Please give me some math problems for the sixth grade of 2009! Hurry, hurry

= 1 1600 (originally planned to be 1 1600 per carriage per transport unit) and the remaining part can be transported x times. then, 1 1600 20 20+1 1600 (20+30)x=1x=24

A: The remaining part can be transported 24 times.

2.(1) The two cars meet when they are in x hours. then, 57x+(57+1)x=276

x=A: After two cars met when they were young.

2) Let it take y hours from the start to the distance of 46 km, then, 57x+(57+1)x=276-46

x=2A: It took 2 hours from the start to the distance of 46 km.

3) There is a distance of 69 km from the start to the meeting, and z hours are shared, then, 57x+(57+1)x=276-69

x = A: There was a distance of 69 kilometers from the start to the meeting, and it took hours.

120÷10=12km/h

20-12=8km/h

8 2 = 16 km h (this is the speed in still water) 320 16 = 20 h (h, is the hour) Answer: It takes him 20 hours to sail 320 km in still water.

4.If the two stations of A and B are separated by x kilometers, then.

x-65)÷65×

x=455A: The distance between the two stations is 455 kilometers.

Question 3 or Question 4 If you don't understand it 1428289052 Add my QQ

Question 1: 24 times.

Question 2 (1) hour.

2) 2 hours.

3) 3 hours.

Question 3: 20 hours.

Question 4 455 km...

Ask for points...

1 question, 24 times, 2 questions, 2 4 hours, 2 hours, 3 hours, 3 questions, 20 hours, 4 questions, 455 km.

1>(80-20)×20÷(20+30)=242>

320 [(200 10+120 10) 2]=204> A and B stations are x kilometers apart.

x-65)÷65×

x=455

1 20*80=1600

2(1) 276 (57+(57+1))=(2) (276-46) (57+(57+1))=2(3) (276-69) (57+(57+1))=3 Let the hydrostatic velocity x and the water velocity y

x+y=200/10

x-y=120/10

So x+y=20, x-y=12

So x+y+x-y=32, 2x=32, x=16320, 16=20

Absolutely do it yourself.,There's no way to make a mistake.。。。

1 solution: 20 80=1600 knots 20 20=400 knots (1600-400) 30=40 times Answer;

2(1)276 (57+57+1)=hours A. (2)(276-46) (57+57+1)=2 hours A.

3) (276 + 69) (57 + 57 + 1) = 3 hours A.

3 solutions; Let the water flow velocity be x, and the velocity in still water is y 200 (y+x)=10 120 (y—x)=10

x = 4 y = 16 320 16 = 20 hours.

4 solution, let the express train travel for x hours, and gather y kilometers 65x=y

x= 7 y=455

Question 1: 24. Question 2: Question 1, Question 2: 2, Question 3: 3. Question 3: 20. Question 4: 1040 km.

Question 1: 24 times, Question 2: Hours, 276 (57+58)=

Question 3: The speed of sailing along the water is 200 10 = 20km hours, the speed against the water = 120 10 = 12km hours, the speed of the still water = the speed of the water - the speed of the water = the speed of the water against the water + the speed of the water so the speed of the water is 4km hours, and the speed of the still water is 16km hours 3200 16 = 200 hours.

Question 4: The fast train travels 1 hour longer than the slow car, and the fast train travels 104-65=39km more than the slow train at the same time

Therefore, the slow train travels for a total of 39 (hours, so the express train travels for 7 hours, and the distance between A and B is 65*7=455

When the salesman remitted money to the owner, the invoice on the 0 more than one became ten times the original amount, and the owner remitted the over-remittance of 9000 yuan to show that 9000 yuan is 10-1 = 9 times the original amount, so 9000 divided by 9 is 1000, that is, the original amount is 1000The manager asked him to compensate for the remittance fee caused by the mistake is 9000 times to get 900, 1000 multiplied to get 100,900-100 = 800, so the salesman should compensate 800 yuan, 1000 + 100 = 1100, so the payable on the invoice is actually 1100 yuan.

Set up x members who should be exported.

x+9000=10x

x=1000

The wrong number is 10,000 yuan.

Therefore, compensation should be paid: 10,000 1% = 100 yuan.

(720 720 115% 720 25%) Yuan Answer: Dad brought 1440 yuan.

Income on three-year deposits: $25,000.

Income on three-year treasury bonds: $25,000.

Answer: The yield of the three-year treasury bond is large, 100 yuan larger.

It's very simple, children, it is recommended to think about it more, practice more after class, and don't be lazy!

Percentage questions. We haven't learned that yet. sorry

The money used by three people = (720*80%) + 720*80%*15%+720*80%) + 720*80%*25%)

Your dad's money = (720*80%)+720*80%*15%+720*80%)+720*80%*25%) divided by.

It is a problem of public multiples, every 10 minutes of news broadcast by Channel A and then then broadcast advertisements for 2 minutes is 12 minutes, Channel B broadcasts advertisements for 1 minute after every 8 minutes of news is 9 minutes, and Channel C broadcasts advertisements for 3 minutes after every 15 minutes of news is 18 minutes, that is, you are asked to find the common multiples of 12, 9, and 18, that is, 36. This means that when the first time the advertisements of the three news stations end at the same time is at 12:36, the news broadcast ends.

A news plus advertising is 12 minutes.

Channel B News plus advertising is 9 minutes.

Channel C: News plus advertising is 18 minutes.

The greatest common divisor of 12,9,18 is 36

So it's 36 minutes later.

The least common multiple of +3 is the end of the first simultaneous advertisement, which is the end of the newscast.

Least common multiple: 36

12:00 + 36 = 12:36 News broadcast ends.

Find the least common multiple of three numbers at 12:36.

Question 1: Find the least common multiple of 6 and 10: The least common multiple of 6 and 10 is: 30. At least seconds.

Question 2: (1) Total length: 50 (37 1) = 1800 (m) (2) is to find the least common multiple of 50 and 60: the least common multiple of 50 and 60 is: 300.

3) Look at how many 300s there are in 1800, just as many immovable poles as there are, and add the first one at the beginning.

4) A few sticks don't move: 1800 300 1=7 (roots).