High Score Reward Senior 2 Chemistry !! A calculation problem! HELP！！！！！

It's C5H10

2H2O+2Na2O2=4NaOH+O2(gas) Weight gain.

x 2x2CO2+2Na2O2=2Na2CO3+O2 weight gain.

y 28y, because the H2O of xmol is obtained by the reaction of O2 (conservation of oxygen atom), and the CO2 of ymol is obtained by the reaction of O2 of ymol (conservation of oxygen atom), so the remaining O2 of this hydrocarbon after combustion is (

2x+28y=15

x = so the hydrocarbon is burned to form CO2, H2O

Since 1mol of this hydrocarbon contains C 5mol and H 10mol, the molecular formula is C5H10

CO2 passes through Na2O2 to get 1 2O2, weight gain 44-16 = 28H2O through Na2O2 to get 1 2O2, weight gain 18-16 = 2 So let the molecular formula CxHy be produced, then oxygen is consumed.

The equation is .

28*So x=5, y=10

So the chemical formula is C5H10

I made a big mistake just now and forgot to include oxygen.

2CO2 + 2Na2O2 = 2Na2CO3 + O2 per 2mol CO2 reaction solid weight gain 2*44-32=56g, gas volume decreased by 1mol

2H2O+2Na2O2=4NaOH+O2 The weight of the reaction solid is 2*18-32=4g per 2molH2O, and the gas volume is reduced by 1mol

Let the original molecular formula be CXHY

CXHY+(X+Y 4)O2=ignition=XCo2+Y2 H2O, then there is +

The original volume of the gas is the volume of O2 that is reacted with the volume of CO2 that is reacted to form and finally the volume of O2 that is formed.

The reaction to form H2O and the final volume to form O2 Final volume.

56*So x=5, y=10, so the molecular formula is C5H10.

Calculate it yourself. The solid is sodium carbonate, and the gas is oxygen

Note that the last gas has CO2 and O2 in it.

It is necessary to start with heavy nao2

If you ask the teacher, you will say the same.

Hehe. I know that liters are one mol.

cxhy+(x+y/4)o2=xco2+y/2h2o(x+y/4)

2Na2O2+2CO2=2Na2CO3+O2 weight gain 44*2-32=56

2Na2O2+2H2O=4NaOH+O2 weight gain18*2-32=44*

Let's figure it out for myself, I don't have a calculator in my hand.

By the title of the equation:

1: 2Fe + 6H2SO4 = Fe (SO4) 3 + 6H2O + 3SO2 2: Fe + H2SO4 = FeSO4 + H2

Let the generation of 3SO2 be xmol and the generation of h2 be ymol, has: x+y=

and 64x+2y=

Get x=, y=

1) If there is no iron powder left, then 20x 3+y=30 56 contradicts x+y=, so there is a surplus.

2) The amount of sulfuric acid is: 6 3 * x + y = the concentration of concentrated sulfuric acid is:

naoh+nahco3===na2co3+h2o11

z y is the remaining sodium hydroxide after the reaction with sodium bicarbonate.

CaCO3 == High temperature == Cao + CO2

x solution gives x = 8

The mass fraction of calcium carbonate in this calcium supplement tablet = 8 10 * 100% = 80% is conserved according to mass.

10+y= The mass of dilute hydrochloric acid added before the solution reaction y=100 grams.

1. Calculate the amount of the substance n according to the amount of carbon dioxide collected; It is also the amount of the substance of calcium carbonate, thus calculating the mass of calcium carbonate. 2. The mass fraction of calcium carbonate in calcium tablets is equal to the mass of calcium carbonate divided by 10 grams, 3. Calcium carbonate and hydrochloric acid are a one-to-two reaction, and the amount of calcium carbonate is known to know the hydrochloric acid, and you can find it!