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Anonymous users2024-02-081.The number of eggs must be a common multiple of 7 and 9.
2.The number of eggs must be an odd number.
3.The number of eggs must be 1 or 6
So. Pushable by 2 and 3.
The mantissa of the number of eggs is 1
At the same time, it can be inferred from the 8 and 8 more than one in the question.
The number of eggs can be expressed as 40x+1
It can be seen from 1. 40x+1＝63y
Then the mantissa of y is 7
When y 7 is 63y 441
Meet the conditions of 40x+1.
At the same time, it can be inferred.
When y satisfies the condition of 40z+7, the condition is satisfied.
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Anonymous users2024-02-07Let n be a non-negative integer.
Just after taking it, the note is divisible, because the least common multiple is 63, so this number can be 63n.
The remaining 1 means that it is divided by the remaining 1, because the least common multiple is 8, so (63n) is divided by 8 and the remaining 1, n is divided by 8 and the remaining 7, and the minimum value of n is 7, so the minimum value of 63n is 441, and because the least common multiple of 8 and 63 is 504, so this number can be (441+504n).
6 leftover 3, indicating divided by 6 remainder 3, that is, divided by 2 remainder 1, the condition is repeated with the above.
5 is left with 4, which means divided by 5 and 4, so (441+504n) divided by 5 and 4, n is the minimum is 2, so (441+504n) the minimum value is 1449, and because the least common multiple of 5 and 504 is 2520, this number can be (1449+2520n).
The minimum number of eggs is 1449, and every additional 2520 after that can also meet the requirements. Thank you!
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Anonymous users2024-02-06A basket of eggs:
Take them one by one, just finished.
2 2 take, 1 left.
Take 3 of 3 and take it just over.
4 4 take, 1 left.
5 5 take, 1 left.
6 6 take, 3 left.
Take 7 7 and take it just right.
8 8 take, 1 left.
Take 9 of 9 and take it just over.
Answer: 441.
Solution: According to 3 3 takes, 7 7 takes, 9 9 takes, just after taking it, it can be seen that the total number of eggs is a multiple of 63.
Because 2 of 2 are taken, and 1 is left, the total number of eggs is an odd number.
Because 5 of 5 are taken, and 1 is left, the single digit of the total number of eggs is 1.
3*7 21,63 is 7 times that.
So this basket of eggs is 441 pcs.
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Anonymous users2024-02-05Looking for answers ? A basket of eggs:
Take them one by one, just finished.
Take 2 by 2 and take it just over.
Take 3 of 3 and take it just over.
4 4 take, 2 left.
5 5 take, 4 left.
Take 6 of 6 and take it just over.
7 7 take, 5 left.
8 8 take, 2 left.
Take 9 of 9 and take it just over.
Q: How many eggs are in the basket?
1 1 is just finished, 3 3 is just finished, 7 7 is just finished, 9 9 is just finished, and the number of eggs in the box is a multiple of 4*9=63.
2 2 take 1 left, 5 5 take 1 left, and the single digit is 1.
So find 37 ...... from the following numbers
So the minimum number is 441
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