Dad is 43 years old, daughter is 11 years old, a few years ago the daughter was 20 years old ?

Dad is 40 years old, daughter is 8 years old.

That is, 3 years ago.

Solution: Suppose the daughter was 20% of the father's before x

11-x20％（43-x)

Answer: 3 years ago, my daughter's age was 20 of my father's.

Each subtracts three years old, the father is 40 years old, and the daughter is 8 years old, exactly 20%.

I will answer it myself, and I hope for it.

Solution: Let the daughter's age be 20% of the father's before x, and the equation can be obtained:

43-x）×20%=11-x．，x=3；

A: Three years ago, my son was 20% of my father's age

Solution: Suppose the daughter's age was 20% of her father's before x.

43-x)*20%=11-x

x = 33 years ago, the daughter's age was 20% of her father's

Let x years ago, then the father is 43-x, then the daughter is 11-x, (43-x)*, you can calculate, x=3, is it okay? I don't know how to ask again.

Three years ago, Gozen. How many years ago, the age of the daughter was 20% of the father's, in other words, the father's age was 5 times that of the daughter. The age difference between the father and the daughter will not change, when the father's age is 5 times that of the daughter, the father's age is 4 times older than the daughter's age, and these 4 times is the age difference between the two, so the age of the daughter of the year is (43-11) (5-1) = 8 years old, this year's daughter is 11 years old, and the town is stupid and clear that the age of the daughter is 11-8 = 3 years ago is 20% of the father's.

3 years ago. At this time, a math equation problem can be set to x a few years ago, according to the equation of (43 x) 20 11-x according to the fact that the father is 43 years old and the daughter is 11 years old this year.

If x is equal to 3, then three years ago, the daughter's age was 20% of her father's slender hand.

Set x years ago, my daughter's age was 20% of that of my father, Yuming Wang's father

43-x) 20% = 11-x 20% approximate.

43-x)1 5=11-x Equation: Huaizhou on both sides of Zhenzi multiplies 543-x=11*5-5x shift.

5x-x=55-43

4x = 12x = 3 years.

A: 3 years ago, my daughter's age was 20% of her father's

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3 years ago. Suppose the daughter's age before x was 20% of her father's, then there is 11-x=(43-x)*, and the solution is x=3. That is, three years ago, the daughter was 8 years old, the father was 40 years old, and the daughter was 20% of the father's age.

Hello, three years ago, my daughter was 8 years old and my father was 40 years old, and my daughter's age was just one-fifth of her father's age, which was 20%. Don't hesitate to adopt!

Suppose the daughter is x years old, 5x-x=43-11, x=8, 11-8=3, i.e. 3 years ago.

Three years ago, my daughter's age was 20 percent of her father's. Three years ago, my daughter was 8 years old and my father was 40 years old. 20 percent means 1 5Then 8 40 = 1 5

Set: Daughter's age x a few years ago.

11x = 43 times 20 percent

11x = approximately equal to 9].

x = 9 divided by 11

x is approximately equal to 1 year

Simple question: Just make an equation.

Just set x years ago, the daughter's age was the same as the father's.

Set x years ago, the daughter's age was 20% of the father's, from the title.

11-x)*5=43-x

55-5x=43-x

4x=12x=3

Three years ago, my daughter's age was 20% of her father's

Three years ago. Dad is 40 and daughter is 8 years old.

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Three years ago, my daughter was 8 years old and my father was 40 years old.

Suppose x years ago, the daughter's age was 20% of the father's, and the inscription showed that (11-x)*5=43-x

55-5x=43-x

4x=12x=3Three years ago, the daughter's age was 20% of her father's

Set to x years ago, then (43-x)*20%=11-x

The solution is x as 3

Three years ago, my daughter was eight years old and my father was forty.