-
Anonymous users2024-02-15It's the same, depending on what you're asking for.
If the weights a and b are the same, you get a1 b1, a2 b2, ......The weighted average of .
If the weights A and B are different, you get the weighted average of a and the weighted average of b.
In the first case, you evaluate the comprehensive situation of each company in the region, where your weight a=b is actually the weight of the average price of materials of a single company, and you do the weight of the average price.
In the second case, you evaluate the comprehensive average price of all companies in the area, and you do the weighting of the total price, the weight of the volume, and the average weight.
If you use the first case, it should be applied in this case: you are going to buy a large amount of material that one company cannot provide, and several companies in the region provide it together. At this time, you buy directly from each company, you already know the supply and volume of each company, and your weight of each company is a comprehensive value after considering the supply and volume of the company.
If you use the second case, it should be applied to this case: you are going to buy a large amount of materials not directly from the company, but from the market in the area. Because you can't know for sure which company produces everything you buy, use this method to make a comprehensive evaluation of the goods on the market in the area, so that the ratio of quality to quality can be optimized.
-
Anonymous users2024-02-14I've been doing math for years.
-
Anonymous users2024-02-13Averages include two categories:
Arithmetic mean, weighted mean.
What we usually call the average is the arithmetic mean, for example, Ji Zi He Tuan calculates the average score of a mathematics test in your class, which is actually the arithmetic mean of the calculation.
You have to use a formula to calculate the weighted average.
Regardless of the average, our calculation idea is "sum divided by the total number".
-
Anonymous users2024-02-12Generally, the average of n numbers is weighted the same, which is 1 n (1 n=1).
The weighted average can be selected according to the actual situation, that is, a(i)(a(i)>=0, a(i)=1).
-
Anonymous users2024-02-11This kind of problem is calculated using the idea of weighted average.
The full score for all grades is 100 + 100 + 100 = 30040% + 30% + 30% = 100%.
So this student's grade should be = 90 40% + 88 30% + 98 30% = for your understanding, I can give you another example.
For example, if a student's scores in two unit tests are 88 and 90 respectively, the mid-term test score is 92, and the final test score is 85. In view of this consideration, we tend to assign different weights to these four grades.
Since 10%+10%+30%+50%=1, that is, the sum of the weights is 1, the denominator in the formula for finding the weighted average is 1
88*10%+90*10%+92*30%+85*50%=The following example is the case of unknown weights:
**a, 1000 shares, **10;
**b, 2000 shares, **15;
Arithmetic mean = (10 + 15) 2 = ;
Weighted average = (10 x 1000 + 15 x 2000) (1000 + 2000) =
<> set pb=1, pa=2, pc=3
Because cq=2, pc=3, pq=1 >>>More
In the third year of high school, if you are preparing for tutoring, the foundation of mathematics can be raised; Otherwise, you will have to prepare for the exam. For senior high school students, don't always think about starting from scratch and doing a big job, it's very unrealistic. What you need to do now is to take a few days to summarize yourself and identify your strengths and weaknesses. >>>More
Solution: (1) f'(x) = 3mx 2+4nx-12, from the question -2, 2 is f'(x)=0, 2+2=-(4n 3m), (2)*2=-12 3m, n=0, m=1; At this point, f(x)=x3-12x,f'(x)=3x^2-12 >>>More
To make proposition p or q a false proposition.
Then both propositions p and q are false propositions. >>>More
Let the function z = z(x,y) be determined by the equation f(x+mz,y+nz) =0, where f(u,v) is a differentiable function and m and n are constants, find m( z x) + n( z y). >>>More