What is the specification of a 380V2 5kw motor, which needs to be matched with the empty open wire?

A motor needs to be equipped with a 16A empty open square power cord.

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With the wire, the air switch 16A can be.

5kw three-phase motor selects wires.

The rated current of the three-phase motor is i=p

If it is in close proximity (within a few tens of meters), copper wires are 4 square millimeters, and aluminum wires are 4 square millimeters.

If it is a long distance (more than 100 meters), the copper wire is 6 square millimeters, and the aluminum wire is 10 square millimeters.

If it is between long distance and short distance, copper wire is 4 square millimeters and aluminum wire is 6 square millimeters.

For the sake of insurance, the copper wire is selected to be 5A per square meter, and the aluminum wire is selected to withstand 275A per square of cable (copper wire). The 55 square cable (aluminum wire) can withstand a cable divided by 220V (voltage value) and 380V (voltage value). It can be seen that the 60kW 380V motor requires 55 square cables (power supply voltage 220V) or 32 square cables (state power supply voltage 380V).

For aluminum wire, you should choose 110 square (220V supply voltage) or 65 square (380V supply voltage).

The three-phase motor can be opened with multiple currents, and the no-load current should be four or five amperes. The full-load current is about 14 15 amperes.

Motor type (Y4001-4), rated power (400kW), rated voltage (380V), rated frequency (50Hz), synchronous speed (1500R min), installation method (IMB3), protection level (IP23), cooling method (IC01), insulation grade (B), environmental conditions (altitude 1000m, ambient temperature 40).

Now there is an output power, how big of a line does a 380v motor need and how big of an empty opening? What formula is used to calculate it?

Kiss! Hello! We're happy to answer for you!

This problem needs to be calculated using Ohm's law and the power formula. Ohm's law is expressed as: Current (i) = voltage (v) Resistance (r) The power formula is expressed as:

Power (p) = Voltage (V) x Current (i) We can solve this problem according to these two formulas. First of all, according to the power formula, we can calculate the magnitude of the current: = 380v x i i = 380v Therefore, we need a wire with a rated current greater than or equal to.

Depending on the standard of wire current load capacity, we can choose between 16A or 20A wires. Secondly, we need to choose an empty opener. The air opener is an important component used to protect the circuit, and its rated current needs to be greater than or equal to the current of the motor.

In this example, we need to select an air opener with a rated current greater than or equal to. Usually to be on the safe side, we will choose an air opener that is slightly larger than the required rated current, such as a 16A or 20A air opener. So, the answer is:

You need to choose a wire with a current rating of 16A or 20A, and an air opener with a current rating of 16A or 20A. Note: In the actual circuit layout, we also need to consider the length of the wire, heat dissipation and other factors to ensure the integrity and reliability of the circuit.

Therefore, before proceeding with the actual installation, you should consult a professional and carefully read the instructions of the electrical equipment.

30 thousand w380v motors, air open to the motor indirect line 1 km, how big air to use.

Dear, I am glad to answer for you: A 30 thousand w380v motor, air open to the motor indirect line 1 km, how much air to use as follows: 30kw 380v should be used 6 square cables and 50A air open to meet the requirements of the voltage of 380 volts, the load of 30 kw electrical equipment, choose how much air switch with action current? To solve this problem, it is first necessary to determine what the nature of the load is of the electrical equipment.

If it is a resistance circuit, the working current per kW is about 5 amps, then the 30kw current is about 150 amps, according to the electrical installation regulations, the choice of the switch is a multiple of the working current, so the air switch should be selected with an action current of 200 amps.