-
I don't think you should think about it. I am a high school girl, and I am also an excellent student in my class, and there is a boy in my class (I often take the top three exams, and I am also in the top ten), and he asks the girl who goes home with me every day to tell me that he likes me, and often gives me candy, books, etc., which makes me very distressed and affects my study, and I hate him very much. In the end, I couldn't do it anymore, so I told the head teacher, and the old class told me to reject him fiercely.
In the end, I ignored him.
You don't know how pure our high school girls are, and they only think about studying, which is the most responsible performance for themselves, their parents, and others. As a boy, you should understand this, study hard, work hard, and don't bother her! It's not too late to talk about it when you have achievements in the future!
A word to you: every stage of life has something to do at that stage, and if you delay it (such as early love) or postpone it (such as hard work), it will not end well! Notice!
-
It's not right to get the moon first near the water, you should keep a certain distance from her, but from time to time make excuses to approach her and show your positivity. However, you can't be uncomposed, you can't lose your grace too much, and you can't be too pretentious. Come on!
-
If your own conditions are very good, confess to him clearly, if you are not afraid of blows.
After all, if you do this, you won't have any other problems.
Say it early, say it early.
Good luck!
-
Isn't it a high school student?。。。 Ask questions like a junior high school student, you say she likes you very much, has she confessed to you? You like her.,Then do you like her to be a class flower.,Or really like it.,You shouldn't be annoyed if you figure it out.。。。
-
If it's a boy, take the initiative.
The girl was just waiting for a confession.
Waited too long. Tossing and turning for too long.
Too long to guess. Disappointed for too long.
Who's still interested in you?
-
Persistence and then abandonment is basically the case.
-
If you don't work hard, you won't get anything. That's it. Kindness.
-
1. Because x 0, m 3x, so 3x 0, m-3x 0, meet the requirements of the mean inequality, thus, 3x+(m-3x) 2 [3x(m-3x)], that is, 2 [3x(m-3x)] m is obtained.
3x(m-3x)] m 2, 3x(m-3x) m 4, divided by 3 on both sides of the inequality at the same time, gives x(m-3x) m 12, so the maximum value of the function is m 12
2. Because 2 x>0, 4 y=2 2y>0
So 2 x+4 y 2 (2 x*2 2y)=2 2 (x+2y)=2 2
So 2 x+4 y 2 2
After doing these two problems, I want to tell you that this is actually a kind of regular problem, that is, when using the mean theorem, I always try to turn one side of the inequality into a constant, because only when one side is a constant, this constant is the maximum value of the other side. If there are variables on both sides of the equation, it is impossible to determine the maximum.
-
1. Let a= [3x(m-3x)]<=[3x+(m-3x)] 2=m 2
So 3x(m-3x)<=m4
So y max = m 12
x>0
4^y=2^2y>0
So 2 x+4 y>=2 (2 x*2 2y)=2 2 (x+2y)=2 1=2
So 2 x+4 y 2
-
x(m-3x)=3x(m-3x) 3 (1) Know the inequality 2(a 2+b 2)>(a+b) 2>4ab When a, b>0, I omit the equal sign. So let 3x=a then equation (1) becomes a(m-a)(2) Since it is known that both a and m-a are greater than 0, so a(m-a)<(a+m-a) 2 4=m 2 12 Attached 2 means 2 to the power of 2, which is squared, and m 2 is the square of m, so that y obtains the maximum value of m 2 12. When x=m 6.
Question 2: First, 2 x+4 y=2 x+2 2y (1) is known from x+2y=1 x=1-2y, so that (1) becomes 2 x+2 (1-x) (2).
Let 2 x=a then equation (2) becomes a+2 a(3) From inequality (a+b) 2>4ab know that equation (3) is greater than or equal to 2*2 (1 2) is the meaning of 2 multiplied by the root number 2 Got it, the value range is 2 times the semi-closed interval of the root number 2 to positive infinity.
-
(1)h2o,h2o2
2) For example, HD
3) Isomers are those with the same molecular formula but different structures. Allotropes are elemental elements composed of the same elements and in different forms. H2O and D2O are neither. To do this kind of topic, you need to be clear about the concept.
