A steel mill plans to double its steel output in two years, looking for an average percentage of ann

The answer upstairs is good, simple and straightforward!

Dogtail mink, explain!

First of all, the problem is that after 2 years, the output will be doubled, and the goal is to find the annual growth.

Let the annual growth percentage be x, and the current output will be a

Now: A Year 2: A (1+x) ......First-year production multiplied by growth rate plus first-year production].

Year 3: a(1+x)*(1+x)......The second year's production multiplied by the growth rate plus the first year's production].

From the meaning of the title, we know that the output in the third year is twice that of the current one, that is, 2a, and the equation a(1+x)(1+x)=2a

i.e. (1+x) 2=2

Solution x=i.e.

This is a type of question, and this question is simple and can be analyzed like this; If you ask about doubling in 10 years, such an analysis is unrealistic.

To summarize the problem solving rule: (1+x) n=t to find x

where denotes the power of the year, t is the multiple, n and t are the known numbers, and the unknown number x is found

In addition, you have to figure out the meaning of doubling.

Multiplying a few times means multiplying by 2 several times.

For example, 5 is tripled, which means 5*(2*2*2) 40

Multiplying several means multiplying by a few

For example, 5 is tripled, which means 5 3 = 15

If the output in January is x, then the output of Liang Jing in the second socks is slag x (1 + 20%), and the output in March is x (1 + 20%) (1 + 20%)

Solution x(1+

Solution x=5000

That is, to be cautious, the production in January is 5000

Set up a month of sail chaos and hunger steel production of x tons.

x*(1+20)^2=7200

x=5000

The steel production in the month of the return was 5,000 tons.

Let the average monthly growth rate of each Weixing be x;

5000﹙1+x﹚²＝7200

1+x refers to the sedan up.

1+x=x=sedan chair.

Production in February 5000 1+20 6000

Suppose the production in 2004 is 500, with an annual growth rate of x500*(1+21%)=500*(1+x) to the power of 2.

Solution: x=10%.

Let the growth rate be x

So. 5000 (1+x) liquid return = 7000

1+x）²=

1+x=x=x=

If you don't understand, you can ask.

If the buried cover helps, remember, thank you.

Set up to double the annual output of the loose culture wide x year.

a* (medium fibrillation 1+10%) x 2a

1+10%) x Bright 2

The production of the X 8 has doubled in 8 years.