, and the reaction is complete.

c₆h₈o₆+i₂→c₆h₆o₆+2hi

The reaction of VC with I2 is a redox reaction. If yes, the oxidant is iodine c h o + i = c h o + (2h +) + 2i -) >

c₆h₈o₆＋i₂→c₆h₆o₆＋2hi

The interaction of vitamin C and sodium carbonate can produce a single sodium salt, which does not undergo hydrolysis because the double bond stabilizes the lactone ring, but in a strong alkali solution, the lactone ring can be hydrolyzed to form ketoate.

The olenodiol group in the molecular structure has strong reducibility, and is easily oxidized to a diketone group to become dehydroascorbic acid, which can be hydrolyzed in an alkaline solution or a strong acidic solution to form diketone gulloic acid and lose its activity.

CH3CH2OH+I2=CH3CHO+HI, CH3CHO+I2+H2O HCOOH+HCI3 (iodoform, light yellow precipitate).

Iodine + hydroxide = iodine ion + hypoiodate ion + water.

Ethanol + Periodic Acid Examples = Acetaldehyde + Iodide Ions + Water.

Acetaldehyde + Hypoiodate + Water = Triiodomethane + Formate.

Matters needing attention in the chemical reaction of ethanol and iodine: iodoform reaction is a reaction in which methyl ketone compounds or compounds that can be oxidized into methyl ketones by sodium sodium tetrahalorate of Zhaochun are reacted with chlorine, bromine and iodine under alkaline conditions to produce chloroform, bromoform and iodoform respectively.

Ethanol can be oxidized by iodoform and contains the CH3CO- group, which can undergo an iodoform reaction. However, acetic acid becomes CH3COO- under alkaline conditions, and the oxygen anion is conjugated with the carbonyl group, which reduces the positivity of the carbonyl group, so the activity of -h is reduced, and the iodoform reaction cannot occur.