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Solution: Set up to rent X trains of type A and Y trains of type B, according to the relationship in the question, there are:
x+y=16
18x+16y≥266
10x+11y≥169
Draw the above three equations to establish the coordinate axis, and you will get a region.
Because the fuel cost = 1500x+1200y, so let 1500x+1200y be the smallest, that is, on the line of x+y=16, and the integer solution closest to the origin in the region is the solution, it can be found that when taking 18x+16y=269 and 10x+11y=169 near the intersection point, it should be the closest to the origin in the three regions, and the nearest integer interprets x=5, y=11, so the solution is to rent 5 cars of the first type, 11 cars of type B, the minimum is 5 1500 + 11 1200 = 20700 yuan.
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Solution: (1) Set up to rent X trucks of type A, and rent (16-x) trucks of type B, according to the title, 18x+16(16x) 266
10x+11(16−x)≥169②
By , x 5, by , x 7, so, 5 x 7, x is a positive integer, x = 5 or 6 or 7, therefore, there are 3 car rental schemes: scheme 1: group A type of trucks 5, type B 11 trucks.
Plan 2: Group 6 type A trucks and 10 type B trucks. Option 3:
There are 7 trucks of type A and 9 trucks of type B. (2) Method 1: From (1), rent X trucks of type A and rent trucks of type B for (16-x), and the total fuel cost of the two trucks is Y yuan.
According to the title, y=1500x+1200(16-x), =300x+19200, 300 0, when x=5, y has a minimum value, y min=300 5+19200=20700 yuan;
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<> rotate it yourself and watch it. Thank you.
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After conversion you get (a+b) 2 (a-b) 2=2, then (a+b) (a-b)=+sqrt(2).
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Proof: (1).
Prove the monotonicity of a function by definition].
Take x1, x2 r, and x1 x2
then f(x1) f(x2) a [2 (2 x1 1)] a [2 (2 x2 1)].
2(2 x1 2 x2)] [(2 x1 1)(2 x2 1)] y 2 x increments on ( and x1 x2 2 x1 2 x2
2^x1)-(2^x2)<0
(2 x1 1) (2 x2 1) 0
f(x1)-f(x2)<0
i.e. f(x1) f(x2).
f(x) is an increment function on (.
2) f(x) is an odd function, then f(0) a [2 (2 0 1)] a 1 0
A 1 is tested and f(x) is an odd function when a 1.
3) f(t 2+2) + f (t 2-tk) > 0 is constant and immediately has f(t 2+2) >-f(t 2-tk) = f(tk-t 2) and t 2 is obtained by the increase function t 2+2>tk-t 2
2t^2-tk+2>0
Then there is discriminant = k 2-16<0
i.e. get -4
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Big brother, I can't see clearly, but I can't see it clearly.
Because Xueba is a special creature, this kind of creature is detached from the common sense described by the theory of evolution, it may be a genetic mutation, or it may be affected by the monsoon or living in the interior all year round, and it may be that the changes of the times and the development of Marxism have promoted the life process of this creature, and they are likely to get rid of the constraints of gravity. Therefore, the top student is not cute, who is cute?
Can I choose to do it for you? There are too many words to translate.
In our academic career, there will be a small number of top students in the class, and their academic performance is very good. At the same time, it can also be found that these top students do not actually spend as much time on studying as others, but their grades are often the best in the class. However, in real life, everyone found that none of the top students around them went to become teachers. >>>More
It may be more able to promote the growth of scumbags. Two people become a couple, Xueba can tell the scumbag a good learning method, the scumbag wants to make himself more compatible with the Xueba, so he can only work harder in learning, a good long-term relationship is that the two can grow better together and make themselves better.