Biology VS Chemistry Multiple Choice Questions, Superior! Why, please! 10

1. C Analysis: Too much auxin will inhibit growth, and the transmission of auxin is transmitted from the apical bud to the side bud, so the side bud accumulates too much auxin, and the growth is slow.

2. D analysis: to contrast with the flowers coated with auxin in the bagging.

3、d4、a

5. A analysis: if you don't stain, you can't tell the position of chromosomes.

6. C Analysis: A. Ammonia is easy to decompose, and there will be water molecules in it;

b. Aqua regia is a mixture of hydrochloric acid and sulfuric acid;

c. Iron oxide (Fe2O3) takes 56*2 (56*2+16*3)=70%, which is just pure;

D, the same as C7, D Analysis: KCl is very stable and cannot react with Ki to form I2.

8. I didn't understand this topic very well, so I didn't write about it.

c Auxin has a duality, and more inhibits growth.

d Control experiment.

c This one reads the biology book.

A I don't dye it, I dye it deep with gentian purple.

a d by looking at which is not oxidizing.

b If you have the same number of electrons, you are the same atom

CDD Analysis: Ribosomes are the place where proteins (peptides) are synthesized in cells, so they are likened to the "assembly machines" of proteins (peptides). a a

If chemistry is not good, let's not talk about it.

c. High auxin concentration inhibits growth.

d Because it is a comparative test, there is less DDD

c Done this question. cbb

1:a2:d

3:d4:a

5:b6:a

7:b8:c

This is my personal answer, oh, I don't know, right?

Why is it difficult to talk about it!

b.The mass represented by an active site is, 10*10-6 (10-23)=5*10-7

It's a hassle to calculate... This is also the first time I have done this kind of problem.

The ATP molecule contains two high-energy phosphate bonds, and when hydrolyzed by enzymes, the high-energy phosphate bonds away from adenosine A, that is, -p, are broken to form ADP and PI (phosphoric acid), and the energy contained in them is released. The bond can easily break or re-form under certain conditions, thus ensuring the release and storage of energy. So 32p radioactivity will appear in the PI.

However, the high-energy phosphate bond (-p) close to a is not easy to break and recombine, and cannot participate in energy metabolism. So the radioactivity of [-32p]-atp does not appear in the pi in the same amount of time.

The hydrolysis of ATP to form ADP and the formation of ATP by ADP and PI is a process of dynamic equilibrium. When [-32p]-atp is added, its hydrolysis yields ADP and 32P-labeled PI. But when [-32p]-atp is added, its hydrolysis is to generate 32p-labeled adp and pi.

Only when the rehydrolysis of the 32p-labeled ADP occurs will the AMP and 32p-labeled PI be generated.

Carbohydrates: Polyhydroxy aldehydes, polyhydroxyketones or their derivatives, or a general term for these compounds that can be produced when hydrolyzed.

According to the degree of aggregation, it is divided:

1。Monosaccharide

Sugars that cannot be hydrolyzed into smaller molecules, also known as simple sugars, such as glucose, fructose, ribose, etc.

2。Oligosaccharide oligosaccharide includes many categories, disaccharide or disaccharide, which generates a sum of 2 molecules of monosaccharides when hydrolyzed, such as maltose, sucrose, etc.; trisaccharides, when hydrolyzed, oak silver is formed into 3 molecular monosaccharides, such as raffinose; as well as tetrasaccharides, pentaccharides, etc.

3。Polysaccharides

When hydrolyzed, sugars with more than 20 single molecules are produced. Includes:

1) Homopolysaccharides: Hydrolysis produces only 1 monosaccharide or monosaccharide derivative, such as glycogen, starch, chitosan, etc.

2) Heteropolysaccharides: hydrolysis produces more than one monosaccharide or monosaccharide derivatives, such as hyaluronic acid, hemicellulose, etc.

Divided by group:

Aldose Ketulose.

Question 15: There are about 2 peptide bonds in one alanine, and when you get rid of 2 alanines, the number of peptide bonds is reduced by 4. The process obtains 3 short peptide chains and two free alanine, 3 short peptide chains and two free alanine, 3 short peptide chains add 2 amino groups and 2 carboxyl groups, and two free alanine groups increase 2 amino groups and 2 carboxyl groups, so the amino group and carboxyl group are increased by 4 respectively, and the polypeptide takes off 2 of the alanine and needs to consume 2 H2O molecules.

Therefore, the number of hydrogen atoms increases by 8 and the number of oxygen atoms increases by 4. Question 16: The original peptide is 39, and the number of peptide bonds is 38.

Now 4 polypeptides of different lengths are obtained, and the number of peptide bonds is 6+7+8+10=31 according to the figure. Reduced by 7, so item A is correct. The molecular formula of alanine is C3H7O2N, and the number of oxygen and hydrogen is not counted.

Alanine has three C's and 4 are removed, making a total of 12 reductions.

Therefore, item b is correct.

Remove 4 alanine, if the end of No. 7 becomes --cooh, then the front end of No. 9 becomes --NH2, that is, an amino group and a carboxyl group are added, (on the contrary, if the end of No. 9 becomes --cooh, then the front end of No. 7 becomes --NH2) can also be used, the same interface, the interface each adds an amino group and a carboxyl group, a total of 3. Therefore c is correct. Alanine was reduced by 4, and alanine was C3H5ON in the peptide chain.

Therefore, the number of O atoms is reduced by 4, and while the alanine is removed, a total of 3 water molecules need to be added, that is, 3 O atoms. Therefore o atom is reduced by one. Therefore, item D is incorrect.

7.Note that it is all organic!

Option C: The four peptide bonds hydrolyzed off each add 2 hydrogen atoms, so the total number of hydrogen atoms added is 8

Option d: Each of the four peptide bonds hydrolyzed by 1 oxygen atom is added, so the total number of oxygen atoms added is 4

The option has one alanine at the peptide chain port so it loses 1 peptide bond, while the other three alanine are inside the peptide chain and not connected so it loses 6 peptide bonds, so the sum is 7

d Because there is an alanine at the port, 2 oxygen atoms are lost, and 1 oxygen atom is added by losing a peptide bond, and the number of oxygen atoms lost in the peptide chain is equal to the number of oxygen atoms added, so the number of oxygen atoms is reduced by 1.