In the spring, A is 1cm taller than B, 2cm taller than C, and 3cm taller than D. 20

In spring, A is a centimeter high, B a - 1 centimeter, C a - 2 centimeters, D a - 3 centimeters.

After a summer, all four people have grown taller, but the height of each person is different, but they have all grown a whole centimeter taller, and when the height is measured in the autumn, it is found that the four people are still 1 centimeter shorter than the other.

In autumn, the armor grew b cm and was a + b high. Ding is A+B-1 tall, and he has B+3.

Because four people are still one is 1 centimeter shorter than the other.

There are three possibilities.

The heights of 1 and 4 people are A+B, A+B-1, A+B-2, A+B-3.

B high A+B-2, C high A+B-3. or B high A + B-3, C high A + B-2.

B has B-1 and C has B-1. Or B has B-2 and C has B.

Because the height of each person's strength is different, it is not established.

The human height is a+b+1, a+b, a+b-1, a+b-2.

B high A+B+1, C high A+B-2. Or B high A + B-2, C high A + B + 1.

B has a b+2 and C has a b. Or B has b-1 and C has b+3.

Because the height of each person's strength is different, it is not established.

The height of the person is a+b+2, a+b+1, a+b, a+b-1.

B high A+B+2, C high A+B+1. Or B high A+B+1, C high A+B+2.

B has a b+3 and C has a b+3. Or B has b+2 and C has b+4.

Because the height of each person's strength is different, B has a b+2 and C has a b+4 to stand.

C is high A+B+2, C is the highest.

Except for D, the other 3 people are all possible, only saying that they have grown an integer centimeter, and they do not say who grows faster or as fast, they can grow as long as they want, and anyone in A, B and C can grow to the first height

A, B, and C may all be the first. What's the problem...

Let A, B, C, and D be A+3, A+2, A+1, AAfter a summer, A grows B(A+3+B), and D has A+B+2 and B+2

If B is now 1cm taller than A, then B is A+B+4, then B also has B+2, which is contrary to the original question.

If C is now 1cm taller than A, then C is A+B+4, then C has B+3: if B is the highest, then B is A+B+5, and B+3 is long, which is the same as C's length, which is contrary; When C is the highest, then B is a+b+1, and b-1 is long, which is in line with the title, and C is the highest.

If now A is the highest: when B is after D, then B is A+B+1 and has B-1, then C is A+B, and B-1 is long, and B is the same length as C, which is contrary; When C is after D, C is A+B+1, and B is long, which is the same as A's, which is contrary to A's length.

To sum up, C is the highest.

Let A, B, C, and D be 4, 3, 2, 1 respectively, and later become:

C, A, D, B.

Grow taller respectively: 5 2 4 3

So. C is the highest.

Set the armor to a centimeter.

So, B is A-1, C is A-2, and D is A-3

Later, A is A+X, and D is A+X-1

B is a+x+1 and C is a+x+2

Or C is a+x+1 and B is a+x+2

The topic is incomplete.

I guess different combinations of numbers will have different answers.

For example, A, B, C, and D were originally respectively and have grown taller respectively, that is, A, B, C, and D are now respectively . Then now it is Ding the highest.

And it's not an ordinary cowardice. It's no use telling them.

Spring: Xiao Ming, Xiao Qiang, Xiao Jun, Xiao Hua.

3 2 1 0 Autumn: Set Xiao Ming to open xcm

The order may be:

Xiao Ming, Xiao Hua, Xiao Jun, Xiao Qiang.

x x+2 x x-2 does not set up Xiao Ming, Xiao Hua, Xiao Qiang, Xiao Jun.

x x+2 x-1 x-1 does not form a small army Xiaoqiang Xiaoming Xiaohua.

x+4 x+2 x x+2 does not form Xiaoqiang, Xiaojun, Xiaoming, Xiaohua.

x+3 x+3 x x+2 does not form Xiaoqiang, Xiaoming, Xiaohua, Xiaojun.

x+2 x x+2 x do not form a small army Xiao Ming Xiao Hua Xiao Qiang.

x+3 x x+2 x-1 is established, so the army is the highest

So the answer is: small army