Hydrogen peroxide is often used to disinfect bleaching, and its advantages are:

Advantages of hydrogen peroxide for oxygen production:

1. No heating, saving energy.

2. The response speed is fast and saves time.

3. The experimental device is relatively simple.

4. The product is water, no pollution, clean!

The effect is good, there is no pollution (generating water), and the preparation method is relatively simple.

1) With the increase of the solute fraction of hydrogen peroxide, the reaction rate accelerated.

2) Exothermic. 3）2h2o2=2h2o+o2

500×17%=85（g）

85÷（34×2）×32=40（g）

Theoretically, 40 grams of oxygen can be produced.

1) As can be seen from the diagram, the equation of the reaction is H2O2 catalyst H2O2 when ethylanthraquinone is used as a catalyst to produce hydrogen peroxide

So the answer is: h2

O2 catalyst H2O2

2）c=1000ρω

m1000×1g/l×5%

34g/mol

mol l, so the answer is: mol l;

3) From the image, it can be seen that the decomposition rate is the largest under alkaline conditions, and it can be seen that the higher the pH of the solution, the faster the decomposition rate of hydrogen peroxide, so the answer is: keep other conditions unchanged, the greater the pH of the solution, the faster the decomposition rate of hydrogen peroxide;

4) Redox reactions occur to produce oxygen and Mn2+

The ionic equation is 2mNO45H2O2

6h+2mn2+

8H2O+5O2, so the answer is: 2mNO45H2O26H+2MN2+

8h2o+5o2

Finished. According to the reaction 2mNO45H2O2

6h+2mn2+

8h2o+5o2

n（h2o2

?l-1c（h2o2

mol l, so the answer is: mol l;

Hydrogen peroxide solution is a strong oxidant, which has the functions of disinfection, antiseptic, deodorization and cleaning, and is used to clean wounds, ulcers, pus sinuses, and pus in the ear; Coating of ** facial brown spots (liver spots); a dressing to remove the crust and adhere to the wound during dressing changes (to reduce pain); Dilute to a concentration of 1% for tonsillitis.

Gargling of stomatitis, diphtheria, etc. Hydrogen peroxide solution is indicated for purulent otitis externa and otitis media.

Vincent's stomatitis, gingival pus-leakage, tonsillitis and cleaning wounds. And when the hydrogen peroxide solution meets **, wounds, pus or dirt in the mouth and mucous membranes, it decomposes to oxygen. This oxygen atom, which has not yet been combined into oxygen molecules, has a strong oxidizing ability, and when it comes into contact with bacteria, it can destroy the bacterial body and kill the bacteria.

In addition, a 2% 3% solution of liquid hydrogen peroxide is often used in oral medicine as a rinsing drug. For example, in the root canal surgery of oral medicine, hydrogen peroxide is used when the root canal is expanded.

Often with normal saline (sodium chloride solution.

Use them together alternately. At the same time, hydrogen peroxide solution is also one of the essential drugs for pericoronal irrigation. Since most of the infections in the oral cavity come from anaerobic bacteria, hydrogen peroxide solution is widely used in oral clinical medicine due to its oxygen production.

a. Hydrogen peroxide encounters and manganese dioxide will decompose under the catalysis of manganese dioxide, so it will lead to the deterioration of sodium percarbonate crystals, so A is wrong;

b. Hydrosulfuric acid and sodium carbonate can react, which will lead to the deterioration of sodium percarbonate crystals, so B is wrong;

c. Dilute hydrochloric acid can react with sodium carbonate to generate carbon dioxide, so hydrochloric acid will cause sodium percarbonate crystals to deteriorate, so C is wrong;

d. Sodium bicarbonate will not react with sodium carbonate and hydrogen peroxide, so sodium bicarbonate will not cause sodium percarbonate crystal deterioration, so D is right

Therefore, choose D

(1) Volumetric flasks are required to prepare a solution with a certain concentration of substance, so the answer is: volumetric flask;

3) The acidic potassium permanganate solution is acidic, so it should be contained with an acid burette, and the phenomenon of the end point of the titration is: drop a drop of potassium permanganate solution, the solution is red, and it does not fade within half a minute, so the answer is: acidic, drop a drop of potassium permanganate solution, the solution is red, and it does not fade within half a minute;

4) Let the mass of hydrogen peroxide in 25ml hydrogen peroxide solution be X, 5H2O2 + 6HCl + 2KMno4 = 2mnCl2 + 2KCL + 5O2 + 8H2O

170g 2mol

x 10-3cvmol

x= cvg

Then the mass of hydrogen peroxide in 250ml of hydrogen peroxide solution is CVG, and the mass of hydrogen peroxide solution is 10 g, so its mass fraction = CVG

10ρg100%=17cv

2 %, so the answer is: 17cv

ii If hydrogen peroxide can make the starch potassium iodide solution turn blue, it means that hydrogen peroxide oxidizes iodine ions to produce iodine element, and iodine turns blue when it meets starch, so it can prove that hydrogen peroxide is oxidizing;

If hydrogen peroxide is heated to produce a substance that can rekindle the spark-bearing sticks, it means that hydrogen peroxide decomposes to oxygen, so it can prove that hydrogen peroxide is unstable, so the answer is:

Experimental content. Experimental Methods.

Experimental phenomenon. Verify oxidation.

The solution turns blue.

Verify instability.

