Fractional equation application problems about money, math fractional equation application problems

2008, Zaozhuang) a project, in the project bidding, received a bid, B two engineering team bidding, construction day, need to pay a project team project 10,000 yuan, B engineering team project 10,000 yuan, the project leading group according to the bidding of A, B two teams of bidding, there are the following schemes:

1.Team A completed the project on its own, just as scheduled;

2.Team B completed the project alone by one day more than the allotted date.

3.If Team A and Team B work together for 3 days, the rest of the work will be completed on schedule by Team B alone.

Let's ask: On the premise of not delaying the construction period, which construction plan do you think is the most economical for the project? Please explain why.

2008, Yibin) A and B are 360 kilometers apart, with the transport convoy from A to B, when 150 kilometers away, received a notice, asked to arrive in advance, the team decided to increase the speed to the original times, arrived at B for 6 hours, asked what was the original speed of the convoy?

I don't have an answer.

Go to the book store to buy, teaching aids, or exam question sets.

The cost of buying Taiwanese apples before the "three links" was twice as high as this year.

It also used 100,000 yuan to purchase Taiwanese apples, but this year it bought 20,000 kilograms more than before the "three links".

After the realization of the "three links" between the two sides of the Taiwan Strait, the cost of a fruit sales company to purchase apples from Taiwan has dropped significantly, please calculate the cost of the company's purchase of apples in Taiwan before the realization of the "three links" according to the dialogue between the above two managers.

Solution: If you buy back x pieces for the first time, then the purchase price of the clothes you buy back for the first time is 50,000 x, then the second purchase price is 3x, so the purchase price of the second purchase is (50,000 x) + 12, so the store profit is 80 (4x-400) + 80 400 65%.

50000+186000), and x can be based on 186000 3x=(50000 x)+12, and you can get the profit of the store by bringing x in.

The original plan was to produce x tons of water per day

It takes 1800 x days to produce 1800 tons;

After the work efficiency is doubled, it takes 1800 (days) to produce 1800 tons of production;

After Sun Qing's work efficiency was doubled, it was completed 3 days earlier than the original plan, and the Kai potato equation is listed as follows:

1800/x)-3=1800/(;600 x=3;

The solution is x=200;

1.Solution: If it takes X days for A to do alone, then it takes 3x 2 days for B to do it alone, (2 x) + (2 + 1) (3 x 2) = 1

2/x+2/x=1

4 x = 1 x = 4 days.

3x 2 = 6 days.

Answer: It takes 4 days for A to do it alone, and 6 days for B to do it alone.

The cooperation of the two teams is completed every day: (1-10 20) 6 = 1 12 Team B needs to complete alone: 1 (1 12-1 20) = 30 days 2) Team B needs to be constructed for at least x days, then.

2*[1-x/30]/(1/20)+1*x≤3540-4x/3+x≤35

x/3≤-5

x 15 days.

A: Team B needs to work for at least 15 days.

3.Solution: Let B make x pieces every day, then A will make x + 4 pieces per day 120 2x + 2 = 120 (x+4).

60/x +2 =120/(x+4)

60(x+4)+2x(x+4)=120x

2x^2 -52x+240=0

x^2-26x+120=0

x-6)(x-20)=0

x1 = 6, x2 = 20 pieces.

x+4 = 10 pieces or 24 pieces.

A: A does 24 pieces a day, B does 20 pieces a day, or A does 10 pieces a day and B does 6 pieces a day.

1. If it takes x days for team A to do it alone, then it takes (3 2) x days (1 x) * 2 + 1 [(3 2) x] * 3 = 1 x = 4 days for team B to do it alone.

So it takes 4 days for Team A to do it alone, and 6 days for Team B to do it alone.

2. It takes X days for Team B to complete this project alone.

1 20) * (10 + 6) + (1 x) * 6 = 1x = 30 days.

If the B engineering team needs to be constructed for at least y days, then the A engineering team needs to be constructed for 20*[1-(1 30)*y] days.

20*[1-(1 30)*y]*2+y=35y=15 days.

3. If A makes x pieces every day, then B does (x-4) pieces (120 x) = [120 2(x-4)] + 2 every day to get x 2-34x + 240 = 0

x-17)^2=49

x = 24 or 10

So A makes 24 pieces a day, then B makes 20 pieces a day.

Or A does 10 pieces a day, then B makes 6 pieces a day.

