Solve the equation 2x 3 x 1 4x 3 to the process answer

Answer: Let 2x+3=0, x-1=0, solve: x=-3 2, x=1 When x<-3 2, -2x-3+x-1=4x-3, solve: x=-1 5, not in the range of x<-3 2, rounded.

When -3 21, 2x+3-x+1=4x-3, the solution is: x=7 3 In summary, the equation is solved as x=7 3

When x 1, the original question is 2x+3-x+1=4x-3, x=7 3, which is in line with the title:

When x -3 2, the original question is -2x-3+x-1=4x-3, x=-1 5, which contradicts x -3 2 and is discarded.

When -3 2 is summed up, the equation is solved as x=7 3

When x-1>=0

Then 2x+3>0 is inevitable, so 2x+3-x+1=4x-3 can obtain x=7 3 verification is a positive solution.

When x-1>=0

When 2x+3>0

Then 2x+3+x-1=4x-3 can be verified by x=5 and is not eligible.

When 2x+3>0

Then -2x-3+x-1=4x-3 gives x=-1 5 validation and is not eligible.

Therefore the equation has a unique solution x=7 3

This is a bit troublesome, and the way to do this is to discuss the positive and negative within the absolute value, so as to get rid of the absolute value and solve the x value. That's it

1) When x - 3 2, the original formula is: -3-2x+x-1=4x-3 5x=-1, and the solution is: x=- 1 5, which is inconsistent with x-3 2; Orange belt (2) when x 1, original = 2x+3-x+1 = 4x-3 3x=7 ode hand x = 7 3 (3) dang- 3 2 .

4 x-2 x+3=(2 x-3)-1 (2 2) x-2 x+3=2 x-3-1 (2 x) 2-2x2 x+7=0 y=2 x y 2-2y+1=-6 y 2-2y+7=0 Because of 0, the material is ready to be uncovered.

4(x+1)=3(x+2)

Remove the parentheses: 4x+4=3x+6

Move item to get: 4x-3x=6-4

Merge: x=2 I wish you progress in your learning, and if you don't understand, you can ask! Thank you!!

How to solve the equation 4(x+1)==3(x+2) (process) solution, get:

4x+4==3x+6

4x-3x==6-4

x==2

4(x+1)=3(x+2)

4x+4=3x+6

4x-3x=6-4

x=2 is glad to answer for you, I wish you good luck in your studies! The [the1900] team will answer the questions for you.

If you need help with other topics, you can turn to me. Thank you!!

(1) When x -3

2, the original equation can be reduced to: -3-2x+x-1=4x-3 5x=-1, and the solution is: x=-15, and x -3

2 inconsistencies; 2) When x 1, the original equation can be reduced to: 2x+3-x+1=4x-3 3x=7

x=73；3) When-3

At 2 x 1, the original equation can be reduced to: 2x+3-1+x=4x-3 x=5 and -3

2 x 1 mismatch;

In summary, the solution of the equation is: x=73

For the time being, I can only think of segmenting with a number line.

First of all, it is divided into negative infinity to -3 2, -3 2 to 1, 1 to positive infinity, and above is 3 cases

1.-2x-3-1+x=4x-3

x=-1 5 (rounded).

x=5 (rounded).

x=7 3, so x=7 3

I don't know if it's right or not. Oral arithmetic. That's the way.

Demarcated by absolute value of 0 points.

x<=, it is -2x-3-1+x=4x-3, and x=-1 5 (rounding) is solved

, it is 2x+3+1-x=4x-3, and the solution is x=7 3

The original equation is: 3x 4(x 1)(x 1) = 3 (2x 2) 3x 4(x 1)(x 1) (2x 2) = 33x 4(x 1)(x 1) [2(x 1)] = 33x 4(x 1)(x 1) 4(x 1) = 33x 4(x 1)(x 1) = 33x 4 2x(x 1) = 3

3x－8x²－8x=﹣3

8x²＋5x－3=0

x＋1)(8x－3)=0

So the solution of the original equation is x 1 = 0 and x 1 = 1

or 8x 3=0, x2=3 8

Solution: 3x-4(x2-1)=-3-(4x2+8x+4)3x-4x2+4=-3-4x2-8x-4

3x+4=-3-8x-4

11x=-11

x=-1 is not easy to do, let's adopt it.........