Saved a few chemical equations, help 20

Only looked at one.

Chloric acid is HCO3.

In the generated substance, the gas that turns red in the air is NO, and the redox reaction occurs during the reaction, in which the valency of iron increases by one valence, and the valency of N in nitric acid decreases by 3 valence, and the dosage ratio of FeC2O4*2H2O to HNo3 is 3:1, considering that K2C2O4 on the left contains two Ks, and K3 Fe(C2O4)3 *3H2O contains 3 Ks on the right, FeC2O4*2H2O and Hno3 coefficient ratio is 6:2, and the trim Fe, FE3 Fe(C2O4)3 * The coefficient of 3H2O is 6, the coefficient before trim K, K2C2O4 is 9, the coefficient before trimming oxalate (or C), H2C2O4 is 3, look at H, there is 32 on the left, 36 on the right, add 2 H2O on the left, and finally look at oxygen, both sides are equal.

6fec2o4*2h2o+2hno3+9k2c2o4+3h2c2o4+2h2o=6k3［fe(c2o4)3］*3h2o+2no↑

The correct one should be: +4Hno3 ==Fe(NO3)3 + 2CO2 + No +4H2O

It does not form complexes, and Hno3 is highly oxidizing and can oxidize oxalate.

3 fec2o4·2h2o + 5 k2c2o4 + h2c2o4 + 2 hno3 + h2o= 3 k3[fe(c2o4)3]·3h2o + no↑ +kno3

The gas that turns red in the air is NO, so in this question, HNO3 acts as an oxidant, and itself is reduced to NO, and ferrous oxalate FeC2O4 is oxidized to trivalent potassium trioxalate ferrite.

Only the valency of iron and nitrogen has changed! Then you turn the hydrogen peroxide into nitric acid, just add a no to the product, and then use the valence change to equalize. It's going to be uneven!

Therefore, it can be inferred that a substance was also generated, and that is potassium nitrate (nitric acid is more acidic than oxalic acid)! So you can trim it! Equations Write Your Own and Trim It!

The final product also has a potassium nitrate, and this equation is leveled by valence.

Reaction of copper with concentrated nitric acid.

Cu4HNO3 (concentrated) =

cu（no3）2

2no2↑2h2o

Reaction of copper with dilute nitric acid; 3cu ＋8hno3＝3cu（no3）2＋2no↑＋4h2o

Reaction of copper with concentrated sulfuric acid; Cu 2H2SO4 (concentrated) Cuso SO2 2H2O

The reaction of iron with concentrated nitric acid must be heated, and it is passivated at room temperature, Fe is insufficient, Fe + 6Hno3 (concentrated) = ΔFe (No3) 3 + 3H2O + 3 No2

Fe excess, Fe + 4Hno3 (concentrated) = δFe (No3) 2 + 2H2O + 2 No2

Reaction of iron with dilute nitric acid.

Fe is insufficient, Fe + 4Hno3 = = Fe (No3) 3 + 2H2O + NO

Fe excess, 3Fe + 8Hno3 = = 3Fe (NO3) 2 + 4H2O + 2 NO

The reaction of iron with concentrated sulfuric acid must be heated, and it is passivated at room temperature.

Fe 6H2SO4 (concentrated) ==Fe2 (SO4)3

3SO2 6H2O iron with dilute sulfuric acid) Fe H2SO4 FeSO4 H2

They are all redox reactions, and it is relatively simple to match them with the total number of valence rises and falls equally.

1. C + O2 = ignition = CO2

2. H2+CuO= =Cu+H2O

3. Zn+H2SO4=H2 +ZnSO4, H2O=Power-on=H2 +O2

4. CO2 + H2O = H2CO3

5. CO+CUO=δ=CU+CO2

6. Fe+CuSo4=Cu+FeSo4

7. There are two ways to write the chemical equation of ethanol, which one you choose depends on your textbook (the composition of hydrogen atoms is different, so the equation is different):

C2H6O+3O2=Ignition = 2CO2 + 3H2O C2H5OH+3O2= Ignition = 2CO2 + 3H2O Octa, 2mg+O2= Ignition = 2mgo

9. CH4 + 2O2 = ignition = CO2 + 2H2O ten, CO2 + Ca(OH)2 = CaCO3 + H2O eleven, 3CO + Fe2O3 = high temperature = 2Fe + 3CO2 twelve, H2CO3 = CO2 + H2O

13. C + 2Cuo = high temperature = 2Cu + CO2 14. 2H2 + O2 = ignition = 2H2O

What about the reaction? At least give the reactants and conditions......

1. C+O2=ignition=CO2

2、h2+cuo=δ=cu+h2o

3、zn+h2so4=h2↑+znso4

4、co2+h2o=h2co3

5、co+cuo=δ=cu+co2

6、fe+cuso4=cu+feso4

7. C2H6O + 3O2 = ignition = 2CO2 + 3H2O mg + O2 = ignition = 2mgo

9. CH4+2O2=ignition=CO2+2H2O10, CO2+Ca(OH)2=CaCO3 +H2O CO+Fe2O3=high temperature=2Fe+3CO212, H2CO3=CO2+H2O

13. C+2CuO=High temperature=C2U+Co H2+O2=Ignition=2H2O

Conditional Ignition Conditional Heating Gas Arrow+FeSO4 Conditional Heating.

Conditional Ignition Conditional Ignition Conditional Ignition Precipitate +H2O

Conditional heating. Conditional Heating Conditional ignition.