Knowing that the solution x of the equation ax 2 2 a x satisfies the absolute value of x 1 2 0, find

Solution: x+1 2=0 so x=-1 2

Substitute x=-1 2 into the equation.

-1 2a+2=2(a+1 2).

1/2a+2=2a+1

5/2a=-1

a=2 5, so the value of a is 2 5

Absolute value of x+1 2 = 0

x=-1/2

Substitution equations. ax+2=2(a-x)

a=(-2-2x)/(x-2)=2/5

From the absolute value of x+1 2 = 0, we get x=-1 2

Bringing x=-1 2 into ax+2=2(a-x) gives a=2 5

The absolute value of x+1 2 = 0, so x+1 2=0, x=-1 2, substituting into ax+2=2(a-x), gives -1 2a+2=2a+1, equal to -1 2a-2a=-2+1 equals -3 2a=-1, a=2 5 You see, right?

Because |x+1/2|=0, so x=-1 2

Substituting x=-1 2 into the original equation yields -1 2a+2=2a+1

The solution is a=2 5

x+1/2=0

x=-1 2 brings this to the original equation.

The solution is a=2 5

From the absolute value of x+1 2 = 0 to get x=-1 2 3a 2=3 brought in x=-1 2 then a=2 (right?) ）

Bullshit, very categorical discussion answer is a=-8 or 4

Solving the equation ax+2=2(a-x) satisfies the solution of the equation ax+2=2a—2xax+2x=2a—2(a+2)x=2a-2 x=(2a-2) good number (a+2) The solution of the equation ax+2=2(a-x) satisfies (the absolute value of x-1 2) = 1 |x-1/2|=1 x-1 2= 1 solution yields: x1 = x2 = when x=, i.e.:

2a-2)/(a+2)=.

The absolute value of the 2 in x+1.

get x=-1 2;

Bring in the equation ax+2=2(a-x).

2-x)a=2+2x;

a=（2+2x）/(2-x)=2/5;

Simplify, -1 times of (a square x-2ax) + 4 = 0 unary once, so a = 1 or -1 absolute value, so a can only = -1

So x = minus twelve.

The inscription condition can be reduced to: [(a-2) |a|x+4=0 (a does not equal 0).

Since the equation is a univariate equation, then:

a-2)/|a|is not equal to 0 and a is not equal to 0

Solving the inequality yields that a is not equal to 2 and a is not equal to 0

The solution is x=4|a|/(2-a)

Answer: (a-2) The absolute value of xa is -1 power + 4 = 0 (a-2) the absolute value of a is +4 = 0a-2 + the absolute value of 4a = 0, when a > 0, a = 2 5, when a < 0, a = -2 3

x=-2 is the solution of equation 1 2(1-2ax)=x+a, and x=-2 can be substituted into 1 2(1-2ax)=x+a:

1/2(1-2a*(-2))

2+a1+4a

4+2a2a=-5

a=-5/2

From the absolute value of x -2 = 0, x = 2 is obtained, which can be obtained by substituting the original formula respectively.

At x=2, a=7;When x = -2, a = -1

ax+2=3(a-x)+1

ax+2=3a-3x+1

a+3）x=3a-1

The absolute value of x is -2=0

x = 2 or -2 substitution.

a=7 or, a=-1