Take an appropriate amount of hydrogen peroxide solution in a test tube, heat it, and test it with a wooden strip with sparks

1) The name of the instrument: separating funnel, drying tube, Erlenmeyer flask;

2) In a, hydrogen peroxide and manganese dioxide react to produce water and oxygen, and the chemical reaction equation is 2H2O2MNO

2h2o ten o2

3) B is to dry oxygen, and the bottle is liquid, so it is concentrated sulfuric acid;

4) Device C can be used to check whether the oxygen is dry, that is, to check whether there is still water, so it is necessary to use a white anhydrous copper sulfate solid to observe whether it turns blue

5) The method of oxygen filling is to use a wooden strip with sparks to lay flat on the mouth of the gas collection cylinder to observe whether the wooden strip rekindles

6) Device A does not need to be heated, and can also produce carbon dioxide and hydrogen, and combined with the collection method of device D, it can only be carbon dioxide

So the answer is: (1) a separating funnel; Drying tubes; Erlenmeyer flask;

2）2h2o2

mno2h2o ten o2

3) Concentrated H2SO4

Remove water from oxygen (or dry O2

4) Anhydrous copper sulfate; The drug in the drying tube does not change blue;

5) Use a wooden strip with sparks close to the mouth of the gas collector bottle, if the wooden strip is rekindled, it proves O2

Collected; 6）co2

(1) The volumetric flask is a constant-volume instrument, which can accurately measure 250ml of liquid, so the answer is: volumetric flask;

2) Hydrogen peroxide exhibits strong reducing properties when it encounters a strong oxidant potassium permanganate, and the essence of the reaction is: 2mnO4

5h2o2+6h+=2mn2++8h2o+502, so the answer is: 2; 5；6；2；8；502 ；

3) Potassium permanganate itself is a purple-red liquid, when the potassium permanganate standard solution is injected into the burette to titrate hydrogen peroxide, when the titration end point is reached, the solution is purple-red, and does not fade within 30 seconds, so the answer is: drop the last drop of potassium permanganate solution, the solution is purple-red, and does not fade within 30 seconds;

4) According to the equation for the reaction of potassium permanganate and hydrogen peroxide, let the amount of hydrogen peroxide be n, then.

2mno4+5h2o2+6h+=2mn2++8h2o+502

cv×10-3mol n

Then 2cv 10

3mol＝5n

The solution is n=so the mass of hydrogen peroxide=, the mass of hydrogen peroxide=, then the mass fraction of hydrogen peroxide is:

10 g100%=, so the answer is:

(5) There are bubbles in the tip of the burette before titration, and the bubbles disappear after titration, the volume of bubbles is included in the amount of standard solution, which is equivalent to the use of more standard solution, so the result is high, so the answer is: high

Hydrogen peroxide has oxidizing properties, can oxidize reducing sulfur ions to elemental sulfur, to optimize its oxidation, it can be reacted with reducing hydrogen sulfide or potassium iodide, the specific operation is: take an appropriate amount of saturated hydrogen sulfide solution in the test tube, drop into the hydrogen peroxide solution (take an appropriate amount of potassium iodide starch solution in the test tube, add hydrogen peroxide solution), hydrogen peroxide can oxidize sulfur ions to sulfur element, iodide ions can be oxidized to elemental iodine, iodine elemental starch turns blue; Hydrogen peroxide is unstable, heating will produce water and oxygen, oxygen can rekindle the wood strips, and can react with hydrogen sulfide to form a desalinated precipitated sulfur element, so the answer is: experimental content.

Experimental Methods.

Experimental phenomenon.

Oxidation.

Take an appropriate amount of saturated hydrogen sulfide solution in a test tube and drop it in.

Hydrogen peroxide solution (take an appropriate amount of potassium iodide starch solution in a test tube and add hydrogen peroxide solution).

A yellowish precipitate is produced or the solution becomes cloudy (the solution turns blue).

or instability.

Take an appropriate amount of hydrogen peroxide solution in a test tube, heat it, and test it with a wooden strip with sparks (take an appropriate amount of hydrogen peroxide solution in a test tube, heat it, and use a trachea to pass the obtained gas into a test tube filled with saturated hydrogen sulfide solution).

Bubbles are generated, and the wood strips re-ignite (the solution becomes turbid or has a light yellow precipitate).

It is easy to conclude from the information in the title that sodium percarbonate has both the properties of hydrogen peroxide and sodium carbonate, that is, all substances that react with hydrogen peroxide or sodium carbonate can react with sodium peroxide to make it invalid

a. Manganese dioxide is a catalyst for the decomposition of hydrogen peroxide, and when the two meet, they will react and release oxygen to deteriorate sodium percarbonate, so A is wrong;

b. The clarified lime water can metacompose with sodium carbonate to generate white precipitated calcium carbonate, which will also deteriorate the sodium percarbonate, so B is wrong;

c. Hydrochloric acid can metacompose with sodium carbonate to generate gas, which will also deteriorate sodium percarbonate, so C is wrong;

d. Sodium chloride neither reacts with hydrogen peroxide nor with sodium carbonate, so it will not deteriorate sodium percarbonate, so D is right

Therefore, choose D

Pick D! Manganese dioxide can catalyze hydrogen peroxide reactions, copper sulfate can react with carbonate, and hydrochloric acid can also react with carbonate.

Sodium chloride does not react with sodium carbonate and hydrogen peroxide.