Please help solve a math problem, help solve a math problem

Solution: 1-8

Class A, odd odd even even odd odd, the first two digits are odd, and the last two digits are at least one even number; or the last two digits are odd, and the first two digits have at least one even number, class B, even number odd number odd number even number.

The four digits are all odd numbers; or at least one even number for the first two digits and at least one even number for the last two digits.

The total is 8 8 8 8

1) odd-odd-even, odd-even, odd-even; Odd and even, even and even, even and even. Category A: (4 4 4 4 4 4 4 4 4 4 4 4 4) 2, accounting for (4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4 4

2) Qiqi Qiqi; odd-even, odd-even, odd-even; Even-odd-even, even-odd-even, even-odd-even. Category B accounts for 1 3 8 5 8 of the total

So the percentage of the number of class A to the number of class B is 3 5 60 references.

In this way, it is obvious that the composition of the four digits of class A is not even, so he has a total of 5 * 5 * 5 * 4 = 500 possibilities, and the number of class B can be composed of four of them as long as there is an even number, then he has a total of 9 * 10 * 10 * 8-5 * 5 * 5 * 4 = 6700

where 9*10*10*8 is the total number of four digits that are neither 0 nor 9, and 5*5*5*4 can be understood in this way.

The first 5 means that there are only 5 possibilities for the number of thousands, which can be 1, or 3, or 5, or 7, or 9

The other two 5s also have this meaning, and the sub-table indicates the possibility of hundreds and tens of digits.

4 means that there are only 4 possibilities for a single digit, it may be 1, or 3, or 5, or what is the percentage of the number of classes of 7 to the number of classes B = 500 6700 =

The probability of throwing one, which is neither 5 nor 6, is 2 3, so the probability of throwing two that are not 5 or 6 is 2 3 * 2 3 = 4 9 (they are independent of each other).

Therefore, the probability of at least having a 5 or 6 is 1-4 9 = 5 9

The probability is 5 9, and the total number of points is 36, and the number of 5 or 6 is 20.

There are 36 possible cases of at least one of 5 or 6 (5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)(1,5)(1,6)(2,5)(2,6)(3,6)(3,5)(4,5)(4,6) So the probability is 5 9

Five out of nine, the probability of not having two dice is four out of nine, which is two-thirds multiplied by two-thirds and subtracted by one.

Its opposing event is that there are no 5 and 6 points.

So p=1-4 6 4 6=20 36=5 9

Hectare. Harvest 85-74 = 11 hectares.

2.Because there are 1 4 more boys than girls, there are 1 5 fewer girls than boys

6 (1 5) = 30 people [refers to the scumbag Weiji quietly born].

30-6=24 people.

3.Length + width = 49 2 = meters.

Width: m. Length: m.

Ton. 5.The first half of the month accounts for 1-2 5-1 4 = 35% 35 35% = 1 million yuan.

6.Radius: meters.

Area: square meters.

The yuan is about 113 yuan.

7.The remaining front trembling accounted for all the original chickens: 1-40% -1 3 = 4 151200 (4 15) = 4500 chickens.

9 10 (1 12 + 1 15) = 6 days.

9.Daddy left 1-60% = 40%.

360 yuan of father's salary: 5 8-40% =

360 RMB.

Question 1: coordinates of a (3,2), coordinates of b (3,0).

In the second question, if the distance from point m to point b is x, s=2 x 2=2, x=2, then the coordinates of point m are (1, 0).

Proof: 1= 2

db ec (inner wrong angles are equal, two lines are parallel).

e= 4 (two straight lines are parallel, and the inner wrong angles are equal) 3= e

ad be (the inner wrong angle is equal, and the two lines are parallel).

Solution: Set the pear of basket B 3x kg, then the pear of basket A 5x kg, A and B two baskets of pears have a total of (3x+5x) kg, according to the meaning of the topic: 3x+5=7 9 (5x-5) solution x=10, 3x+5x=8x=80kg.

Therefore, the two baskets of pears in basket A and basket B weigh a total of 80 kilograms.

Grab the total weight of two baskets of pears in A and B and solve the problem.

The ratio of the second basket to the total weight of the two baskets of pears is.

3/5 (1+3/5) 3/8

The ratio of the second basket to the total weight of the two baskets of pears is.

7/9 (1+7/9) 7/16

The total weight of two baskets of pears.

5 (7/16-3/8).

5 1/16

80 (kg).

This question is very interesting, and if you don't pay attention, you will be fooled. The first mistake is that the small squares in the graph are rectangles rather than squares, which has a certain effect on the area; The second misunderstanding, there are some subtle gaps in the edges in the first figure, which is the reason why the graph combination is very loose, and it is difficult to find it if you don't look carefully (your graph is too small to see, the original picture can be seen), and the graph combination in the second figure is very tight, so leave a lot of space. That's why there is a big difference between the two pictures.

A is x, B is y

1 , y=3/5x

2, (x-5)x7 9=y+x-52 simplified to 3

7/9x-35/9=y+x-5

2/9x=y-10/9

3 , y=10/9-2/9x

Substituting 3 into 1 equals.

