Regarding buoyancy physics questions, experts please come in and look at the questions

v A: v B = 3:2 If it is completely floating on water, the buoyancy ratio should be 1 1 If both balls are sunk underwater, the buoyancy ratio is 3 2, that is, so it can be determined that one floats and one sinks Because of the small size of B, it must sink in the water And A floats on the water, gravity is equal to buoyancy The solution is shown in the figure.

A density = 4 5 times the density of water.

B density = 6 5 times the density of water.

The mass is equal, the density of A: the density of B = 2:3, which means that the volume of A: the volume of B = 3:2 because the density of B is large.

There can be three scenarios, 1If both balls sink into the water, the buoyancy ratio of the water to the two balls of A and B is 3:2, which does not meet the theme.

2. Both balls float on the water, the masses of the two balls are equal, and the buoyancy is equal, which does not meet the theme.

3.A floats, B sinks, the only possibility.

The buoyancy ratio of water to the two balls of A and B is 6:5, A is buoyant = A gravity = A density * A volume * g, B is buoyant = water density * B volume * g, so A density: water density = 4:5

According to Archimedes' law, the buoyancy of an object in a liquid is equal to the weight of the liquid it distributes, then the buoyancy of this piece of iron when submerged in water is: f= water*v*g=1000*

Known: p water =

v=g=find:ffloat. Solution: F float = p water vg = =

Answer: A block of iron with a volume of 1 cubic centimeter submerged in water is subject to buoyancy.

Very simple. I don't know if your teacher said that buoyancy is equal to the weight of the liquid.

So this question can do that.

F float = f water drain = p water vg = 10 -6 * 10 3 * satisfied not?

Hello landlord.

First of all, the answer should be to choose A

Let's think in a different way. Because the external force is certain, it is the gravity of the test tube + iron block.

All buoyant drained water always has the same volume v, and iron has helped to drain a little volume.

Because the iron can be put in, you can know that all the water of the iron will naturally rise higher.

I hope you understand

The answer should be b

At the beginning, f float = total gravity.

Later, the buoyancy experienced by the plastic is equal to its gravitational force, but the buoyancy experienced by the iron block is less than its gravitational force, so the total buoyancy experienced is reduced. According to Archimedes' law, the volume of water discharged decreases. The liquid level drops.

That's because the total gravity of the tubes and the iron is constant, and the buoyancy is determined by the total volume of the water they drain. It stands to reason that the volume of water is the same for both drains.

But the previous time, because the iron was in the water, it was also buoyant by the water. The next time, the iron is in the test tube, and there is less buoyancy of the water directly on the iron. So, the tube needs to drain more water to provide buoyancy, so the water surface rises.

The answer is wrong, the liquid level should not change, and the test tube will sink.

After all submersion in water, the gravity of the water in the barrel = the buoyancy of the water, the size of the dynamometer tension has nothing to do with the water in the barrel, as long as the force of the dynamometer on the "empty" bucket is considered.

The empty barrel is balanced by force, tensile force t + buoyancy f = gravity = 10nt = 10 - f< 10 choose b

The density of the block is.

Because it is floating in the water, it is 18n in the water.

The block will sink to the bottom in the alcohol, so 2 cubic decimeters in the alcohol g=16n

It can be calculated that the density of the object is less than water, and the buoyancy in water is equal to gravity, and the buoyancy in alcohol, the density is multiplied by g and the volume is equal to.

Please, let's get a full topic.

You ignore the buoyancy of the heavy object, the heavy object also has volume, it sinks in the water to drain the water, the natural buoyancy of the water, the buoyancy of the heavy object plus the buoyancy of the balloon is the buoyancy of the whole system, you can also strive for its volume and even density according to the buoyancy of the heavy object, if you are interested, try it!! As for what you said, I don't think the bottom of the container is smooth, and it is buoyant to sink to the bottom.

The buoyancy of the object in the water is equal to the weight of the water it distributes, because the wooden block floats in the water, so the buoyancy of the wooden block is equal to its weight and is also equal to the weight of the overflowing water, so there is no need to calculate, the answer to 1 question and 2 questions is 50g.

Simple, set gold xcm3, copper ycm3

Simultaneous two systems of equations, x+y=18 (1000*, solve it yourself.)