4) Mixed glycerides are generally mixed because of the different possibilities of their R groups. The main components of water gas are CO and H2. It's memorized.
5) A is a non-volatile acid to volatile acid, such as concentrated sulfuric acid to hydrochloric acid. The strong acid of B is the same as that of A; Strong acids to weak acids are the production of acids with a higher degree of ionization into acids with a lower degree of ionization, that is, the formation of weaker electrolytes. 2HCl+CaCO3=CaCl2+H2O+CO2 is the formation of weak acid H2CO3 from HCl, and then carbonic acid decomposition.
6) A is a mixed salt. Mixed salts are generally salts composed of one cation and two acid ions. caocl2 can be written as ca(clo)cl.
-
1.o can at least generate h2o and h2o2 (plus ho2 or something)2If it is H2O is a compound, two atoms 3
An isomer is a compound with the same chemical formula, the same chemical bonds, and different atomic arrangements. To put it simply, the phenomenon that compounds have the same molecular formula but have different structures is called isomerism; Compounds with the same molecular formula but different structures are isomers of each other.
H2O and D2O have different chemical formulas, so no, the latter is 4Monoglycerides. Mixed glycerides are pure, they have only one molecule, water gas is a mixture of H2 and CO.
False, for example, HCl+NaOH==NaCl+H2OB pairs, for example, H2SO4+BACl2==2HCl+BaSO4 There are many weak acids that are generated, and strong acids make weak acids, such as HCl+Na2CO3 is a mixed salt reference.
-
The 1n element forms a variety of hydrides, including ammonia and hydrazine.
o elements also form two hydrides, water and hydrogen peroxide.
2 The two atoms it refers to may be two atoms of the same element, different isotope atoms or atoms of different elements, 3a is the same substance, d is deuterium, also known as heavy hydrogen, is an isotope of ordinary hydrogen, d2o and h2o are not two substances.
4. Monoglycerides and mixed glycerides are pure, the three hydrocarbon groups of monodry oil esters are exactly the same, the three hydrocarbon groups of mixed glycerides are not identical, and water gas is a mixture of carbon monoxide and hydrogen.
5. The reaction of barium chloride and sulfuric acid will produce hydrochloric acid.
6. The last question will not.
-
1.O can form H2O2.
2 Isotopes such as O18 and O16 (two different atoms of the same element) are mixed to form a substance that is still elemental (a pure substance composed of the same element).
3 Isomers, as the name suggests, have the same molecular formula (i.e., the same type and number of atoms that make up the molecule) but different structures, obviously the molecular formulas of H2O and D2O are different (because H and D are not the same atoms), while the latter have the same molecular formula, only different structures.
4 Monoglycerides. Mixed glycerides are pure, except that the former is esterified by one carboxylic acid and glycerol, while the latter is esterified by multiple carboxylic acids and glycerol, but they are still only one substance. Water gas, on the other hand, is a mixture of CO and H2.
5 Item A cannot be cited as a counter-example for the time being.
In item b, there is 2HCl CaCO3=CaCl2 H2CO3 (H2O CO2).
bacl2+h2so4=baso4↓+2hcl
6. Mixed salts: salts formed by the replacement of hydrogen atoms in binary or polyacid molecules by different metal atoms, or the hydrogen atoms in two or more acid molecules by the same metal atoms, composed of a metal cation (including NH4+) and two acid anions. For example, calcium nitrate chloride, calcium hypochlorite chloride caocl2, etc.
PS: CaoCl2 is composed of Ca2+, Cl-, Cl-. Item B consists of Bio+ and NO3 as ordinary salts.
-
The first question A is wrong because O can produce two hydrides, H2O and H2O2 (hydrogen peroxide).
1.The water fee is 128 yuan》40*(
That is, more than 40 tons of water are used. >>>More
I'm really fake, it's all there.
By the question, there is |f(-1)|= |-a+b|<=1 ; f(1)|= |a+b| <=1 >>>More
Let BC be x and AC be y, then in the triangle ABC x 2+y 2=2 2+8 2In the triangle ACD and BCD x 2-2 2 = y 2-8 2, the solution can be found to find cd
This question. No.
First of all, I don't know if the ring in the middle is painted. >>>More