10/9-2/9x=3/5x

This gives 10 9 = 37 45x

x=50/37

x into equation 1.

y=30/37

Result: x+y=80 37

A total weight of 2 kg and 6 37 kg.

I won't do this kind of question next time).

During the transformation, the total weight does not change. So, at the beginning, B accounts for 3 5 of the total divided by (1 + 3 5) = 3 8, and after 5 kg is obtained, B accounts for 7 9 of the total divided by (1 + 7 9) = 7 16, therefore, the total is 5 divided by (7 16-3 8) = 80 kg.

Let A be x, then B is, as the question can be obtained.

7 9) (x a 5) =

Solution: (8 45) x = 80 9

140÷(4+3+2)=15...5

So it's a yellow flower.

Red 14 * 4 + 4 = 60

Yellow 14 * 3 + 1 = 43

Blue 14 * 2 = 28

4567 multiplied by 3s.

So the single digit is the same as 3 3 = 27, which is 711

B = 3 A 5 = A :

A-5)*7 9=A+5

Multiply 9 on each side of the equation

7A-35=A+45

A = 80 A = 50 kg.

B = 50 kg * 3 5 = 30 kg.

A 50 kg + B 30 kg = A and B two baskets of pears weigh a total of 80 kg.

B = 3 A 5

B +5 = 7 (A-5) 9

3A 5+5=7(A-5) 9

27 A + 225 = 35 A - 175

27A-35A=-175-225

8A = -400

A = 50 B = 3 (50) 5 = 30

The two baskets of pears weigh a total of 80 kilograms.

Let the weight of basket A be x and the weight of basket B be y.

You can list two equations:

y＝3/5x

y＋5＝7/9（x－5）

Solve the equation to get the value of x,y.

Add the x and y values to get the total weight of the two baskets of A and B.

You can have basket A x kg, then basket B has 3 5x kg, from which we get 7 9 (x-5).

3/5x+5

If the solution is x is 50, then the total weight is 80 kg.

Let A be x, B is 3x 5, according to the title.

x-5）7/9=3x/5+5

Solution x = 50 kg.

So B weighs 30 kg.

Total weight 80 kg.

Let be: A has x kilograms, then B has (3 5) x kilograms.

7/9)(x-5)=5+(3/5)x

x = 50 B has (3 5) x = 30 (kg).

A has 50 kg.

Solution: Let the first basket of pears be x kilograms, then the second basket of pears is 3 5 x kilograms.

x－5）×7/9＝3/5×x＋5

7/9×x－35/9＝3/5×x＋5

8/45×x＝80/9

x 50 then the first basket of pears weighs 50 kg, the second basket weighs 30 kg, and the two baskets of pears A and B weigh a total of 80 kg.

Let A have x kilograms, then B has 3x 5, x-5 = (3x 5+5)7 9

Solve the equation to get x, and then find B, and finally add it up.

Basket A weighs, (1-3 5) * 5 (1-7 9) + 5 = 50 kg, basket B weighs, 50 * 3 5 = 30 kg, two baskets weigh together, 50 + 30 = 80 kg.

If the calculation formula is set to 1 part of the first basket, there are 3 5 parts of the second basket, and the weight of the first basket of the calculation formula is:

5x(|10:7 9) (3:5-7:9).

5x16/9÷8/45

80/9x45/8

The weight of the 50kg basket is 50x3 5=30kg

The total weight of the two baskets is 50 ten, 30 = 80kg

If the weight of the basket is x, then there is.

xa 5) x7 9 = 3x 5 ten 5

7x 9 a 3x 5 = 5 ten 35 9

8x/45=80/9

x=45x80/(8x9)

x=50kg

Weight of the basket: 50 3 5 = 30

The total weight of the two baskets of A and B is 50 ten, 30 = 80kg

The total weight of the two baskets is 350 kg.

If basket A weighs x kilograms, then basket B weighs 3/5 kilograms.

3/5x+5=7/9(x-5)

Then go to the denominator and move the terms.

Get x = 50 kg.

Then 3 5x = 300 kg.

Then the two baskets of A and B are weighted together.

50 + 300 = 350 kg.

Please refer to it, thank you.

Set: A and B two baskets of pears weigh a total of x kilograms. According to the title, there is a basket of pears and a basket of pears.

1+3 5) A basket of pears.

1+7 9) (5).

x can be solved by x.

Consider the total weight of two baskets of pears as unit 1

From the fact that basket B is 3 5 of basket A, we can know that basket B is 3 (3 + 5) of the total weight of the two baskets, that is, after 3 8 takes out 5 kg from basket A and puts it into basket B, the total weight of the two baskets is unchanged, and at this time basket B is 7 9 of basket A, and it can be known that basket B is 7 (7 + 9) of the total weight of the two baskets, that is, 7 16

From the above, we can know that if you put more 5 kg into the basket, the total weight of the basket will increase from 3 8 to 7 16, that is, the score corresponding to 5 is 7 16-3 8

To require the total weight of two baskets is to find the quantity of unit 1 and divide it.

80 (kg).

The key to solving this problem is that the total weight of the two baskets remains the same.

It turns out that the basket is a few fractions of the total weight.

Now the basket is a fraction of the total weight.

A: Basket A weighs 50 kg and basket B weighs 30 kg.