What is the role of the ratio of the strength of the longitudinal reinforcement to the stirrup, and

Purpose of reinforcement strength ratio: due to the torsion reinforcement by closing stirrups.

and torsional longitudinal reinforcement, and the proportion of the reinforcement has a great influence on the torsional performance and ultimate torsional bearing capacity. In order to make the stirrups and longitudinal bars play an effective role, the quantity and strength of the two parts of the reinforcement should be controlled, that is, the reinforcement strength ratio of the two parts of the reinforcement should be controlled.

The reinforcement-strength ratio can be defined as the product of the volume ratio and strength ratio of the torsional longitudinal bars and stirrups According to the test results, at that time, the longitudinal bars and stirrups can basically reach the yield strength when the torsional member is damaged.

However, the difference between the two types of reinforcement should not be too large.

gb50010;2010) recommendations should be met:

According to my understanding, it is to ensure that the longitudinal bars and stirrups of the torsional member can fully function. Experiments show that when in the range, the longitudinal reinforcement and stirrups of reinforced concrete can basically reach yield strength when torsional members are damaged. For the sake of prudence, the norms restrict it as follows:

When approaching, the reinforcement reaches the optimal value for yield. Due to the need for the balance of internal forces in the cross-section, only the symmetrically arranged longitudinal reinforcement cross-sectional area is taken in the calculation for the situation where the longitudinal reinforcement cross-sectional area is configured for the troops. (See GB50010-2010 for details).

The parameter reflects the relative relationship between the longitudinal reinforcement and the stirrups in the number and strength of the torsional member, which is called the reinforcement strength ratio of the longitudinal reinforcement and stirrups, that is, the product of the volume ratio and the strength ratio of the longitudinal reinforcement and stirrups. AST1 is the cross-sectional area of a single limb of the stirrups, and S is the spacing of the stirrups, which corresponds to the volume of a stirrup AST1UCOR (UCOR = 2BCOR + 2HCOR) The volume of the longitudinal bars is ASTL S (ASTL is the cross-sectional area of all longitudinal bars arranged symmetrically within the section), then = FYASTL S FYV AST1UCOR. The test shows that only when the value is within a certain range, can the strength of the longitudinal reinforcement and stirrup be fully utilized when the component is damaged.

The specification requires that the value should meet the conditions of . When >, take =.

Make sure that the "plastic hinge" appears at the beam end! Look at the textbook specifically!

Answer]: The ratio of the strength of the longitudinal reinforcement to the stirrups in the first combustion of the torsion: the ratio between the strength of the torsional longitudinal bars in the unit length of the core perimeter of the section and the strength of the torsional stirrups in the unit length along the length of the component, or the product of the volume ratio of the longitudinal bars to the stirrups to the strength ratio.

Summary. When the strength ratio of torsional longitudinal bars to torsional stirrups is =3, the general failure form is stirrup slip failure. At this point, the concrete generates a large amount of shear stress around the stirrups, causing the iron bars to slip and causing the concrete to produce axial extrusion above the stirrups.

At the same time, the lateral expansion capacity of the concrete around the stirrups is limited due to axial compression, which leads to failure. In the actual project, it should be considered comprehensively according to different situations to ensure the safety of the structure.

What is the failure when the reinforcement strength ratio of torsional longitudinal bars and torsional stirrups = 3.

I'm sorry I don't understand, but can you elaborate on that?

When the disturbing strength ratio of torsional longitudinal bars and torsional stirrups is =3, the general failure form is stirrup slip and breaking. At this point, the concrete generates a large amount of shear stress around the stirrups, causing the iron bars to slip and causing the concrete to produce axial extrusion above the stirrups. At the same time, the lateral expansion capacity of the concrete around the stirrups is limited due to axial compression, which leads to failure.

In the actual project, it should be considered comprehensively according to different situations to ensure the safety of the structure.

Summary. Hello dear when o>f long side midpoint first cracked, then.

Stretch out to the upper and lower short sides, forming a space distortion surface that is tensile on three sides and compressed on the surface, and the component is broken.

Bad, brittle failure. Cracking torque with breaking.

The torques are basically equal.

If the shear stress value reaches the ultimate strength at a certain point of the cross-section, the entire component is considered to be damaged. Section.

The shear stress at the midpoint of the long side is: tmax

wh/b=1~10,=

ter ahb'f.

Formula for the strength ratio of longitudinal reinforcement to stirrup reinforcement of torsional members.

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<> dear, hello When the midpoint of the long side of O>F is cracked first, and then stretched to the upper and lower short sides, it forms a space distortion surface that is rounded on three sides and compressed on the surface, and the component is broken and broken, showing brittle failure. If the shear stress value of the shear stress value at a certain point of the cross-section is equal to the breaking torque and the basic line answer of the cracking torque reaches the ultimate strength, it is considered that the whole component is broken. The shear stress at the midpoint of the long side of the cross-section is:

tmax≤,= ahb'f.

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In the reinforced concrete beam, it is generally equipped with longitudinal stressed steel bar, stirrups, bent steel bar, and erection steel bar.

Longitudinal stressed reinforcement: used to follow the tensile force generated by the bending moment in the beam, stirrup effect: used to bend the steel bar with the main tensile stress caused by the shear force and bending moment in the beam

In addition to the tensile forces generated with the positive bending moment in the span, the bending section close to the support is used to withstand the main tensile stresses due to the bending moment and shear forces.

Erection reinforcement appointment: in order to fix the correct position of stirrups and form a reinforcement skeleton on both sides of the outer edge of the compression zone of the beam, parallel to the longitudinal stress reinforcement to arrange the erection reinforcement, in addition, the erection reinforcement can also withstand the stress caused by temperature change and concrete shrinkage, to prevent cracks.

Concrete beam stirrup effect:

fix the position of each longitudinal reinforcement to make it a regular reinforcement cage that conforms to the calculation model;

constraining concrete, which constitutes a prerequisite for the calculation of the requirements of the code;

What is important is the shear bearing capacity of the oblique section of the beam that is made up with concrete.

The role of the longitudinal reinforcement of the concrete beam:

The upper part is long rib to meet the basic structural measures of seismic resistance; It can also be used as a erection rib; It can also be used as a negative reinforcement effect.

Erect bars, erect stirrups to make it a regular steel cage.

Negative bars bear the strong tensile force generated by the action of negative bending moment.

Construct waist tendons, connect the waist of the longer hoop limbs, and jointly ensure that the reinforcement cage is regular.

Torsional waist tendon resists the shear stress caused by the torque of the beam body.

6.The bottom reinforcement bears the strong tensile force generated by the action of the positive bending moment.

Meters of suspended beams 4 16 miles of steel bars can be picked.