Chemical organic calculations, about the calculation of organic compounds

Solution: Let the molecular formula of the organic matter be cxhyoz and the relative molecular mass is m

cxhyoz + x + y/4 - z/2)o2 → xco2 + y/2h2o

The quality of the water is grams.

In water, m(h)=

In carbon dioxide, m(c)=

Before and after the reaction, the mass of the carbon element and the hydrogen element does not change, so the mass of the oxygen element contained in the organic matter is then its number =

The ratio of the atoms of the three elements (C, H, O): =1:3:1, that is, the molecular formula of the organic substance is (the simplest): CH3O

However, from "if the same amount of organic matter is completely dissolved in water, 150ml of 2mol l of solution can be obtained": the amount of the substance is n(cxhyoz)=2*

So, m = i.e. the substance is C2H6O2

m/m÷

m= The molecular weight of organic matter is m=62 Since the number of carbon and hydrogen has been calculated, how much oxygen is calculated according to the difference in molecular weight.

You've missed one condition.

From the water calculated h atom mograms.

From carbon dioxide is calculated as a c atom in mograms.

Their mass is 9 grams.

Subtract with total mass.

Oxygen atomic mass grams.

The amount of their substances is divided by the amount of raw organic matter obtained from the solution after the reaction.

There should be 2 carbon atoms, 6 hydrogen atoms, and 2 oxygen atoms.

There are two kinds of chain-like saturated monools of A and B, and their mass is. It is known that the number of carbon atoms of both a and b is not greater than 4 and that the number of carbon atoms of a is less than.

What is the possible molecular formula of a in a mixture? What are the possible molecular formulas? 2. If n(a):

When n(b)=1:1, what is the name of a and what is the name of b? 3. If n(a):

When n(b)≠1:1, what are the structural shorts of a and b? and find n(a):

The value of n(b)? I must talk about it in detail because I am not very good at this kind of question, o ( o thank you.

Acetic acid is C2H4O and ethylene is C2H4

Oxygen accounts for A, so CH2 accounts for 1-A

So the mass fraction of c = 12 14a = 6 7a

(1) Let the average chemical formula of the mixed gas be CXHY, according to the meaning of the title, we can know that y=7, then the number of hydrogen atoms in a and b is between the two sides of 7, and then according to the meaning of the title, the number of carbons in b is greater than a, and they are all gases, and the number of carbons is less than or equal to 4, so if the h of b is greater than 7, then it is C4H8, A is CH4, and the ratio of C2H6 is C4H8:ch4=3:1, C4H8:

C2H6 = 1:1, if the h of b is less than 7, then it is C2H4, C3H6, A is C3H8 C4H10, but because the carbon number of B is less than A, it is excluded.

2）cxhy+(x+y/4)o2→co2+y/2h2o2l (2x+y/2)

For a, y=2x+2 then there are 2x+y 2=3x+1 or x3 or x3 respectively according to the requirements in the question b c more than a and are all gases, so only 2x+y 2=3x+1, or x 3, ch4 c2h6 can be selected, at this time for b can only choose c4h8, because only 2LC4H8 COMPLETELY BURNS THE OXYGEN NEEDED, SO A IS CH4 OR C2H6, B IS C4H8.

Complete combustion means that there is no residual reaction between the organic matter and oxygen, and the production of stable products carbon dioxide and water, the water generated after the combustion of organic matter is vaporized into water vapor, after the clarification of lime water, carbon dioxide reacts with calcium hydroxide, water vapor is absorbed, Ca(OH)2 CO2 CaCO3 H2O, the molar mass of CaCO3 is 100, so the amount of CO2 is equal to the amount of CaCO3, so the original organic matter contains, the molar mass of CO2 is 44, So the mass of CO2 is, the mass of this water should be equal to, and the molar mass of water is 18, so the amount of water is , where it contains hydrogen, c and h altogether, and the remaining mass of the original organic matter, that is, the mass of O, is, the molar mass of O is 16, and the amount of the substance of this o is , so c:h:o::3:1

10g of precipitation indicates that there is generation, containing carbon.

Ca(OH)2 + CO2 = CaCO3 + H2O74 44 100 18 Amount of change = 18-74 = -56

The weight gain of 10g lime water is due to the incoming of the generated water, so the weight gain = the incoming water (the water generated by combustion), so the combustion produces water. Water. It feels like there's something wrong with the data you're gaving. It is impossible for so much water to generate.

The lime water weight gain indicates that the H2O CO2 produced is 10 grams of filtered precipitate, and CaCO3 10 grams of Ca(OH)2 + CO2 = CaCO3 + H2O44 100

10 can be known as CO2 H2O

and according to the conservation of carbon then carbon gram according to h conservation then hydrogen contained:

The organic matter containing c g h o g is reduced to the simplest form: ch3o can meet the organic matter of this minimum form.

If there is only C and H, then all the water and carbon dioxide generated are. And the precipitate is 10g' of calcium carbonate, so carbon dioxide is 10 100=, then water is. Then carbon is and hydrogen is 2 18* then c:

h=1:3。But not equally.

So there is を. then o is, yes, then c:h:

o=1：3：1。

Equation: Ca(OH)2+CO2=CaCO3+H2O74 44 100 1810g

I have not been organic for many years, please point out something wrong, just for reference)

First of all, lime water gains weight because it absorbs carbon dioxide and water. The mass of the carbon dioxide absorbed by the mass of the precipitated substance is, the mass is grams, so the mass of the absorbed water is grams, the mass of the carbon element in the organic matter is, the mass of the hydrogen element is, so the mass of the oxygen element is, the oxygen atom.

So c:h:o=:::3:1

Organic combustion, the product is water and CO2, the question is given to the total, the precipitation is calcium carbonate 10g, using the equation to produce calcium carbonate, the ratio of mass to relative molecular mass, x 44 = 10 100, x is the mass of CO2, then water. That is, c has Mo, H has Mo, C:H=1:

3，…There are many solutions....Help with this.

It is known that m(caCO3) = 60g

n(caco3)=60/100=

So both hydrocarbons contain carbon atoms in them.

And because the mass of A at the same temperature, pressure and volume is 13 times the mass of H2, the relative molecular weight of A is 2*13=26

A and B have a vapor density ratio of 1:3 under the same circumstances, so the relative molecular weight of B = 26*3 = 78

So n(a)=

Therefore, the number of carbon atoms in molecule A = and the molecular formula is C2H2N(B)=

So the number of carbon atoms contained in molecule B = and the molecular formula is C6H6

The whole combustion of the bridge is increased by concentrated sulfuric acid, so the H2O mass is, and the amount of the substance is.

Then through the soda lime weight gain, so the mass of CO2 is, the amount of matter is according to the law of conservation of mass, the mass of oxygen consumed is, the amount of matter is H2O and the amount of oxygen-containing atomic substances in CO2 is.

The amount of oxygen-containing atomic material participating in the reaction is <2mol, indicating that the original organic matter also contains oxygen elements.

The ratio of the number of carbon, hydrogen and oxygen atoms in organic matter is: (:8:1).

The molecular formula is C3H8O

Let the molecular formula be cxhy

The mass ratio of hydrocarbons is 24:5

Then the ratio of the number of hydrocarbon atoms is x:y=(24 12):(5 1)=2:5, and the density in the standard condition is.

then the molar mass is (

12x+y=58

x:y=2:5

The solution is x=4 and y=10

The molecular formula is C4H10