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Binary linear equations can be solved. There is basketball x, football y, x+y=35, x=2y-2, solve y=37 3, if the basketball is twice as many as the football, solve y=11.
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With the addition of the two less basketballs, there are 37 in total.
Football has one.
According to common sense, this is impossible.
There must be something wrong with this question.
70% of the time it's probably a play on words.
20% of the time it's possible to make a mistake.
It is possible that you have been pitted.
The possibility is unknown.
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Basketball A Soccer (A-2) 2 pcs.
a+(a-2)/2=35
a=24 (a-2)/2=11
Football 11 pcs.
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Equation: Let there be x footballs and 2x-2 basketballs.
According to the question, x+2x-2=35
3x=37x=37/3
Basketball: 2*37 3-2=68 3 (pcs).
Football: 37 3 (pcs).
It seems that there is a mistake in the data, hope.
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Set up x football, 2x-2 basketball.
x 2x-2 35 went back next
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Two more is right, 11 in football; Is 2 less a brain teaser?
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There's no solution, can't you calculate the whole number?
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Soccer 37 3, this question seems to be a bit problematic.
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Estimation is a description of the problem, there is no integer solution.
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There are 21 basketball and soccer balls in the gymnasium. And basketball is twice as big as football, three. If we take football as a benchmark number.
Then all the balls are three times the +3 of football. That is, triple the number of footballs plus 3 equals 21, then the number of footballs is six. Actually, it's (21-3) 3=6.
So the final answer is that the number of soccer balls is six.
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There are 21 basketball and soccer in total.
Football x, basketball is 2x+3
A total of 3x+3=21
So x=6 is 6 for football and 15 for basketball.
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Let's say the number of soccer balls is x.
It is known that there are 3 more basketballs than footballs, and the number of basketballs available is 2x+3 (pieces).
Now there are 21 basketball and soccer each, and you can get it:
x+2x+3=21
The solution is x=6, so there are 6 footballs.
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There are 21 soccer balls and basketballs in the gymnasium, and basketball is 3 times more than 2 times that of soccer balls, you can list equations, and if there are x soccer balls, then basketball is 2*x+3, x+2*x+3=21, and x=6, that is, 6 footballs and 15 basketballs.
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There are 6 in football. There are 15 in basketball, which is just three times more than in football.
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Let there be x footballs, then there are 21-x basketballs, and from the conditions in the problem, there are 21-x-3=2x, and solving the equation gives x=6, that is, there are 6 footballs.
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Let there be x footballs and 2x+3 basketballs, and the equation can be x+2x+3=21, so there are 6 footballs.
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This problem is solved with an equation of x for football and 2x + 3 for basketball The equation is as follows.
2x+3+x=21
Solution 3x=21-3
x=6A: There are 6 in football.
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Let there be x footballs, and calculate them according to the question column as follows:
x+(2x+3)=21
3x=18x=6
A: There are 6 of them in football.
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Hello. We'll be happy to answer for you.
15 basketballs.
Soccer 6 pcs.
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Summary. Okay, kiss.
There are 20 in football, which is 2 times less than 4 times that of basketball, and how many are there in basketball.
Okay, kiss. There are no equations.
Isn't it 12.
It's 12 on the homework help.
Kiss, it's twelve.
I just did the other one for you.
You write me the way.
Okay dear. Two approaches.
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Summary. Hello, dear, it's a pleasure to serve you, your question has been received, now start answering for you, typing may take a while, wait a moment pro!
There are 20 in football, which is 2 times less than 4 times that of basketball, and how many are there in basketball.
Hello, dear, it's a pleasure to serve you, your question has been received, now start answering for you, typing may take a while, wait a moment pro!
Hello, dear, the answer is as follows: (20+4) 2=12
Hello, dear, the equation is as follows: solve the equation and let the basketball x 2x-4=202x=24x=12
Dear, Xi Zai hopes that I can help you, if you can, help click on the right rent of the lower corner of the like, I wish you a happy life, thank you for all the evils
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Summary. Hello, there are 45 basketball and football, 5 more than 3 times more than basketball, how many are there in football, the specific calculation process is as follows:
There are 45 basketball and soccer in total, and there are 5 more soccer balls than basketball, and there are so many soccer balls.
Hello, there are 45 basketball and football, 5 more than 3 times more than basketball, how many are there in football, the specific calculation process is as follows:
Let's say there are x basketballs.
So soccer has 3x+5
So x+3x+5 454x 45-5=40x 40 4=10, so there are 10 footballs.
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The number of basketball sedan chairs is 4 times that of football, 5 times less.
Number of basketballs = number of soccer balls x 4-5
251 = the number of late football drafts x 4-5
Football yard filial piety x4 = 251 + 5 = 256
Number of footballs = 256 4 = 64
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Summary. Hello, if the football is x basketball, it is 2x x+2x 324 x 108 football 108 basketball 216.
3. There are 324 football and basketball, and the number of basketballs is twice that of football.
Hello, if the football is x basketball, it is 2x x+2x 324 x 108 football 108 basketball 216.
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Analysis: Equation:
Shout Linai 85 + 5) 2
45 (pieces) Answer: There are 45 bad luck in the basket Zheng Chunqiu.
Equation: Solution: Let there be x basketballs.
2x-5=85
2x=85+5
2x=90x=45
A: There are 45 basketballs.
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There are 85 in football, and there are 5 fewer squires than twice as many as in basketball. Then use 85 + 5 = 90, which is twice as much as Lao Chen's basketball, and then use 90 2 = 45, so the basketball is 45 yuan groups.
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