Note: x 2 represents the square of x.

1 X days for A and y days for B.

y=3/2*x

1/x+1/y）*2+1/y=1

x=4 y=6

2 Set up team B for x days.

1 20 + 1 x)*6+10 20=1 ==> x=30 Set team B to work for a minimum of y days.

1-1 30*y) (1 20)*2+y=35 ==> y=153 Let A do x per day and B do x-4 per day.

120/x-2=120/2（x-4）

x = 24 or 10 24-4 = 20 10-4 = 6 A does 24 per day and B does 20 per day.

A makes 10 a day. B does 6 per day.

The upstairs answer is very good, do this kind of problem, you have to know that there is a characteristic of middle school mathematics, you can set whatever you ask, basically 80% of the time. The information given in each sentence in the stem is basically useful, and you just have to find all of them and write a formula based on each sentence, and don't miss it, and you're basically going to get the problem.

Let the efficiency of human translation be x word minutes.

3300/x-3300/75x=2*60+283300/x-44/x=148

3256/x=148

x = 22 The efficiency of human translation is 22 word minutes, and the computer is 1650 word minutes.

If the water added is x liters, there is.

15% 30 (30+x)=18% 20 (20+x) solution x=20 is tested.

x=20 is the root of the original equation, so add 20 liters of water.

Hello landlord! I'm very happy to be able to ask the landlord a question that just activates my brain! First of all, according to the assumptions of the landlord, I will give you the answer first:

Suppose x people dig the soil, then 72-x people carry the soil, and then we find the equation relationship (one of the keys to solving the problem) x=(72-x)x3 (Note: the small x is the multiplier sign, the same as x, so it is bold) x=54 So 54 people dig and 18 people carry the soil. In fact, the key to solving this kind of problem is to find the equivalence relationship, in which we can see that the person who digs the soil and the person who carries the soil is 3:

1 relationship. So the end result is definitely that the number of people digging is three times as many as the number of people hauling it! So we can derive an equiquantitative relation:

The number of people digging = the number of people transporting soil x 3, and then put the hypothetical x in, get the equation, and find the result! I hope it can help the landlord!! Thank you

Then there is this case where x (72-x)=3 is obtained to x=54

Are you a one-dimensional equation?

Solution: 1) It takes 3x days for A to complete alone, then it takes 2x days for B to complete alone, and the equation is listed to get: 6*(1 3x+1 2x)=1

6*(5/6x)=1

x=5 is tested, x=5 is the solution of the original equation, and it is in line with practical significance, so we get: 3x=15 , 2x=10

Therefore, it takes 15 days for A to complete alone, and 10 days for B to complete alone.

2) From 1), it can be obtained: A's efficiency is: 1 15 - A's workload is: 6*(1 15)=2 5

B's efficiency is: 1 10 - A's workload is: 6 * (1 10) = 3 5 So, A gets the money as:

20000 * (2 5) = 8000 (yuan) B gets the money: 20000 * (3 5) = 12000 (yuan).

The two engineering teams A and B contract the campus greening project of a school, and the time ratio required for the two teams A and B to complete the project alone is 3:2, and the two teams can cooperate for 6 days to complete.

How many days does it take for each team to complete the project individually?

A alone do 1 [1 6 3 (3+2)

10 days. B alone do 1 (1 6-1 10).

15 days. After the project was completed by the two teams A and B for 6 days, the school paid them 20,000 yuan.

A20000 3 (3+2).

12,000 yuan.

B 20000-12000 = 8000 yuan.

Let it take x days for A to be completed alone and Y days for B to be completed alone.

x/y=3/2 y=2x/3

6/x+6/y=1 6x+6y-xy=06x+4x-2x2/3=0

x2/3-5x=0

x2-15x=0

x=15y=10

It takes 15 days for A to complete alone, and 10 days for B to complete alone.

A gets 20,000 * 6 15 = 8,000 yuan.

B gets 20,000 * 6 10 = 12,000 yuan.

Solution: It takes 3x days to set up team A and 2x days to set up team B.

6(1/2x+1/3x)=1

The x=5 test results in x=5 being the solution of the original fractional equation.

3x=15,2x=10

A's workload: 1 15*6=6 15=2 5B's workload: 1 10*6=6 10=3 5 A's money: 20000*2 5=8000

The money B gets: 20000-8000=12000