The Imperial Capital of Chemistry is coming, 15 questions are wrong, and 7 are AT

There's a mistake upstairs, I'll figure it out:

1 NO can be used medically to dilate blood vessels.

2 Sulfuric acid preparation, bleaching.

3 No, it will react to produce hydrogen.

4 2SO2+CA(CLO)2+2H2O==CASO4+2HCl+H2SO4 (CaSO4 can be after ).

5 Option B There are ionic bonds in sodium peroxide, non-polar covalent bonds oo, and polar covalent bonds in CO2 Co double bonds, and the generation of O2 is a non-polar covalent bond and an ionic bond in Na2CO3, and a covalent bond in carbonate.

6 Because acidic potassium permanganate is miscible with ethanol and oxidation reaction, it is immiscible with benzene and carbon tetrachloride, and benzene is less dense than potassium permanganate solution, in the upper layer.

Carbon tetrachloride is denser than potassium permanganate solution, in the lower layer. So the purple upper layer is carbon tetrachloride, the lower purple layer is benzene, and the solution is discolored ethanol.

My answer is right. Hope mine satisfies you! My answer!

1) Toxic and harmful, unknown use.

2) Bleaching to make sulfuric acid. Toxic, no strong oxidation, not used for disinfection.

3) No. 4）2so2+ca(clo)2+2h2o==caso4+2hcl+h2so4 。

5) Cleavage of non-polar covalent bonds in b a.

6) I didn't learn organic, it is estimated that the redox reaction fades the potassium permanganate solution.

endothelial factor: unconditional vascular smooth muscle relaxant;

2. SO2 decolorizing agent, reducing agent, antioxidant.

3. Not good, although there is a dense oxidation protective film, it is actually easy to have defects and will still dissolve.

so2+2h2o+ca(clo)2=cacl2 +2h2so45、oh-+cl2=cl-+cloh cloh +oh-=clo-+h2o

O2 2-+CO2= CO3 2-+O· 2O· =O26, acidic potassium permanganate ethanol, miscible faded, and ethanol was oxidized.

Benzene is immiscible, layered purplish-red in the lower solubility of benzene is insoluble in water and less dense than water.

Carbon tetrachloride is immiscible, layered purplish-red on top of solubility, insoluble in water, denser than water.

The questioner is not the one who believes ... Which class is it from?

(1) The problem calculates the solubility of calcium carbonate, and the molecule calculates the mass of calcium carbonate dissolved in water, so of course multiply by the mass of calcium carbonate.

2) When calculating solutes, the dissolved part of calcium carbonate in water exists in the form of calcium ions and carbonate ions (without considering secondary ionization), so the molar concentration of calcium carbonate dissolved in water is consistent with the concentration of calcium ions.

The dissolved calcium carbonate in the water becomes calcium ions and carbonates, and one calcium carbonate corresponds to one calcium ion and one carbonate, so the concentration of calcium ions multiplied by the molar mass of calcium carbonate represents the dissolved calcium carbonate.

The reason why calcium ions are used instead of carbonate is that carbonate is hydrolyzed in water, and the actual concentration is lower than that of calcium ions (and also lower than the actual dissolved calcium carbonate), so only the concentration of calcium ions is calculated.

(1) CaCO3 and Ca(OH)2; (2) carbonates; Incorrect The aqueous solution of Na2CO3 is also alkaline Add CaCl2 solution dropwise to the solution until it no longer produces precipitation, and add phenolphthalein test solution dropwise to the filtrate after filtration, and the solution turns red, which proves that the solution contains alkaline substances such as NaOH.

It can be seen from the composition of the ash that quicklime will form a microsoluble Ca(OH)2 when dissolved in water, and the dissolved Ca(OH)2 can react with soda ash (Na2CO3) and plant ash (the main component K2CO3) to form insoluble CaCO3 precipitation. Carbonate can react with hydrochloric acid to bubble; Both the aqueous solution of Na2CO3 and NaOH is alkaline, so when testing NaOH, Na2CO3 should be removed first to avoid interference.

1.3Cu + 8Hno3 === 2No + 3Cu (NO3) 2 + 4H20 is.

So consume Hno3 to produce nitric oxide ie.

2.Nitric acid altogether.

Consumed left.

Belgian 1:1 of nitric acid and hydrogen ions).

Copper has to be converted to the rest of the acid.

So to monobase.

Dilute nitric acid reacts to form no

3 cu + 8 hno3 = 2cu(no3)2 + 2no (g) +4h2o

3*64g 8 mol 2 mol 2* lx mol y mol v l

192 = mol, nitric acid mol is required for the reaction; Hno3 = = mol > mol so there is an excess of nitric acid.

v = * 2* l = l

h+] mol / 500 ml = mol/lcu2+ +2oh - cu(oh)2 (|Cu2+ mol is generated, so NaOH = *2 = L = 100 ml

The ionic equation is used, and cu n is obtained from the meaning of the question

1) Dilute nitric acid produces only no total according to the conservation of atoms).

2) There is still that.

3) React with H+ first and then with Cu2+, a total of needs.

I'm a junior in high school this year, and I've been rusty for a few months, and I hope there is no problem.

24, (1) 4Na deca 3CO2 = 2Na2CO3 deca c

The reaction equation is: 2CO2 deca5h2 = catalyst = 2ch2oh deca2h2o)

2，(c2h4o)n

24+4+16)*n=88, the solution is n=2

So the molecular formula is C4H8O2

Propyl formate, isopropyl formate, ethyl acetate, methyl propionate, a 4-kind 3, potassium permanganate solution, the double bond of propylene will fade potassium permanganate, and cyclopropane will not work 4, (1) C3H4O2

2） ch2=ch-cooh

3) A is a monocarboxylic acid, so there is -COOH in A, and A can react with hydrogen, bromine, and hydrogen bromide, so there are carbon-carbon unsaturated bonds in the molecule. The simplest compounds containing carbon-carbon unsaturated bonds are acrylic acid and propynylic acid, but only acrylic acid has a carbon mass fraction of 50%. So a is acrylic

1.（1）.Hydroxyl.

2）.c3h6o ch2=ch-ch2oh2.c4h8o2 (write it yourself)3Bromine water fades to propylene.

4.(1) C3H4O2 (2) CH2=CH-COOH (3) First of all, it is a monobasic acid, and there are two oxygen and an addition reaction can occur It should contain a double bond so it is CXH2X-2O2 Then the carbon is 50%, and X=3 is obtained