Math Problem Help! 3 5 Question 5

x-7)/2-1≤2x→x-7-2≤4x→3x≥9→x≥35-2x＜15-4x→2x＜10→x＜5

The solution of the group of inequalities is:

3 x 5x=5 solutions for non-inequality groups.

x+√-x+√y-15=0

x≥0→x≥0

x≥0→x≤0

x=0 y-15=0 i.e. y=15

x+y)=√y=15

Let the waist be x, then the bottom is 18-2x, according to the title:

3x=2(18-2x)+6

Solution: x=6

That is, the waist of this isosceles triangle is 6, and the base of this isosceles triangle = 18-2x = 18-2 * 6 = 6

This isosceles triangle is an equilateral triangle.

When the waist is 8cm: 8-6=2 8 8+6=14, that is, when the waist is 8cm, it forms a triangle.

When the waist is 8cm, the circumference of the triangle = 2*8+6=22 cm, when the waist is 6cm: 8-8=0 6 8+8=16, that is, when the waist is 6cm, it forms a triangle and also forms a triangle.

When the waist is 6cm, the circumference of the triangle = 2*6+8=20 cm, and when the side of 6cm is the waist, the bottom = (30-6) 2=12 cm, that is, the bottom = 2 times the waist.

When the 6cm side is the waist, it does not form a triangle.

When the 6cm side is the base, the waist = (30-6) 2=12 cm, and when the 6cm side is the base, the 12cm side is the waist, forming a triangle.

Waist = 12cm

The length of the three sides of the triangle is: 12cm, 12cm, 6cm set the waist as XCM, then the bottom is 12-2XCM, according to the title:

x-(12-2x)=3

or: 12-2x)-x=3

x-(12-2x)=3→x=5

That is, the waist is 5cm, and the bottom is 12-2x=2cm

The waist is 5cm, and the bottom is 2cm

12-2x)-x=3→x=3

That is, the waist is 3cm, and the bottom is 12-2*3=6cm

2 times the waist 6cm

When the waist is 3cm and the bottom is 6cm, it does not form a triangle.

The length of the three sides of the triangle is: 5cm, 5cm, 2cm

3) -3<=x<5

4) x=0, y=225, and then find it yourself.

5) 20 or 22

Both are 12 and 5, 5, and 2 respectively

3.Let the radius r of the great circle and the radius r of the small garden be the area of the shaded part.

r^2-r^2 = 40

The area of the ring is r 2 - r 2= r 2 - r 2) =40 4Because the area of the two triangular rows is the same size, so.

The area of trapezoidal A1DBA and trapezoidal DCB1C1 is the same.

The area of the trapezoidal DCB1C1 is ((12-4)+12)x 3) 2 = 30

There are 16 single-layer triangles, 6 triangles made up of two-layer triangles, 3 triangles made up of three-layer triangles, 1 triangle made up of four-layer triangles, and 1 triangle made up of 5 layers So there are a total of 27 triangles in the figure.

7。Set quotient = remainder = x where x is an integer.

13·x+x>100 x>100 14>=80, so x=8,9,10,11,12

So there are 5 such numbers.

(1) 1260 7 8 1440 (yuan) 1440 1260 2700 (yuan).

2) 180 (8 7) 180 (yuan) 180 (8 7) 2700 (yuan).

3) 84 (4 2 3 2) 6 (cm) 6 4 24 (cm) 6 3 18 (cm).

24 18 432 (square centimeters).

Question 3: Subtract 4*(-4) from the square of 3

When , this equation has 3 different real roots;

When , this equation has 3 identical real roots;

When , this equation has no real roots.

Please confirm it, it feels a little strange, and let's talk about the general idea: mda= dac, nda= bad, so mdn= bac, and other angles are also provable, the three angles are equal, so they are similar.

dgc = abc, you can prove it, it's relatively simple.

Question 3: Because ab=ad,bc=cd,ac=ac, the triangle abc is all equal to the triangle adc, so the angle bac=angle dac, and because ab=ad, ap=ap, the triangle abp is all equal to the triangle adp, so pb=pd

The picture is not complete, so take a complete picture.

Question 3 (1) x = 3 2, y = 2. (2)y=o，×=9。The fifth question is a=1, b=1. The result was 9

No, it's still connected! Seriously! The volume area formula can be written out.